Explore topic-wise InterviewSolutions in Current Affairs.

hit like if you find it useful

Thiry thousand five hundred rupees = 30,500 rupees

25%of 20 is 5 it means it won 5 matches so it lost matches=20-5=1515matches lost

correct answer is 2,28,800

candidate win with margin 32332

2,28,800 is the correct answer

yes all are same one-tenth = 1/10 = 0.1

thank you for the answers

5000 + 800 + 80 + 1 = 5881

root(5)=2.236so root(125)=5root(5)root(500)=10root(5)so 5root(5)-10root(5)/5=5root(5)-2root(5)=3root(5)=3*2.236=6.708

500+5+200+4=709The answer is 709.

1500÷3÷5÷10500÷5÷10100÷10= 10

the your question answer is 10

mode=3median-2meanso 80=3median-220so 3median=300so median=100

The given number is rational because, it is in p/q form where q is not 0, and p and q are both integer

When a die is thrownTotal number of outcomes= 6

Possible outcomes for number greater than 4 = 2

Therefore, probability of getting no. greater than 4= 2/6 = 1/3

(3) is correct option

It is an AP with a = 5 and d = 2.

Tₙ = 205 = a+(n-1)d = 5 +(n-1)*2

200/2 = 100 = n-1, or n = 101.

S₁₀₁ = (101/2)[2*5+ (101–1)*2]

= (101/2)[10+200]

= 101*210/2

= 10605.

Answer: The sum of odd numbers from 5 to 205 is 10605.

The coat of one bottle = 70/5 = 14 rupees

Total bottles = 12*24 = 288 bottles

Cost = 288*14

= 4032 rupees

the answer is so simple my dear friend

weight of each crate =7.25

max weight it can afford =1000

then max crate =1000/7.25

137.93

so 137 can be stored max

1crate=7.25x crates=1000x*7.25=1000x=1000/7.25x=137.93x==138(approx)if u satisfied. give me a like

101 35+x 66-x 3+x 32 34-x3 x 32-x 2

If you find this answer helpful then like it.

106 × 106 - 94 × 94

106² - 94²

(106 - 94) ( 106 + 94)

12 × 200

2400

Area of four walls=4[2(lh+bh)]=4[2(5*3+4*3)] m²=4[2(15+12)] m²=4[2*27] m²=4*54 m²=216 m²

Given : Length of wallpaper = 260 m and breadth = 30 m

So,

Area of wallpaper = 260×30 = 7800 m2

And

Length of the room is 7 m and its breadth is twice its height.

Let Height of room =x , So

Breadth of room = 2x

And surface area of all four walls of room = 2 ( Length×Height + Breadth×Height ) , So

2 ( 7x+ 2x(x) ) = 7800

7x + 2x2= 3900

2x2+ 7x- 3900 = 0

We know quadratic formula :

x =−b±b2−4ac√2ahere a= 2 , b = 7 and c = -3900

So,

x =−7±72−4×2×−3900√2×2=−7±49+31200√4=−7±31249√4So,

x =−7−31249√4and−7+31249√4

But we assume "x " is height of room so that can't be neagtive so we neglect negative term (x =−7−31249√4)and get

x =−7+31249√4=−7+176.774=169.774=42.44

Therefore,

Height of room = 42.44 m

answer is 3m

C #3 is the right answer

with steps pls

is it 24?

total distance = distance travelled during going up + during coming down until water surface + underwater surface = 12+12+!2 = 36

thanks

are bhai ye mujhe ans krna tha

verify the property(a×b)×(c)= a×(b×c) if a =2,b=3,c=4

bhk ankhila chowdary thori der shaant baith na

saharash i wanted Answer quixly she answered

please post it as a separate question.

commutative property of multiplocation

ok didi

Mr Saharsh Pandey feel free to post answers to others question but refrain yourself from posting informal messages on others questions and yours too. We very strictly forbid those comments in the community.

who are you creator of scholr?

i have been using it since 2015

shut uo

shut up guys chill i am a kid pls stop fighting

okay kid as you say

now answer my other question that i posted now

mr sharsh pandey i guess you are an educated person so put some sense in the brain and behave never behave like this in a public forum i will make sure that you will be blocked immediately

mr Aneesh J V feel free to

Volume = 1680m³Volume = LBH1680 = 14×10×H12=H

by BODMAS rule10(-1)-(-2)(-3)/2[-8÷(-4)]=-10-6/2(2)=-10-3(2)=-10-6=-16

The GCD is (x - 3a)

it will be 2*3*a*a= 6a^2thanks

2a×3a=2×3×a×a=6a^2

3a(x+y) - 2b(x+y)Taking, (x+y) common, we can write:(x+y)(3a - 2b)

PLEASE HIT THE LIKE BUTTON

Let the first term be a and common difference be dnth term = a+(n-1)d

Given Third Term + Seventh term = (a+2d)+(a+6d) = 6 ==> a+4d = 3hence, a= 3-4d

Third Term * Seventh term = (a+2d)*(a+6d) = 8(3-4d+2d)*(3-4d+6d) = 8==> (3-2d)*(3+2d) = 8i.e. 9-4d^2 = 8==> d^2 = (9-8)/4 = 0.25==> d = 0.5 or -0.5

Now to check which is correct d...Substitute and find

Case (a): d= 0.5a+4d = 3==> a=3-4d = 3-4(0.5)=13rd term = a+2d= 1+2*0.5 = 27th term = a+6d= 1+6*0.5 = 4Sum = 6 and Product = 8

Case (b): d= -0.5a+4d = 3==> a=3-4d = 3-4(-0.5) = 3+2 = 53rd term = a+2d= 5+2*(-0.5) = 47th term = a+6d= 5+6*(-0.5) = 2Sum = 6 and Product = 8

Since both are matching, we will go with bothvalues

Sum of first 16 terms = n*(2a+(n-1)d)/2 = 16*(2a+15d)/2= 8*(2a+15d)

Case (a): d= 0.5Sum = 8*(2*1+15*0.5)=76

Case (b): d= 0.5Sum = 8*(2*5+15*(-0.5))=20

Given side = 45 cm

Area of square = side² = 45² = 2025 cm²

sir question is find the area of a square whose length is 1 unit

if length is 1 unit then area of sqaure is

side² = 1² = 1 unit²

why you have given area 45