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Cost price of bicycle for Raju = cpSelling price of bicycle for Raju= cp(1+8/100) = cp(27/25)

Cost price of bicycle for Amit= cp(27/25) + 54

Then,cp(27/25) + 54 = 1134cp(27/25) = 1080cp = (1080/27)*25 = 40*25cp = 1000

Raju purchased bicycle for Rs 1000

Percentage of students with cycle = 65 %Let us take the total students as 100 % studentsSo, the percentage of students without cycle = Total students - Students with cycle

So, 100% - 65% = 35%Students without cycle= 35% of the class

Thanks

A union territory is a type of administrative division in the Republic of India. Unlike the states of India, which have their own governments, union territories are federal territories ruled directly by the union government, hence the name "union territory".

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A is the subset of A UBA= 1,2,3B= 4,5,6A€ {1,2,3,4,5,6}

Given that two circles intersect at two points A and B. AD and AC are diameters to the two circles.Join AB.

∠ABD = 90° (Angle in a semicircle)∠ABC = 90° (Angle in a semicircle)

So, ∠ ABD + ∠ ABC = 90° + 90° = 180°

Therefore, DBC is a line. That is B lies on the line segment DC.

180 is correct and best answer 👍 👍👍 👍👍 👍

radii are OA,OB,OC,OD,OQdiameters are AB,CD

5/4 is the answer of this question

-1(35-6x)+2(14-18)+3(3x+15)=-35+7x+2(-4)+9x+45=35+7x-14+9x+45=80-14+26x=66+26x: 26x=-66; x=66/26=

answer is (c) 30°

𝑨𝑵𝑺𝑾𝑬𝑹 𝑰𝑺 64\125

answer of this question is 64/125

The answer is 64/125

(4/5)^3 = 4/5×4/5×4/5 = 64/125

(4×4×4)/(5×5×5)64/125

4×4×4= 645×5×5=125is the right answer

The figure is a square.It has all four sides equal.All four angles equal to 90 degrees.

Given:height= 28 mradius=21 mFormula:l^2=r^2+h^2csa=pi* r* lSolutionslant height=ll^2= 21^+28^2=441+784=1225l=35 mcsa= pi* r*l=3.14*21*352307.9 m sqTherefore canvas required = 2307.9 sq m

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(x-2)/x²+x-6

=(x-2)/(x²+3x-2x-6)

=(x-2)/(x(x+3)-2(x+3))

=(x-2)/(x+3)(x-2)

=1/(x+3)

Lim. 1/x+3x->2

=1/2+3

=1/5

required coordinates of the end points of other diagonal are (3,2) and (-3,2)

To draw chords, one needs two points. So, with one fixed point, 3 chords can be drawn. No take another point, one can draw five chords as the other one is already counted.

This way count, 3+2+1=6 chords

Primary occupation in my district are1. farming2. Crafting3. fishing

We have ABD and ACE are same equilateral triangle , So

AB = BD = DA = AC = CE = EAAnd from given information we get our figure , So,AB = ACThenTriangle ABC is a isosceles triangle , So from base angle theorem We get∠ABC =∠ACBAnd∠ABD =∠ ACE = 60° ( As these angles from equilateral triangles ABD and ACE )And ∠CBD =∠ABC +∠ABD ---------- ( 1 )And ∠BCE =∠ACB +∠ACESo,∠BCE =∠ABC +∠ABD ----------- ( 2 ) ( As we know∠ABC =∠ACB And∠ABD =∠ ACE )From equation 1 and 2 , we get∠CBD =∠ BCE ---------- ( 3 )Now in∆CBD and∆BCEBC=BC( Common side )∠CBD =∠ BCE ( From equation 3 )And BD=CE( Given )Hence∆CBD≅∆BCE ( By SAS rule )So,BE=DC ( By CPCT ) ( Hence proved )

Ray BO is the bisector of angle CBE Therefore,angle CBO=1/2of angle CBE=1/2(180-y)=90-y/2 (1)Similarly,ray OC is the bisector of angle BCD Therefore,angle BCO=1/2 of angle BCD=1/2(180-z)=90-z/2 (2)In triangle BOC,angle BOC+BCO+CBO=180 (3)Substituting (1,2,3) you getAngle BOC+90-z/2+90-y/2=180Angle BOC=z/2+y/2=1/2(y+z)But,x+y+z=180 (angle sum property)y+z=180-xAngle BOC=1/2(180-x)=90-x/2=90-1/2angle BAC

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