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R.H.S =>(x+y) ( x2- xy + y2)=> x3- x2y + xy2+ x2y - xy2+ y3 {On multiplying x3+ y3with(x+y) ( x2 - xy + y2)}=> [x3+ y3] + ( -x2y+ x2y) + (xy2- xy2)=> x3+ y3Since R.H.S = L.H.S,That is x3+ y3= x3+ y3Hence, verified that x3+ y3=(x+y) ( x2- xy + y2)

R.H.S =>(x+y) ( x²- xy + y²)=> x³- x²y + xy²+ x²y - xy²+ y³ {On multiplying x³+ y³with(x+y) ( x² - xy + y²)}=> [x³+ y³] + ( -x²y+ x²y) + (xy²- xy²)=> x³+ y³Since R.H.S = L.H.S,That is x³+ y³= x³+ y³Hence, verified that x³+ y³=(x+y) ( x²- xy + y²)

The gap between conduction band and valence band in small in semiconductor (fig) , therefore electrons from the valance bond can jump to the conduction band on increasing temperature.

Thus they become more conducting as the temperature increases

Let MP = 100.SP after giving 10% commission = 100 - 10% of 100 = 90.Let CP = X.Gain = 20%.Now,X + 20% of X = 90120X /100 = 90X = 75.CP = 75.If 15% commission was given then Sp = 85.Gain = 85 -75 = 10% gain = (10 *100)/75 = 40/3 = 13.33%.

thanku so much

let list price =100xwhole saler sp=80xcp of retailer=80xdiscount =8% on list pricesp=92xprofit=92x-80x=12x%ptofit= profit*100/cp =12x*100/80x = 15% sp=

sp= 15% answer this questions

Let CP=100

MP=120

Discount =10% I.e. 10%of MP =10% of 120 =12

SP = MP - Discount = 108

Gain % = (gain/CP)*100% = 8%

speed =distance/ time speed=437/4.75speed=92 km/hr

Answer:1) 10.26cm sqExplanation

In 60 minutes, the minutes hand covers 360 degrees. or angle of 2π or the full circle.

In one minute it sweeps an angle of 2π / 60 or 1/60th of the area of full circle.

Area of the sector it sweeps in one minute =π r² / 60 =π * 12² / 60 = 7.54 cm²

Hence in 15 minutes7.54*15=113.1cm^2=792/7cm^2option 3

number of students take commerce= 18% of 650= 18/100 × 650= 117

Sin 18°/cos 72° + root(3) [tan10 tan 30 tan 40 tan 50 tan 80]

= Sin18/cos(90-18) + root(3) (cot(90-10). tan 30 cot(90-40). tan50. tan 80)= sin18/sin18 + root(3)(cot 80. tan 30. cot50. tan50. tan 80)= 1 + root(3)(tan30)= 1 + root(3)[1/root(3)]= 1 + 1= 2

8

13*16/12*18*20/10 =624

√3 cosec 20° - sec 20°

= √3/ sin 20° - 1/ cos 20°= √3cos 20° - sin 20°/ sin 20° cos 20°

= 4 [√3/2 cos 20° - 1/2 sin 20° / 2 sin 20° cos 20°]= 4 [ sin 60° cos 20° - cos 60° sin 20°/ sin 40°] = 4 sin (60° - 20°) / sin 40°= 4 sin 40°/ sin 40°= 4

thx

The clock loses 10 minutes per hour

Here, the clock shows only 50 minutes for 60 minutes( in 1 hour)

The watch show the time 12 : 50, after 1 hour

Formula ,To find the angle between hour hand and minutes at H hours M minutes =30H – 11/2 M

The angle between the two hands of the clock after 1 hour

=30 x 12 – 11/2 x 50

= 360° - 11×25

=360º – 275º = 85º

Number of hours between 10 pm on 21st January 2010 and 4 pm on 22nd January 2010= 18 hours

First clock gains 2 min every hour. Then time it will show= 18 hours + 2*18 min= 4:36 pm

Second clock loses 5 min every hour. Then time it will show= 18 hours - 5*18 min= 18 hours - 90 min= (18 - 1.5) hours= 16.5 hours= 2:30 pm

1

2

Factorization

2x³ + 2xy² + 2xz²

2x ( x² + y² + z²)

thanks

(a) is correct answer

use percent formula to find it

(b) is correct answer

Let the cp=100sp=100+40%of 100=140after discount=140-5% of 140=133profit=133-100=33profit%=33/100*10033% profit

Given:C.P= ₹ 550M.P= 20% more than the C.P

M.P= C.P + 20%of C.P

M.P = 550+ (20/100)× 550

M.P = 550 + 110= 660

M.P= ₹ 660

Discount = 20%of M.P

Discount= (20/100)× 660

Discount= 2×66= 132

Discount= ₹132

S.P = M.P - Discount

S.P = 660- 132

S.P = ₹ 528

C.P > S.P

Loss= C.P - S.P

Loss= 550- 528

Loss= ₹ 22

Loss%=( loss/C.P)×100%

Loss% =( 22/550)×100

Loss%= 4%

Hence,the loss is ₹22 & loss% is 4%

C.P= ₹ 550M.P= 20% more than the C.P

M.P= C.P + 20%of C.P

M.P = 550+ (20/100)× 550

M.P = 550 + 110= 660

M.P= ₹ 660

Discount = 20%of M.P

Discount= (20/100)× 660

Discount= 2×66= 132

Discount= ₹132

S.P = M.P - Discount

S.P = 660- 132

S.P = ₹ 528

C.P > S.P

Loss= C.P - S.P

Loss= 550- 528

Loss= ₹ 22

Loss%=( loss/C.P)×100%

Loss% =( 22/550)×100

Loss%= 4%

Hence,the loss is ₹22 & loss% is 4%

5(10x+3y)=9(5x+2y)50x+15y=45x+18y5x-3y=0hencex=3/5yput in second condition13(2x+y)=11(X+2y)26x+13y=11x+22y26x-11x=22y-13y15x=9y5x=3ynow5*3/5y=3y 1=1hence proved

Solution :-

Given - Cost price of goods = Rs. 1100

And, Marked Price = 20 % above the cost price

⇒ Marked Price = 1100 + (1100*20)/100

⇒ M.P. = Rs. 1320

Now, The shopkeeper gives 20 % discount on M.P.

⇒ Discount = (1320*20)/100

⇒ Discount = Rs. 264

Selling Price = Marked Price - Discount

⇒ S,P. = 1320 - 264

S.P. = Rs. 1056

Cost Price > Selling Price = Loss

Loss = Cost Price - Selling Price

⇒ Loss = 1100 - 1056

⇒ Loss = Rs. 44

Loss Percent = (Loss*100)/C.P.

⇒ (44*100)/1100

⇒ 4 %

So, Loss is Rs. 44 and Loss Percent is 4 %

Factorization

18x³y³ - 2xy

2xy ( 9(xy)² - 1)

2xy ( (3xy)² - 1)

2xy ( 3xy - 1) ( 3xy + 1)

Given: SP = RS 810 ; Loss percent = 10%

By using formula ,

C.P = 100/(100-loss %) * SP

= 100/(100-10)*SP = 100/90*810

= Rs 900

Answer : Hence, CP is Rs 900.

it's amazing it's really working.... it's very useful app thank you for answer the question..... thanks a lot

CP = ₹ 24SP = ₹ 30So CP < SP,so there is a profit.SP - CP = 30-24 = 6so profit% = 6/24 × 100 = 25%