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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
1. Find the final selling price when(i) Marked price-Rs 350, discount5%(ii) Marked price-Rs 555, discount 8%(iii) Marked price-Rs 274, discount 7 %(iv) Price Rs 236, sales tax 10%2(v) Price = Rs 450, sales tax = 8% |
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| 2. |
L5SAS Rof the shaded region in Fig. 12.20, if radii of the two concentric circles witho are 7 cm and 14 cm respectively anaZ AOC=40centre |
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| 3. |
Find the actual cost price of a towel of cost80 when sales tax of 8% is charged on it. (2) |
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Answer» anyone more please answer |
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| 4. |
. Rajat purchases a wrist-watch costing R540.The rate of Sales Tax is 8%. Find the totalamount paid by Rajat for the watch. |
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| 5. |
(Finding Sales Tax) The cost of apair of roller skates at a shop was Rs 450. Thesales tax charged was 5%. Find the bill amount. |
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| 6. |
the cost of the fan including sales tax is Rs.918 if the list price of the fan is Rs.850 . Find the rate of sales tax |
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Answer» Sales tax = 918 - 850 = 68 rupees |
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| 7. |
he wants a gain of 12%The marked price of an article is Rs.850 and the retailer gives a discount of 6% on that articleFind the sale price of the article.3.discount of 8%, sales tax at the rate |
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Answer» If the marked price is 850Discount = 6 percentagenow it will be850*6/10051 ruppesnow the selling price850-51799 ruppes |
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| 8. |
. Ranjeeta purchased a set of cosmetic RS150. She paid RS165 for it including salestax. If the rate of sales tax is 10%find the cost price of the set. |
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Answer» not understand |
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| 9. |
53 AL |
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Answer» 4x - (3x+3) = 5 x-3 = 5 x = 8 thank you |
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| 10. |
9. What percent of:(i) 50 kg is 65 kg(ii)9 is4? |
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Answer» hidcgcbhchj iicjhuch. hvhhchh h let percent be xx/100*50=655x/10=655x=650x=650/5x=130percentand, x percent of rupee 9 is 4x/100*9=49x/100=4x=400/9x=44.4percent |
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| 11. |
cos 30+ sin 60Q.27. Show that 1+ cos 60+ sin 602 |
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Answer» cos30+sin60/1+cos60+sin60= cos30=V3/2; sin60=V3/2; cos60=1/2;; V3/2+V3/2/1+1/2+V3/2=v3/2+V3/2/2+1+V3/2=V3/2 × 2/V3=1 V3/2+V3/2=3/2;; 1+1/2+V3/2=2+1+V3/2=/=3+2/V3x 2/3=V3/2 cos30°+sin60°-----------‐------------------------ 1+cos60 + sin30 |
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| 12. |
Q 13: If A- 30, verify that:1 - tanAcos 24 1+ tan2 A |
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Answer» Given,A = 30 LHS: cos 2A= cos 2*30= cos 60 = 1/2 RHS: 1 - tan^2 A/1 + tan^2 A= 1 - tan^2 30/1 + tan^2 30= 1 - (1/sqrt(3))^2 /1 + (1/sqrt(3))^2= (1 - 1/3)/(1 + 1/3)= (2/3)/(4/3)= 2/4= 1/2 LHS = RHS Hence proved |
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| 13. |
r two concentric circles are 13 cm and 8 cm. AB is a diameter ongent to the smaller circle touching it at D and intersecting the larger circle at18. The radii Cproducing. Find the length of AP |
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Answer» To know AD,we need to know AC & CD. To findthem, we need BC and BD first. Given OA=OB = R ,OD= r Let theradii of circles be R & r. R > r.R= 13cm r = 8cm. Finally: AD =√(R²+3 r²) =√(13²+3*8²) = 19 cm |
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| 14. |
.| एक वृक्ष को क्रमशः ५। कमशः 5 सेमी, 11 सेमी लम्बाई की दो जवाएँ AB, CD रोमान्तर हैं। यदि AB और CDके बीच की दूरी 3 सेमी हो, तो वृत्त को त्रिज्या ज्ञात करें । |
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Answer» visit a market palce in your locality and write a note on it about two hunded wrods |
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| 15. |
23. In a trapezium ABCD, if E and F be themid-points of the diagonals AC and BDrespectively. Then, EF-?(a) AB(b) CD22(c) (AB+CD)(d) 5(AB-CD)2 |
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Answer» thanks |
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| 16. |
12. Two chords AB, CD of lengths 5 cm, 11 cm respectively of a circle are parallel. If thedistance between AB and CD is 3 cm, find the radius of the circle |
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| 17. |
4.ABCD is a quadrilateral.Is AB + BC+ CD +DAABCD is quadrilateral. IsAB + BC + CD DA <2 (AC+ BD)?AC+ BD?Al5. |
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| 18. |
Ton4. ABCD is a quadrilateral.Is AB + BC + CD + DA> AC + BD?5. ABCD is quadrilateral. IsAB + BC + CD + DA<2 (AC + BD)? |
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Answer» AB < AC _______(1), BC < AC ___________(2) ABCD IS quadratilateral ABCD DA < BD____________(3), CD< BD____________(4); AB + BC + CD + DA<(AC + AC) + ( BD + BD)= AB+ BC + CD + DA<2(AC + BD) |
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| 19. |
2. Fill in the blanks:1) 1 week days2)14 1521 2228 29comes before Sunday.th of the year isRI SAT7 8 |
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Answer» 1 week has 7 days.Saturday comes before Sunday. |
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| 20. |
Vit cos 30Q. 29. Prove that= = sec 60+tan 60V1 -cos 30 |
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Answer» V1+ Cos30/ V1- Cos30 = V1+ Cos30/V1- Cos30 x 1-Cos30/ 1- Cos30=V(1+Cos30)(1- Cos30)/V1- cos30(1 - Cos30)=V(1-Cos30)^2/V1- Cos30( 1- Cos30)=1- Cos30/Sin30^2=1-V3/2//1/4=2-V3/2 x 4/1=2-V3/2 ×4/1=2-V3/2 1-V3/1/2=(V2+(V3)=sec60 + tan60 |
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| 21. |
92. Today is Monday. What will be the dayafter 64 days?(A) Thursday(B) Wednesday(C) Friday(D) Tuesday |
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Answer» the day after 64 days is Tuesday |
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| 22. |
UPS OW FORD. RAPBUC.WIf day before yesterday was Saturday, then day after tomorrow will beA FridayB. ThursdayC. Wednesday D.TThere is a certain relationship between figures (1) and (2). Establish the sinbetween figures (3) and (4) by selecting a suitable figure from the opreplace the (?) in figure (4).(1)(2)(3)(4)C.SPACE FOR ROUGH WORK |
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Answer» A. Friday is correct answer. C. Wednesday is correct answer Tuesday is the right answer Wednesday is correct answer c.is the correct answer i.e.wednesday tuesday is the right answer c is the right answer c is the right answer c is the right answer. |
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| 23. |
6. A wire of length 44.4 cm is bent in the form of a square and it is also bent in form of a hexagon.Find the measure of the side of the square and the hexagon. |
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Answer» Total length of wire is 44.4cm so for square perimeter is = 4*a therefore a = 44.4/4 = 11.1 cm is the side of square. now for hexagon , 6 sides are their . let s be the side . so 6s = 44.4 s = 44.4/6 = 7.4 cm. |
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| 24. |
18. If Tuesday falls on the fourth of the month,then which day will fall three days after the24th?(a) Monday(b) Tuesday(c) Thursday(d) Friday |
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Answer» Monday will correct think so. the answer of this question is thursday the answer of this is thirsday Thursday Thursday bcoz 25th day would be Tuesday Thursday is a right answer |
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| 25. |
PriyanshuToday, 16:05 |
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Answer» p²-1= (secx +tanx)^2-1 sec^2x +tan^2x +2tanxsecx -1 subs 1= sec^2x -tan^2x sec^2x+tan^2x +2tanxsecx-sec²x +tan^2x 2tan^2x + 2tanx secx=2tanx (secx+tanx) p^2+1= sec^2x+tan^2x +2tanxsecx +sec^2x-tan^2x p^2+1 = 2sec^2x+2tanxsecx =2secx(secx+tanx) (p^2-1)/(p^2+1)= 2tanx /2secx= sinx |
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| 26. |
What universal set(s) would you propose for each of the following(i) The set of right triangles.(i)The set of isosceles triangles. |
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| 27. |
čĄExplain way 7x 1 1x13+13 is Composite |
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Answer» 7*11*13 + 13= 13(7*11 + 1)= 13*78= 13*13*3*2 Since it has more than two factors so its a composite number |
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| 28. |
A car can travel the distance between the home and the office, which are 1.2 km1.8 minutes. How much faster must it travel to do the distance in 1.5 minutes?apar, n |
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Answer» Speed of car in 1.8min traveling =1.2/1.8 = 0.67km per min.speed required if it travels distance in 1.5 min =1.2/1.5 = 0.8km per min. now how faster it should travel to do distance in 1.5 minutes = speed in 1.5min traveling -speed in 1.8min traveling = 0.2km per minute It should travel 0.2km per minute faster |
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| 29. |
29. In the figure, ABC is a right-angled triangle in which90° and AB-4 cm. BD is perpendicular to AC and4BCLABDwhere tan θ-05. Find the length of AC.A caT |
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| 30. |
Explain way 7x I1x13+13 is Composite |
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| 31. |
Q.13 ชุสุ, Eat, fat ฐสุธี 6材Het HH Т ЧТTzT sT, TF fHA5砌5A watch gains 5 seconds per minute and was set right at 6 AM. What would be the timeshown on the watch when the correct time is 2 PM? |
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| 32. |
67. A watch which gains 5 seconds in 3 minutes was set right at 7a.m. In the afternoon of the same daywhen the watch indicated quarter past 4 o'clock, the true time isA. 3pm3:45pm3:30pm4pm |
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Answer» Time from 7 am to 4.15 pm = 9 hrs 15 min =37/4hrs 3 min. 5 sec. of this clock = 3 min. of the correct clock. Now 3min.5sec. is37/720hrs of this clock = 3 min.is1/20 hrs of the correct clock 37/4hrs of clock =(1/20×720/37×37/4)hrs of the correct clock. = 9 hrs of the correct clock. The correct time is 9 hrs after 7 am. i.e., 4 pm. |
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| 33. |
10. write f(x) = x2 + 5x + 4 in completed square form |
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Answer» book answer not coming |
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| 34. |
A Tck 0) the correct answers1. My lather and mother are my(a) daughters b sone2 My parents son is mya) ssterb) brotherLedaughter3 We are our parentsC (e) aunt(b) cousins4. A family of four members is a(a) small âĄ(b) bigfamily(c) large5. Tick () the pictures that show enjoying with family |
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Answer» 1.parents 2. brother 3.children 4.small 1 parents,2 brother, 3 children,4 Small 1. parents2. brother3. children4. small |
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| 35. |
(5) Fill in the blank and rewrite the completed statementis expressed in Oersted. |
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Answer» μ in this case is permeability, the unit of magetizability. In the air, μis usually about 1, except special case, and 1 Gauss ≒ 1 Oersted. Usually,magneticfield strength is defined by the unit of Oe・A/m ( Oersted・Ampere/meter ). And when it is defined by flux density, the units of G (Gauss) or T (Tesla) are used. |
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| 36. |
A soild cube is cuand that of the cuboidt middle as shown in fig. Find the ratio of the total surface area of the given cube |
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| 37. |
A car can travel the distance between the home and the office, which are 1.2 km apart, in1.8 minutes. How much faster must it travel to do the distance in 1.5 minutes? |
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Answer» Speed of car in 1.8min traveling =1.2/1.8 = 0.67km per min.speed required if it travels distance in 1.5 min =1.2/1.5 = 0.8km per min. now how faster it should travel to do distance in 1.5 minutes = speed in 1.5min traveling -speed in 1.8min traveling = 0.2km per minute It should travel 0.2km per minute faster |
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| 38. |
Find the HCF of 437 & 133. |
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Answer» 437 = 19×23 133 = 19×7 HCF = 19 eamiti eamiti |
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| 39. |
437/999 |
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Answer» 2.2860411899 is the answer |
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| 40. |
Âż3 By Mobile marked at Rs. 15000/- is sold for Rs. 14000/-.What is thediscount and discount percentage. loodoo |
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| 41. |
10. Factorise 8x64 |
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Answer» 8x^3 + sqroot(64)y^3= 8x^3 + 8y^3= 8(x^3 + y^3) |
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| 42. |
10. Factorise 8x't V64 |
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| 43. |
Volume of cuboid...cu, unit |
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Answer» Volume of cuboid= length× breadth× height |
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| 44. |
ong the chรถrds are.parallel chords of a circle are 6 cm and 8 cm in length. If they are 7 cm apart, find thercle. |
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| 45. |
A shopkeeper marks his articles 50% above the cost price and gives a discount of 20%. Find higain 96. |
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Answer» hit like if you find it useful |
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| 46. |
A shopkeeper marks his goods 20% more than theirof 10%. Find his gain or loss percent.cost price and allows a discount |
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Answer» Let CP=100 MP=120 Discount =10% I.e. 10%of MP =10% of 120 =12 SP = MP - Discount = 108 Gain % = (gain/CP)*100% = 8% this question ans are 3 % |
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| 47. |
(1)A shopkeeper marks his goods at such a price that would give him a profit of 10% afterallowing a discount of 1 2%. If an article is marked at Rs 2250, find its :(i) selling pricethe cost price of the article if he makes 25% profit on selling it.048.(ii) cost price |
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Answer» Let the selling price and cost price of the goods be x and y respectively.Marked price = Rs 2250Discount = 12% of marked priceThus,selling price = 88% of marked price = 88% of 2250 = 0.88 X 2250 = Rs. 1980Cost price = selling price - profit(1 + 0.10)cost price = selling price1.10 cost price = 1980Cost Price = 1980/1.10 = Rs 1800 |
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| 48. |
alculate speed:1. Distance437 km, Time = 4.75 hours 2. |
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Answer» Formula:Speed=Distance/TimeGiven): Distance=437 km time=4.75 hrsSolution :437 /4.75=92km/hrSpeed=92 km/hr |
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| 49. |
F= 3i +4(Tra-1 (1+1)A force F-3 i +4/newton is applied on a body ofmass 2 kg. Calculate the magnitude anddirection of the acceleration in the body.(Lesson 1) (1+1) |
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| 50. |
docK o F 52,ndäşźăFind the, Frobation of gettingca |
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Answer» Number of red cards = 26Number of queens = 4Number of cards that are neither red or queen = 52-28= 24.Total number of cards = 52Probability of neither red nor queen card = 24/52= 6/13 Please hit the like button if this helped you |
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