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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\left(\frac{\tan 35^{\circ}}{\cot 55^{\circ}}+\frac{\cot 78^{\circ}}{\tan 12^{\circ}}\right) |
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| 2. |
(cos(20^circ) - cot(40^circ)^2)/(-cot(40^circ)^2 %2B sec(50^circ)^2) |
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| 3. |
\left(\frac{7}{5} \times\left(\frac{-3}{12}\right)\right\}+\left\{\frac{7}{5} \times \frac{5}{12}\right. |
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Answer» Clear picture please (7/5)*(-3/12) +(7/5)*(5/12)= 7/5*(5/12-3/12) = 7/5*(2/12)= 7/30. |
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| 4. |
\frac{1}{3}+\frac{4}{5} \text { of } \frac{7}{5} \div 1 \frac{17}{25} |
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Answer» 17/15 of (7/5 * 25/42) = 17*7*25/15*5*42 = 119/126 |
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| 5. |
a hole in the form of a rectangular region is 14 by 12 m how many marble tables 8 cm and 6 CM are needed to cover the floor of the hall? |
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Answer» Area of Reactangle regionAr = length*breadth = 14*12 = 168 m^2 = 1680000 cm^2 Area of tile At = length*breadth = 8*6 = 48 cm^2 Let no. Of tiles required is nThen, n*At = Arn = 1680000/48 = 35000 Number of tiles required = 35000
wrong answer try again pleas |
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| 6. |
7 x^{2}-2 \sqrt{8 x}-6 \text { Divide by } x-\sqrt{2} |
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| 7. |
\begin{array} { l } { \text { Divide: } } \\ { \text { (a) } ( - 9 ) \text { by } ( - 7 ) } \end{array} |
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Answer» -9/-7=1.285 is the answer |
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| 8. |
\left. \begin{array} { l } { \text { Divide } } \\ { \text { a } 574.25 } \\ { 10 } \end{array} \right. |
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Answer» 574.25/1057.425when dividing by 10 we need to shift the decimal to left by one place. |
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| 9. |
Divide \begin{array}{l}{32 \text { by } 4} \\ {82.20 \text { by } 3} \\ {48.32 \text { by } 4} \\ {595.80 \text { by } 9}\end{array} |
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Answer» 1. Rs 32 by 4 =32/4 =Rs 8 4. Rs 82.20 by 3= 82.20/3=Rs 27.40 7. Rs 48.32 by 4 = 48.32/4 =Rs 12.08 10. Rs 595.80 by 9 =595.80/9 = Rs 66.2 |
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| 10. |
\frac{\cos 9^{\circ}+\sin 9^{\circ}}{\cos 9^{\circ}-\sin 9^{\circ}}=\cot 36^{\circ} |
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Answer» Tanq |
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| 11. |
Divide the sum of \frac{2}{3} \text { and }\left(\frac{-5}{6}\right) \text { by the product of }\left(\frac{-3}{4}\right) \text { and }\left(\frac{-1}{3}\right) |
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Answer» 2/3-5/6=(2×2-5)/6=-1/6-3/4 × -1/3=1/4(1/6)/(1/4)=4/6=2/3 |
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| 12. |
Divide 6 x ^ { 2 } - 31 x + 47 \text { by } 2 x - 5 |
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| 13. |
\cot A+\cot \left(60^{\circ}+A\right)+\cot \left(120^{\circ}+A\right)=3 \cot 3 A |
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| 14. |
\frac { \operatorname { sin } 70 ^ { \circ } } { \operatorname { cos } 20 ^ { \circ } } + \frac { \operatorname { cosec } 36 ^ { \circ } } { \operatorname { sec } 54 ^ { \circ } } = \frac { 2 \operatorname { cos } A } { \operatorname { tan } 10 ^ { \circ } \operatorname { tan } } |
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Answer» Sin70°/cos20°+cosec36°/sec54°-2cos43°cosec47°/tan10°tan40°tan50°tan80°=sin70°/cos{(90°×1)-70°}+cosec36°/sec{(90°×1)-36°}-2cos43°cosec{(90°×1)-43°}/tan10°tan40°tan{(90°×1)-40°}tan{(90°×1)-10°}=sin70°/sin70°+cosec36°/cosec36°-2cos43°sec43°/tan10°tan40°cot40°cot10°=1+1-2cos43°(1/cos43°)/tan10°tan40°(1/tan40°)(1/tan10°)=1+1-2×1/1=0 Ans. |
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| 15. |
\frac { \sin ^ { 2 } 15 ^ { \circ } + \sin ^ { 2 } 75 ^ { \circ } } { \cos ^ { 2 } 36 ^ { \circ } + \cos ^ { 2 } 54 ^ { \circ } } = |
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Answer» sin15=sin(90-75)=cos75cos36=cos(90-54)=sin54(cos^2 75+sin^2 75)/(sin^2 54+cos^2 54)=1/1=1 1👍👍👍👍👍👍👍👍👍👍👍 |
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| 16. |
+ \frac { \operatorname { cot } 54 ^ { \circ } } { \operatorname { tan } 36 ^ { \circ } } + \operatorname { sin } 20 ^ { \circ } \operatorname { sec } 70 ^ { \circ } - 2 . CC |
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| 17. |
\frac 31 10 \times \frac 3 10 %2B \frac 7 5 \div 4 = 1 |
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Answer» 31/10 * 3/10 + 7/5 ÷ x = 193/100 + 7/5x = 17/5x = 1 - 93/1007/5x = (100-93)/1007/5x = 7/1005x = 7*100/75x = 100x = 100/5 = 20 Value of x is 20 |
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| 18. |
7. A quadratic polynomial has no real zero, then the graph(A) touches x-axis at any point(0) intersect y-axis in two distinct point D is in one half plane(B) intersect x-axis in two distinciiS in |
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Answer» It will be above the x axis |
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| 19. |
Andy has twice as many marblePandy put together. Andy has 110 marbles which is 115 marbles less than Sandy. How manydoes each of them have?s as Pandy, and Sandy has half as many has Andy andf tho oumher of 25 |
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| 20. |
e How many matches did they play in all?IfChameli had 600 left after spending75% other money how much didshehavein the beginning? |
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Answer» thank you |
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| 21. |
lf-a-s-....-e-theaprovethateach tatio is equal to ½ or |
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Answer» Given question a/b+c = b/c+a = c/a+b Add all the numerator That is (a+b+c) And the denominator as well (b+c+c+a+a +b) which will result in =2a+2b+2c = 2 (a+b+c) Solving it will show like = a + b + c/ b + c + c + a + a + b = a+b+c / 2a + 2b + 2c =(a+b+c) / 2 (a+b+c) =1/2 |
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| 22. |
NX¥\o =20 thea X:=9 |
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Answer» Ans :- x + 10 = 20 x = 20 - 10 x = 10 |
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| 23. |
The product of two numbers is 2160 and their HCF is 12. Find their LCMChe product of two numbers is 2560 and their LCM is 320. Find their H |
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Answer» (i) Product of two numbers = HCF x LCM2160 = 12 x X2160/12=X180=LCM |
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| 24. |
272. A das ohs hsFind te theKilingce ond of 0 tints ofa class Krthe whaheentIrs: a is30 388. 0days10aof35 citin Find the mas |
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| 25. |
( 8 ) \text Divide : \sqrt 250 \div \sqrt 10 |
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Answer» √250 ÷ √10 √ (250/10) √ 25 5 25 should be the answer of this question |
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| 26. |
hatis business ethics? Mention the basic elements of business ethic |
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| 27. |
What is the value of:72 รท [ 38-(30-(31-60 รท 4 x 5)}] |
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Answer» 72/ [38-{30-(31-60/4*5)}]= 72 / [38-{30-(31-15*5)}]= 72 / [ 38 - { 30- (31-75)}]= 72 / [ 38 - { 30 - (-44)}]= 72/ [ 38 - 74]= 72 / (-36)= -2 PLEASE HIT THE LIKE BUTTON |
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| 28. |
Find the sum of all three digit numbers which are multiples of Ie digit numbers which are multiples of 11 |
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Answer» The first three digit no. which is divisible by 11 is 110 So, a(first term)=110 d(common difference)=11 an(last term)=990 an=a+(n-1)d 990=110+(n-1)11 990-110=(n-1)11 880/11=(n-1) 80=n-1 n=81 So the no. of terms are 81Put all values in Sn Sn = n/2[2a+(n-1)d] = 81/2[2*110+(81-1)(11) = 81/2[220+80*11} = 81/2[220+880) = 81/2*1100 = 81*550 = 44550 |
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| 29. |
\frac 36 54 |
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| 30. |
tan(36^circ)/cot(54^circ) |
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| 31. |
|8- हल. 06० लत, १93. g b नल 8 न67 रब तर ७0 [1 100 0.०० मं 0.0 6, 36 ,L 0 9t 54: बीत की पद ता को वात ekहि e ,wuw,uu;gl 47;,' ७०५९, 1 तिकीन Qdami हा o) cipomts s b T be6% पता 0०6०4 का. 15. 2 0.206.. २:०५ |
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Answer» lcm nikalna hai..............................................................! In the given question, we need to find the minimum number of rooms. The number of room will be minimum if each room accommodates maximum number of participants. Since in each room the same number of participants are to be seated and all of them must be of the same subject. Therefore, the number of participants in each room must be the HCF of 336, 240 and 96 HCF = 48 Therefore, in each room 48 participants can be seated.So, number of rooms required = Total number of participants/ 48= 336 + 240 + 96 /48 = 672/48 = 14 find the HCF of 336,140 and 96. the HCF will be the answer hii |
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| 32. |
What is the value of:72รท[38-30-(31-60 รท 4 x 5)}] |
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Answer» 72÷[38 - (30 -( 31-60÷4*5))]= 72÷ [38 - (30 - (31-15*5))]= 72÷ [38 - (30 - (31 - 75))]= 72÷ [38 - (30 - (-44))]= 72÷ [38 - (30+44)]= 72÷ [38 - 74]= 72÷ [-36= - 2 ans] |
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| 33. |
if sec 36" = a, find the value of tan 54°. |
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| 34. |
1After incurring a loss of 335%, a man had18,600 left with him. What was the amountof money he originally had? |
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| 35. |
How many three-digit numbers are divisible by 3? |
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| 36. |
How many three-digit numbers are divisible by 7? |
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| 37. |
3. How many three-digit numbers are divisible by 7? |
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| 38. |
(c)0upwardsboys put their names in a basket.What is the chance that they will draw their own name? |
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Answer» There are total nine possibilities but possibility of getting one's own name is 1henceprobability is 1/9 dusra answer send karo please |
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| 39. |
13. How many three-digit numbers are divisible by 7? |
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| 40. |
steamer in still water and the alstance eto The distance between two stations is 300 km. Two motorcyclists start simultaneously fromthese stations and move towards each other. The speed of one of them is 7 km/h more thanthat of the other. If the distance between them after 2 hours of their start is 34 km, find thespeed of each motorcyclist. Check your solution.numher is five-sixths the first and the third |
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| 41. |
98. A man covered a distance of 12 km in90 min by cycle. How much distance will he coverin 3 hrs, if he rides the cycle at a uniform speed?(A) 36 knm(B) 24 knm(C) 30 kmm(D) 27 km |
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| 42. |
98. A man covered a distance of 12 km in90 min by cycle. How much distance will he coverin 3 hrs, if he rides the cycle at a uniform speed?(A) 36 knm(B) 24 km(C) 30 km(D) 27 km |
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Answer» Speed = Distance/Time= 12/1.5= 8km/hr. Distance covered in 3 hours = 8*3 = 24kms. Please hit the like button if this helped you i hope option A is a Right Answer |
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| 43. |
48+[35-\{30-(31-26 \div 2 \times 4)\}]= |
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Answer» BODMAS48÷[35-{30-(31-13*4)}]48÷[35-{30-(31-52)}]48÷[35-{30-(-21)}]48÷[35-{30+21}]48÷[35-{51}]48÷[35-51]48÷[-16]-3 |
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| 44. |
31,Pind an angle which ia 5" more than four times ita siipplemout.ă |
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| 45. |
31 \frac { 1 } { 6 } \times 31 \frac { 5 } { 6 } |
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| 46. |
\frac { 1 } { 4 } \times \frac { 2 } { 6 } \times \frac { 3 } { 8 } \times \frac { 4 } { 10 } \times \frac { 5 } { 12 } \times \ldots . x \frac { 31 } { 64 } = \frac { 1 } { 2 ^ { x } } |
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Answer» 32 is the correct answer |
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| 47. |
\begin{array}{l}{\text { What is the value of: }} \\ {72 \div[38-\{30-(31-60 \div 4 \times 5)\}]=}\end{array} |
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Answer» 72/36=2 is the correct answer |
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| 48. |
The sum of the draits of a too distsnumber. Ps. The number formed by,reversing the dicit is greater than teoriginal 2,90. Find the onbiral number? |
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Answer» answerajsjshbsbxvxvxbxbxjs |
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| 49. |
Sanju borrowed a sum of money from Simran at 8% interest per annum. After 4 years,Sanju had to give Simran ₹9900 to clear the debt. What was the amount Sanju borrowed originally? |
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Answer» Suppose Sanju had borrowed ₹ x from Simran.Then,Principal (P) = ₹ xRate (r) = 8% p.a.Time (t) = 4 years.Therefore, interest (SI)= Prt/100=₹ x×8×4/100 = ₹ 32x/100Amount =P+SI=₹ (x+32x/100) =₹(132x/100)This is the amount that had to be returned.Therefore,132x/100 =9900=> x =7500Therefore, sum that was borrowed = ₹x = ₹ 7500 [Answer] |
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| 50. |
11. यदि >- हो, तो 4 + A <y v कितनाg2 [होगा? |
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