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Kinetic energy is the energy possessed by an object by virtue of its motion.

K.E=1/2 mV²

Derivation:

Let us consider an object of m which is at rest lying on a table.

Let A force F acts on the object which moves the object through a distance S.

The workdone=FxS

W=FnetXS-------(1)

Let the workdone on the object causes a change in its velocity from u to V and let a be the acceleration.

From Third equation of motion:

V²-u²=2as

s=V²-u²/2a----------(2)

By Newton's Second law:

F=ma------(3)

From equation (1), (2) and (3)

W=ma*(V²-u²/2a)\=(1/2)m(V²-u²)

As we assumed object at rest, u=0

W=(1/2)mV²

we know that the kinetic energy of a body moving with certain velocity is equal to workdone on the object to acquire that velocity from rest.

∴K.E=1/2 mV²

K. E= mass x velocity so much x v = mv

“Thepurpose oflifeis not to be happy. It is to be useful, to be honorable, to be compassionate, to have it make some difference that you have lived and lived well

E+ E(not)= 1probability of an event + probability of event (not) is always 1

We know probablity is always less than or equal to one.

So,Probablity of an event E + Probability of the event not E = 1

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Answer :d) 1-PExplanation Ifyou knowthe probabilityof an eventoccurring, it is easy to computethe probabilitythattheevent doesnot occur.If P(A) isthe probabilityof Event A,then1 -P(A) isthe probabilitythattheevent doesnot occur.

To solve the question, proceed in the following manner-

Let a and b be those two roots of the given equations.

√(p/q) + √(q/p) + √(n/l) can be written as, √p/√q + √q/√p + √n/√l

= (√p²+ √q²)/(√p*√q) + √n/√l

= (p + q)/(√p*√q) + √n/√l ...................(1)

Given thata : b = p : q

Let a = px, b = qx

a + b = -n/l

⇒px + qx = -n/l

⇒(p + q)x = -n/l

⇒p + q = -n/lx .............(2)

Also a*b = n/l

⇒px * qx = n/l

⇒pq*x²= n/l

⇒√pq * x = √(n/l)

⇒√pq = √(n/l)/x ..........(3)

Now from equation 1,

(-n/lx)/(√(n/l)/x) + √(n/l)

= (-n/l)/(√(n/l)) + √(n/l)

= -√(n/l) + √(n/l)

= 0

So,√(p/q) + √(q/p) + √(n/l) = 0

let a=2.4178178.......(1)1000a=2417.8178...(2)(2)-(1)999a=2415.4a=24154/9990

Please post a picture with complete question in it.

where's the answer

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two distanct real roots

D=0, D=b^2-4ac; 0=40^2-4(2k)(25)=1600-200k; 200k=1600; k=1600/200=8;

Since root are equal then,b^2 - 4ac = 0 ------------(1)here b=-40 a=2k c=25

putting these values in eq (1)

(-40)^2 -4(2k)(25) =01600 -200k =01600 = 200k200k = 1600k = (1600)/(200)k = 8

For equal roots , D=0We know , D=b^2-4acor , 0=(-40)^2-4.2k.25or , 0=1600-200kor , 200k=1600or , k=1600/200or , k=8

i) , ii) are polynomialiv) is not polynomial as the power is negitive v) is not polynomial is in fraction

Kx^2-2kx +6=0

Equal roots implies that D=0

This implies that b^2-4ac=0

(-2k)^2 -24k=0

4k^2-24k=0

4k(k-6)=0

4k=0

This implies that k=0

And k-6=0

This implies that k=6

If a quadratic equation has real roots then the discriminant (b² - 4ac ) is a positive value.

The given quadratic equation be, 9x^2 + 7x - 2 = 0

To find discriminant a = 9, b = 7 and c = -2

b² - 4ac = (7)² - (4*9*-2) = 49 + 72 = 121

Therefore discriminantis positive. So, the equation 9x^2 +7x - 2 = 0 has real roots

9x^2 + 7x - 2 = 09x^2 + 9x - 2x - 2 = 09x(x + 1) - 2(x + 1) = 0(9x - 2)(x + 1) = 0x = 2/9, - 1

Hence, roots of equation are 2/9 and - 1

Equations given

kx + y = k^2andx + ky = 1

Since the equations have infinitely many solutionsThuscomparing the coefficients of x and y

k/1 = 1/k = 2k/1

thusk = +1 or -1k = +1/ root2 or -1/ root2

According to question

Equations given

kx + y = k^2andx + ky = 1

Since the equations have infinitely many solutionsThuscomparing the coefficients of x and y

k/1 = 1/k = 2k/1

thusk = +1 or -1k = +1/ root2 or -1/ root2

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adjacent angles of ||gm are supplementary

/_A+/_B=180°x°+(3x+20)°=180°x°+3x°+20°=180°4x°+20°=180°4x°=180°-20°4x°=160°x=160°/4°x=40

Therefore,/_A=x° =40°/_B=(3x+20)° =(3×40+20)° =(120+20)° =140°

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opposite angles are congruent

/_A=/_C=40°/_B=/_D=140°