The roots of 2kx2 - 40x + 25 = 0 are similarthen, k = ?

1.	The roots of 2kx2 - 40x + 25 = 0 are similarthen, k = ?
Answer» D=0, D=b^2-4ac; 0=40^2-4(2k)(25)=1600-200k; 200k=1600; k=1600/200=8; Since root are equal then,b^2 - 4ac = 0 ------------(1)here b=-40 a=2k c=25 putting these values in eq (1) (-40)^2 -4(2k)(25) =01600 -200k =01600 = 200k200k = 1600k = (1600)/(200)k = 8 For equal roots , D=0We know , D=b^2-4acor , 0=(-40)^2-4.2k.25or , 0=1600-200kor , 200k=1600or , k=1600/200or , k=8

Answer»

D=0, D=b^2-4ac; 0=40^2-4(2k)(25)=1600-200k; 200k=1600; k=1600/200=8;

Since root are equal then,b^2 - 4ac = 0 ------------(1)here b=-40 a=2k c=25

putting these values in eq (1)

(-40)^2 -4(2k)(25) =01600 -200k =01600 = 200k200k = 1600k = (1600)/(200)k = 8

For equal roots , D=0We know , D=b^2-4acor , 0=(-40)^2-4.2k.25or , 0=1600-200kor , 200k=1600or , k=1600/200or , k=8

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