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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
2 The adjoining figure shows a model of a solid consisting of acylinder surmounted by a hemisphere at one end. If the modelis drawn to a scale of 1 200, find(i) the total surface area of the solid in Ď m2.(ii) the volume of the solid in Ď lites. |
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Answer» Given, r = h (of the hemisphere) = 3 cm = 3 x 200 cm = 600 cm = 6 m (because scale = 1:200) height of the cylinder = 8 cm = 8 x 200 = 1600 cm = 16 m. And, r of the cylinder = same as the hemisphere = 6 m. Therefore, CSA of hemisphere = 2 π r^2 = 2 x 6 x 6 π m^2 = 72 π m^2And, CSA of cylinder part = 2 x π x r x h = 2 x 6 x 16 x 19 = 192 π m^2. Area of one circular base =π x r^2 = 6 x 6 x 19 = 36 π m^2. Hence, Total surface area = CSA of hemisphere + CSA of cylinder part + area of one circular base = 192 π m^2 + 72 π m^2 + 36 1 m^2 = 300 π m^2 (Answer (i)) Volume of hemisphere = 2/3 * π* r^3 =2/3 * π* 6 * 6 * 6 = 144 π m^3. Volume of cylinder part = π * r * r * h = π * 6*6*16 = 576 π m^3 Therefore, Total volume of the solid = volume of hemisphere + volume of cylinder part = (144 + 576)π m^3 = 720 π m^3. Since, 1 m^3 = 1000 litre So, 720 * 1000 = 720000 π litres (Answer) I hope this help =) |
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| 2. |
In an army camp, there were provisions for 550 men for 28 days. But, 700 men attendedthe camp. How long did the provisions last? |
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| 3. |
oglIISguingtoschoolandbworse.Whatdoyoutmoys going to school is even6The number of men and women who attended a concertwas in the ratio 4:3. If there were a total777 people there, how many men were there?17 |
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| 4. |
26. The adjoining figure shows the graph of y = ax2 + bx + c.ThenA) a O(B) b < 4ac(C) c> 0(D) a and b are of opposite signsol (x0)(x2,0) |
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| 5. |
Take ,unless stated otherwise.1. The adjoining figure shows a cuboidal block ofwood through which a circular cylindrical holeof the biggest size is drilled. Find the volumeof the wood left in the block.70 |
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| 6. |
A vessel had 444 lit of milk, outof it 22, it was used for makingcoffee now how much of milk'is left for making tea |
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Answer» Total milk=4.25 litreUsed For coffee=2.66 litreUsed for tea=4.25-2.66=1.59 litre 17/4 of total no. liters of milk8/3 of milk is used for coffee remaining milk left for tea= 17/4 - 8/3 = 19\12 17/4 of total no. of liters of milk 8/3 of milk is used for coffee remaining milk left for tea= 17/4-8/3 = 19/12 |
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| 7. |
(1) 14(3) 6(2) 10(4) 24107th term t |
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| 8. |
3. The 3rd term of an A.P is 7 and 7th term is 15 then the first term is...... |
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Answer» thank you so much bro given 3rd term of an AP=7 7th term of an AP=15 1st term of an AP=?Now, a+2d=7------------------(1) a+6d=15----------------(2) (1)-(2)=a+2d-(a+6d)=7-15 =a+2d-a-6d=-8 =-4d=-8 =d=2now,putting d=2 in (1) we have, =a+2.2=7 =a+4=7 =a=7/4 |
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| 9. |
Solve the following pair of(i) x+y=14x-y=4 |
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Answer» x+y = 14 .......(1)x-y = 4 .........(2) eliminating y by adding (1) and (2)2x = 18x = 9 x= 9 & y= 5 |
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| 10. |
Solve the following equation for X1.3x 24 |
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Answer» 3x=24x=24÷3x=8 3 is at left side it is in multiple then it go to left side it becomes divider then 24divided 24divided by 3 it is 8 therefore x=8 |
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| 11. |
Write the equation for the sum of three consecutive numbers is equal to 24 |
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Answer» 3 consecutive numbers are suppose a-d , a and a+d a-d+a+a+d = 24 3a = 24 a = 8 so numbers are 6,8 and 10 |
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| 12. |
37. Graphite cannot be use(1) as a lubricant(2) in making pencils(3) in making electrode(4) as a cutting tool |
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Answer» The delocalised electrons are free to move through the structure, so graphitecan conduct electricity. ... The layers ingraphitecan slide over each other because the forces between them are weak. This makesgraphite slippery, so it is useful as a lubricant .Due to its lack of hardness in it it cannot be used as a cutting tool. Hence, option 4 is correct. |
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| 13. |
A farmer had a large field of dimensions 1396.5 m by 272.72 m. Find the area of the field. He left of this area to make a playground for the children of locality. Find the area of the playground. Which value of the farmer is reflected in this act? |
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| 14. |
Has the rational number (447/2^2.5^7.7^2) a terminatingor a non-terminating decimal expansion? |
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Answer» thanks |
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| 15. |
Ch 6 : Triangleste/ery Short Answer Type Questions(1 mark each)1. In the adjoining figure, ABCD is a quadrilateral with BA parallel to CD. AC and BDmeet at X, where CX= 8 cm and XA = 10 cm.If BD = 27 cm, then find the length of BX.are10kys |
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| 16. |
x2Solve:5 + x²for positive value of x. |
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Answer» x^2 -9/5 + x^2 = -5/99x^2 - 81 = -25 - 5x^29x^2 +5x^2 = -25 + 81 14x^2 =56 x^2 = 56/14 x^2 = 4 x = √4 x = 2 2 is the right answer. |
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| 17. |
x² + 1/x²= 7 , find the value of x³ + 1/x³, taking only the positive value of x+1/x |
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| 18. |
Find the least positive value of n, if=1. |
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Answer» find the least positive value of n .,if (1+1_1-i)=1. |
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| 19. |
24. What positive value of x makesfollowing pair of determinants equal?2x31 1163 |
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Answer» First Determinant = 2x^2 - 15.Second Determinant = 32 - 15.FIrst Determinant = Second Determinant.=> 2x^2 - 15 = 32 - 15=> 2x^2 = 32=> x^2 = 16=> x = 4. PLEASE HIT THE LIKE BUTTON |
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| 20. |
1031pansionof 2x2-following expansions:922, 7th term23 |
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| 21. |
-.The positive value of x in the equation24 24=l is :18 - x 18+ x |
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Answer» hfifr Yosttu ut rodeo takleef is the only one of the movie gam movies to make new movies and cleanliness in a great way for mother to |
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| 22. |
it m-ti,--121 and rn n=20, then positive value of (mn) will be |
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Answer» thank u |
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| 23. |
Rs. 6250 at the rate of 8% for 2 years |
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| 24. |
Find the compound interest of Rs. 6250 for1 yrs. at 16% per annum. Compounded2half yearly. |
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Answer» Amount=P[1+(R/100)]n=6250[1+(16/100)]2=Rs.8410C.I=Amount-P=8410-6250=Rs.2160 |
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| 25. |
wwithout beesformingWhich of the followingIf kossible also Dlong diuision determineare terminating decimal2B8406250 |
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Answer» 12*70= 840 इस थे correct answer 840 is the correct answer |
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| 26. |
20 wristwatches were sold for 756,250. Total profit was? 6250. Whatwas profit per cent?(1) 25 % (2) 20% (3) 12.5% (4) 10% |
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Answer» SP = 56250 PROFIT = 6250 CP = 56250 - 6250 = 50000 PROFIT PERCENTAGE = 6250/50000*100 = 12.5% |
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| 27. |
0, ₹6250 का 5% वार्षिक की दर से 4 वर्ष कासाधारण ब्याज क्या होगा?(1) ¥1350 (2) T 1250. (3) T 1450 (4) इनमें से कोई नहीं« Ot |
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Answer» I= PRT/100= (6250*5*4)/100= Rs. 1250 |
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| 28. |
. Finu he2. Find the compound interest on? 6250 at 16% pa, for 3 years, compounded annually.lean of 80 0oo from the bank. If t |
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| 29. |
QUADRILATERALS151In a parallelogram ABCD, E and F are themid-points of sides AB and CD respectively(see Fig. 8.31). Show that the line segments AFand EC trisect the diagonal BD.5. |
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| 30. |
1.Construct a triangle ABC in which BC = 7cm, <B = 75° and AB + AC = 1 3 cm. |
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| 31. |
The difference in C.l. and S.I. for 2 years on a sum of money israte percent.250. If the sum is6250, then find the12. |
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Answer» If you like the solution, Please give it a 👍 |
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| 32. |
10. In the given figure, m | n andp lg. If 1 75°, thernprove that 22of right angle.2AB |
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| 33. |
1. Construct a triangle ABC in which BC- 7em, 4B- 75° and AB+AC 13cm. |
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| 34. |
93122 |
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| 35. |
: Finthe slope of a line parallel to the following1.lines:3122 |
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| 36. |
6. A, B and Care the points on a circle. The tangent at Cmeets BA produced at T. Given that ZATC-36 andLACT 48°, calculate the angle subtended by AB at0ICSE36the centre of the circle. |
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Answer» 1 2 thanx😊 |
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| 37. |
nd Care three points on a circletangent at C meets BA producedGiven that Z ATC 36° andfind the angle subtended by AB atcentre of the circle.the48°36(A) 90°(C) 108°(B) 96(D) 120°drawn to a cirde |
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| 38. |
22 The given figure shows a pentagon ABCDE. EG,drawn parallel to DA, meets BA produced at G,andCF, drawn parallel to DB, meets AB produced at F.Show that ar(pentagon ABCDE)- ar(ADGF).EG A B F |
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| 39. |
In AABC, D and E are points on sides AB and AC respectively, such that DE | BC.If ADBD, AE4.5 cm, find AC. |
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Answer» In∆ABC,wehaveDE∥BC. Since,DE∥BC, thenAD/BD=AE/EC[Basicproportionalitytheorem]......(1) Now,AD=13BD(given) ⇒ADBD=13 now,from(1)weget 13=4.5EC[∵AE=4.5cm] ⇒EC=13.5cm Now,AC=AE+EC=4.5+13.5=18cm Like my answer if you find it useful! |
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| 40. |
6 In AABC, D and E are points on the sides AB and ACrespectively such thAD 2B and EC -4cm, then find AE. |
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| 41. |
In the figure (ii) given below, A, B and C are three points on a cirdeThe tangent at C meets BA produced at T. Given that LATC=36" andLACT = 48", calculate the angle subtended by AB at the centre of the circle. |
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Answer» where is the figure (ii) What happen? No answer |
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| 42. |
19. In the given figure, the side AC of aAABC is produced to E such thatCE AC. If D is the mid-point of BCand ED produced meets AB at F and CP,DQ are drawn parallel to BA. Prove thatF2BQuadrilaterals |
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Answer» Given,ABC is a triangle.D is midpoint of BC and DQ.They're drawn parallel to BA. Then, Q is midpoint of AC.∴AQ = DC ∴ FA parallel to DQ||PC.AQC, is a transversal so, AQ = QC and FDP also a transveral on them. ∴FD = DP .......(1) [intercept theorem]EC = 1/2 AC = QC Now, triangle EQD, here C is midpoint of EQ and CP which is parallel to DQ.And, P is midpoint of DE.DP = PE..........(2) Therefore, From (1) and (2)FD = DP = PE∴ FD = 1/3 FE |
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| 43. |
prove that LM = LN19. In the given figure, the side AC of aAABC is produced to E such thatCEAC. If D is the mid-point of BC Fand ED produced meets AB at F and CP,DQ are drawn parallel to BA. Prove that B2FDFE. |
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| 44. |
To fill a larger bottle, 3glasses of water are needed2and to fill a smaller bottle, 27 of glasses are needed.What is the ratio of the volumes of the large andsmall bottles? |
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Answer» 3 1/2 =5/2glasses2 1/4 =9/4 glasseshenceratio5/2:9/410/9 |
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| 45. |
Q6. If (3x - 58) and (x +38) are supplementary angles. Find x. (Ans. = 50°) |
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Answer» SUPPLEMENTARY ANGLE=180 DEGREE Therefore, 3x-58+x+38=180 4x-58+38=1804x-20=1804x=180+20 4x=200x=200/4 x=50 |
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| 46. |
Example 1 :If a line intersects sides AB and ACofa AABC at D and E respectivelyAD AEAB ACand is parallel to BC, prove that(see Fig. 6.13) |
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| 47. |
06. If (3x - 58) and (x +38) are supplementary angles. Find X. (Ans. -50%) |
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Answer» 3x-58+x+38= 1804x - 20 = 1804x = 180+204x = 200x = 50 |
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| 48. |
Solve the following pair of equationsby eliminating method.2x y-50 3x-2y-4 02. |
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| 49. |
llowing quadratic equations. If the real roots e(ii) 3x2-43x+4 0lowing quadratic equations, so that they ha |
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| 50. |
Find the roots of the following equations: |
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