2 The adjoining figure shows a model of a solid consisting of acylinder surmounted by a hemisphere at one end. If the modelis drawn to a scale of 1 200, find(i) the total surface area of the solid in Ď m2.(ii) the volume of the solid in Ď lites.

2 The adjoining figure shows a model of a solid consisting of acylinde

1.	2 The adjoining figure shows a model of a solid consisting of acylinder surmounted by a hemisphere at one end. If the modelis drawn to a scale of 1 200, find(i) the total surface area of the solid in Ď m2.(ii) the volume of the solid in Ď lites.
Answer» Given, r = h (of the hemisphere) = 3 cm = 3 x 200 cm = 600 cm = 6 m (because scale = 1:200) height of the cylinder = 8 cm = 8 x 200 = 1600 cm = 16 m. And, r of the cylinder = same as the hemisphere = 6 m. Therefore, CSA of hemisphere = 2 π r^2 = 2 x 6 x 6 π m^2 = 72 π m^2And, CSA of cylinder part = 2 x π x r x h = 2 x 6 x 16 x 19 = 192 π m^2. Area of one circular base =π x r^2 = 6 x 6 x 19 = 36 π m^2. Hence, Total surface area = CSA of hemisphere + CSA of cylinder part + area of one circular base = 192 π m^2 + 72 π m^2 + 36 1 m^2 = 300 π m^2 (Answer (i)) Volume of hemisphere = 2/3 * π* r^3 =2/3 * π* 6 * 6 * 6 = 144 π m^3. Volume of cylinder part = π * r * r * h = π * 6616 = 576 π m^3 Therefore, Total volume of the solid = volume of hemisphere + volume of cylinder part = (144 + 576)π m^3 = 720 π m^3. Since, 1 m^3 = 1000 litre So, 720 * 1000 = 720000 π litres (Answer) I hope this help =)