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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the area of the shaded regioncmin the figure?(1) 18 cm2(2) 8 cm2(4) 9 cm2.(3) 12 cm2 |
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| 2. |
O is any point inside a rectangle ABCD.Prove that OB, OD. = OA2+OC2.DEDUCTION In the given figure, O is a ppoint inside a rectangle ABCD such thatMPLE 19[CBSE 2006C1OB = 6 cm, OD = 8 cm and OA = 5 cm,find the length of°C、 [CBSE 2009C)5 cm6UTION GIVEN O is a point inside a rectangle A |
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| 3. |
3 See the figureandfÄąndtheratio ofances thatNumber of triangles to the number of circles(a)(b) Number of squares to all the figures inside the(c) Number of circles to all the figures inside theinside the rectangle.rectangle.rectangle. |
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| 4. |
3. If the length of a diagonal of a cube is 8/3 cm, then its surface area is(a) 512 cm2(b) 384 cm2(c) 192 cm2(d) 768 cm2 |
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| 5. |
47. In the figure below QR is thdiameter of the semi-circle.PQ 8 cm and PR6 cm.Find the area of the shaded partTake 3.14.A.24 cm2B. 78.5 cm2C. 39.25 cm2D. 15.25 cm2 |
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| 6. |
क9. चित्र में 4728 तथा 402 समरूप हैं। यदि 2९" > 8 सेमी, हू « 4 सेमी, हज > 6-5 सेसी, 4 न 2-8 सेसं, s |C4 77 40 =1 5= 78 कौंक्ए। |
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| 7. |
3 See the figure and find the ratio of(a)(b)ic)Number of triangles to the number of circlesinside the re tangle.Number of squares to all the figures inside therectangleNomber of cireles to all the figures inside the Lrectangle |
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| 8. |
U Students liking cricket to totalnumber of students.3. See the figure and find the ratio of(a) Number of triangles to the number of circlesinside the rectangle.rectangle.(b) Number of squares to all the figures inside the(c) Number of circles to all the figures inside therectangle.Distances travelled by Hamid and Akhtar in an hourratio of speed of Hamid to the speed of Akhtar.Fill in the following blanks:15 1 10 m30 (Are these equivalent rati18 6Find the ratio of the following:(a) 81 to 108 (b) 98 to 63(C) 33 km to 121 km (d) 30 minutes toFind the ratio of the following:Ac |
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Answer» i) 81:106/ 3=27 : 36/3=9:6/3=3:2; ii)98:63=14;9;:3 iii) 33:121/11=3:11 15/18=5/6=10/12=25/30 |
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| 9. |
2b24165. FactorisethSolution. () 4x2 9y 1622 12ry -242(2x)-(3y)2 + (-402 + 2Rtre16rz |
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Answer» 4x^2+9y^2+16z^2+12xy-24yz-16xz=(2x)^2+(3y)^2+(-4z)^2+2(2x)(3y)+2(3y)(-4z)+2(-4z)(2x)=(2x+3y-4z)^2 |
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| 10. |
Example 14: O is any point inside arectangle ABCD (see Fig. 6.52). Prove that |
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Answer» Let ABCD be the given rectangle with point O within it. Join OA, OB, OC, OD. Through O draw EOF||AB.Then ABFE is a rectangle.In right ∆OEA and ∆OFC,OA² = OE² + AE² and OC²= OF²+CF²OA²+OC²=(OE²+AE²) +(OF²+CF²)OA²+OC²=OE²+OF²+AE²+CF²………….(1)In right ∆OFB and ∆ODE,OB² = OF² + FB² and OD²= OE²+DE²OB²+OD²=(OF²+FB²) +(OE²+DE²)OB²+OD²=OE²+OF²+DE²+BF²OB²+OD²=OE²+OF²+CF²+AE²…………..(2)[DE=CF & AE=BF]From eq i & eq ii,OA² + OC² = OB² + OD² HOPE THIS WILL HELP YOU |
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| 11. |
Example (14: O is any point inside arectangle ABCD (see Fig. 6.52). Prove that |
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Answer» Ans :- We draw PQ ║AB ║CD as shown in figure, ABCD is a rectangle , it means ABPQ and PQDC are also rectangle For , ABPQ , AP = BQ [opposite sides are equal ] For, PQDC PD = QC [ opposite sides are equal ] now, for ∆OPD,OD² = OP² + PD² ------(1) For, ∆OQB, OB² = OQ² + BQ² --------(2) add equations (1) and (2), OB² + OD² = (OP² + PD²)+ (OQ² + BQ²) = (OP² + CQ²) + (OQ² + AP²) as you can see figure, ∆OPA and ∆OQC are also right angled triangles For, ∆OCQ ⇒OQ² + CQ² = OC²For,∆OPA ⇒OP² + AP² = OA² , put it above Now , OB² + OD² = OC² + OA² thanks |
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| 12. |
Date2.le is G& m. find itsanea |
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Answer» Circumference of circle = 96.8 m Circumference of circle = 2πr96.8 = 2*22/7*rr = 96.8*7/2*22r = 15.4 m Area of circle = πr²= 22/7*15.4*15.4= 745.36 m² Ans. |
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| 13. |
oF one dagosanea of the uads laanal |
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| 14. |
2) The volume of hemisphere is 2425 cm2 Find its curved surtace anea |
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| 15. |
A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose sides are in the ration of 6:5 The smaller side if the rectangle is |
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| 16. |
O is any point inside arectangle ABCD (see Fig. 6.52). Prove thatOB²+OD²=OA²+OC² |
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| 17. |
Question 3a. In the given figure find the area of the shaded portion inside the rectangle Take T 314 |
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Answer» Area of square = side² = 6² = 36 cm² Area of circle = pi × r² = 3.14 × 3² cm² = 28.26 cm² So area of shaded part is = Area of square - Area of circle = 36 - 28.26 = 7.74 cm² |
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| 18. |
wo meal I 3, 4, 7, p and 10 is 8, find the va15. Find the mean of first six multiples of 5. |
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| 19. |
SHUSTE||2||h hub |
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Answer» 2 divided by 4answer is 2 2 is the right answer 2 divided by 4 answer is 2 answer of this question is 2 2 is the correct answer of the given question 2 is the best answer |
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| 20. |
i Find all the points of local maxima and minima and the correspondingmaximum and minimum valucs of the following function, if anyf(x) = x3-6x2 + 9x + 15IcBSE 1981; PSB 88 NCERTi l) |
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| 21. |
US The cost of 2 pencils and 3 erasers isăŚ9 and the cost of 4 pencils and 6 erasers is? 18. Find thecost of each pencil and each eraser. |
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| 22. |
(iii) abcx㥠xb2CxC4. The area of a triangle isbase x altitude. The base of the triangle is 5x cm whereas the altitude is2of the base. Find the area of the triangle.25.Rohit has 12pg apples. If the cost of each apple is 3p'Ä , find the total cost of apples. |
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| 23. |
the value ofcos 15° +sin 15cos 15 -sin 15d the minimum value o |
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| 24. |
Thirty erasers cost 45. Find the price of45 erasers. |
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Answer» ३०erasers cost 45rupeesone will cost =45/30= 9/6= 1.5 rupeeso 45 erasers will cost 45*1.5= 67.5 rupees |
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| 25. |
yOne crore ninety lakthirty oneFind the products in each of the fol1. 719 * 1573. 4258 3695 8731 X 4027. If the cost of one television is8. An air conditioner costs 18If a daily newspaper has 72. |
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Answer» 1st ka 719*157=112883 |
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| 26. |
Who am 1?T hove 6 flat and equal surfaces.Iamahave6 flat surfaces in which opposite surfaces are equal. I amaopposite surfaces are equal. I am ahave one curved surface and 2 flot and equal surfaces. I am a .ove one curved surface and one flat surface. I am a.. |
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Answer» cube cuboid cone hemisphere |
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| 27. |
Who am 1?I have 6 flat and equal surfaces. I am .Ihave 6 fat surfaces in which opposite surfaces are equal. I amd.have one curved surface and 2 flat and equal surfaces. I am aave one curved surface and one flat surface. I am a.. |
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Answer» cube cuboid cone hemisphere |
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| 28. |
There are 2 socks in a pair.How many socks willthere in 3 pairs? |
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Answer» 1 pair = 2 socks.3 pairs = 2*3 = 6 socks. |
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| 29. |
91. A bag contains 5 brown and 4 whitesocks. Aman pulls out two socks. Theprobability that they are of the samecolour is : |
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| 30. |
If you have a collection of 6 pairs of white socks and 3 pairs of black socks. What is the Prohabiliavow anea 0that a pair you pick without looking is (i) white (i) black? |
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| 31. |
73. A dozen pair of socks quoted at Rs. 80 areavailable at a discount of 10%. How many pair ofsocks can be bought for Rs. 24?(A) 4(B) 5(C) 3(D) 6 |
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Answer» Dozen pair of socks after discount= ₹80-(10/100)*80=₹80-8=72 ₹72 can be used to buy 12 pairs ₹24 can be used to buy 4 pairs |
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| 32. |
The probability of selecting a rotten apple randomly from a heap of900 apples is 0-18. What is the number of rotten apples in the heap ? |
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Answer» Total no. of apples=900let the no. of rotten apples be=xprobability of selecting a rotten apple=no. of rotten apples/ total apples0.18=x/900x=900*0.18x=162therefore the total no. of rotten apples= 162 answer |
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| 33. |
The probability of selesting a rotten apple randomly from a heap of900 apples is 0-18. What is the number of rotten apples in the heap ? |
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| 34. |
1. The probability of selecting a rotten apple randomly from a heap of 900 apples is 0.18 What is thsenumber of rotten apples in the heap? |
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Answer» Total no. of apples=900let the no. of rotten apples be=xprobability of selecting a rotten apple=no. of rotten apples/ total apples0.18=x/900x=900*0.18x=162therefore the total no. of rotten apples= 162 answer |
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| 35. |
The probability of selecting a rotten apple randomly from a heap of 900 apples is 0.18. What is thenumber of rotten apples in the heap?1. |
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Answer» Total no. of apples=900let the no. of rotten apples be=xprobability of selecting a rotten apple=no. of rotten apples/ total apples0.18=x/900x=900*0.18x=162therefore the total no. of rotten apples= 162 Like my answer if you find it useful! |
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| 36. |
The probability of selecting a rotten apple randomly from a heap of900 apples is 0-18. What is the number of rotten apples in the heap? |
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| 37. |
Q 1. The probebility ofin the helyelecding a rottern apple randomly from s heap of 900 apples is 0. 18. What is the number of rottenrottern |
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Answer» Total no. of apples=900let the no. of rotten apples be=xprobability of selecting a rotten apple=no. of rotten apples/ total apples0.18=x/900x=900*0.18x=162therefore the total no. of rotten apples= 162 Like my answer if you find it useful! |
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| 38. |
36, 53% of mangoes fell on the ground from a few mango trees due to a storm. If 159 mangoesremained on the trees, what was the total number of mangoes on thes trees? |
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Answer» Let total number of mangoes on tree are n As 53% mangoes fell on the ground then number of ma goes left on tree= 100 - 53 = 47% Given,(47/100)n = 159n = 159*100/47n = 338 Total number of mangoes = 338 but the answer on the book give 300....please review |
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| 39. |
11, In a basket having 144 apples, of the total appleare rotten. How many of them are in good condition |
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Answer» 120 Apple no. of rotten apples=144/6=24no.of good apples= 144-24=120 |
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| 40. |
1.18 erasers cost72. What is the cost of 1 eraser? |
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Answer» 18 erasers cost 72 rupeeshence cost of 1 eraser will be 72/18=4rupees |
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| 41. |
The number of constant functions possiblefrom R to B where B 2.4,6,8...24 are |
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Answer» for constant function we have to fix the function to values belongs in given domain B so numbers of terms in B is 12 so number of function is 12. |
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| 42. |
sguare park is 60 m and the length of IRthe rectangular parkA wire is in the shape of a rectangle Its length is 40 cm and bri2asame wire is rehent in the shape of a square, what will be the mcasedAlso find which shape encloses more area?le is 130 cm. If the breadth ol te |
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| 43. |
I. A drinking gless is in the shape ocone of heigh 14 m The diuneses ocircular endsare aldm and Oom. Fini Ä°hecipacityofthe glass2. The slant height of a trustun ol s cone iscm s |
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| 44. |
दि ७: आजाद हल ol o l<2M:EE Tl )12=Q_ it लेट कर qfl:flfl i,R |
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| 45. |
1. Find each of the following ratios in the simplest form:(1) 24 to 56(iv) 1.8 kg to 6 kg(ii) 84 paise to 3(v) 48 minutes to I hour |
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| 46. |
ind the value ol the Follouingn. 1(-1 ) + COSㅢじ2 |
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| 47. |
the functicFosc what Value olis.. Continuous-op-x乂)二SinxI/ |
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| 48. |
the probability of selection a rotten apple randomly from a heap of 900:is 0.18,what is the number of rotten apples in the heap? |
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Answer» Total no. of apples=900let the no. of rotten apples be=xprobability of selecting a rotten apple=no. of rotten apples/ total apples0.18=x/900x=900*0.18x=162therefore the total no. of rotten apples= 162 answer |
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| 49. |
09९06. Q/ ने Plmassfo 80 Fodius YA uy if Loजीत (89mes pording oL 15५1 (00 |
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Answer» wrong h |
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| 50. |
The probability of selecting a rotten apple randomly from a heap of900 apples is 0.18. What is the number of rotten apples in the heap? |
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