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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
. Prove that a median of an equilateral triangleis perpendicular to the corresponding side.Hint: Let ABC be the equilateral triangle.Take BC=2k and middle point of BC as theorigin, BC as x-axis and the lineperpendicular to BC as y-axis. |
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| 2. |
रीक्षा • न्यू मॉडल प्रैक्टिस सेट-21 =| 53. 10 आदमी तथा 8 औरतें मिलकर एक कार्य को 24 दिनों में 5सकते हैं। 12 आदमी तथा 10 औरतें मिलकर उस काम को लगाकितने दिनों में करेंगे?(A) 24(B) 20(C) 12(D) 16 |
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Answer» 20 day lagta hai is the answer |
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| 3. |
(c)Find a from the following equation using properties of proportion |
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| 4. |
Q17.Using properties of determinants, prove thatx +4 2x 2x |
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| 5. |
The sides of a triangle are in the form of consecutive even integers. If its perimeter is 48cm, fmeasure of each side |
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Answer» Given : The sides of a triangle are in the form of consecutive even integer. Let the sides be x, x + 1, x + 2. Perimeter of the triangle = 48 cm To Find : The measure of each sides. Solution : Perimeter of a triangle = Sum of all the sides 48 = x + x + 1 + x + 2 3x + 3 = 48 3x = 48 - 3 3x = 45 x = 15 Sides of the triangle are 15, 16 and 17. |
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| 6. |
Sldes of a triangle are in the form of consecutive even integers. If its perimeter is 48cm, findsmeasure of each side.find t |
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Answer» Answer: sides are 14, 16 and 18 Explanation:let first side be x so next sides will be x+2 and x+4Perimeter= sum of all sidesequation will be x+x+2+x+4=48 3x=42 x=14 sides will be 14, 16 and 18 please like my answer if you find it useful |
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| 7. |
2 %2B 2*10 %2B (50*100)/10 |
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Answer» 2+2×10+50×100/10By BODMAS RULE2+2×10+50×102+20+500522 522 is the correct answer of the given question 522 is the right answer for this question 2+2×10+50×102+20+500522 522 is right answer for your question |
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| 8. |
ve the following equation using properties of real5=3x + 4 |
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Answer» 3x+4=-5. 3x=-9x=-3 |
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| 9. |
16. Using properties of determinants prove that:1 +a1111 ab( |
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| 10. |
-log(4, 10)/2 %2B log(8, 10) %2B 2*log(5, 10) |
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| 11. |
15/(-4*sqrt(5) - sqrt(5) %2B 2*sqrt(10) %2B sqrt(10) %2B 2*sqrt(5)) |
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| 12. |
(v)[(2x3 + sec? x+31x) dx JT AT: |
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| 13. |
-2*log(5, 10) %2B log(9, 10)/2 %2B 2 |
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| 14. |
; NâP 'jt,\f\g) Sâ |
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Answer» Please hit the like button if this helped you. |
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| 15. |
( 1. Fİd the value of/) and q, for which3 cosxg(1-sin x)π_2xis continuous at x2. |
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| 16. |
9. Find the product of three consecutive evenintegers, if one of them is 2mHint Let consecutive even integers be 2m,2m + 2,2m +4] |
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| 17. |
i-i5324 |
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| 18. |
Solve 5^{(x+1)}+5^{(2-x)}=53+1 |
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| 19. |
(c) Find the critical points of f(x) x^3- 5x^2- 3x |
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Answer» yahi insurance Tarak and sameera raha tha |
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| 20. |
2If 1, is the mid- point of the line segment joining the points (2, 0) and 0, athen show that the line 5x+ 3y+ 2-0 passes through the point (-1, 3p).3 |
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Answer» let ( x1 , y1 ) = A( 2 , 0 ) , ( x2 , y2 ) = B ( 0 , 2/9 ) ; mid point of joining of A and B = ( x1+ x2 /2 , y1 + y2 /2 ) ( 1 , p/ 3 ) = ( 0 + 2 /2 , 0 + 2/9 / 2 ) = ( 1 , 1/9 ) p/3 = 1/9 [∵ If ( a , b ) = ( c , d ) then a = c and b = d ] p = 1/3 --- ( 1 ) according to the problem given , put ( -1 , 3p ) in the equation 5x + 3y + 2 =0 5 ( -1 ) + 3× ( 3p ) + 2 = 0 -5 + 3× 3 ( 1/3 ) + 2 =0 [ from ( 1 ) ] -5 + 3 + 2 =0 0 = 0 [ true ] Therefore , 5x + 3y + 2 =0 line passes through the point ( -1 , 3p ) . Like my answer if you find it useful! |
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| 21. |
and their pooduct is so4 find the ternsSume |
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Answer» let the terms be a,a+d,a+2da+a+d+a+2d= 273a+3d=27/3a+d=9a(a+d)(a+2d)=504a+d =9a*9*(9+d)=504a= 9-d(9-d)(9+d)*9=504(9+d)(9-d)=504/99^2-d^2=56d^2=81-56d^2=25d=+/-5a+d =9when d = 5a=4the numbers are 4,9,15The same when you take d=-5 |
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| 22. |
兀f(x) = sin' x cos? x | p, q > 0; 0 < x <_ | has2point of maxima at(A) x = tan-1111의(B) x = tan-1(C) no such point exist(D) of these |
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| 23. |
(2m - 5) (3a - 2b) - (2m - 5) (2b - 3ा) |
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Answer» thanks br brother |
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| 24. |
Q. 6. Examine, if sin x| is a continuous function.INCERT |
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Answer» Letg(x)=sinx,,h(x)=|x| (goh)(x)=g(h(x)) =g(|x|) =sin|x| =f(x) g(x) is continuous |
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| 25. |
2m x3-2m22m+4m+1 |
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Answer» tq |
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| 26. |
\left. \begin{array} { l } { \pi ^ { 2 } h } \\ { \frac { 22 } { 7 } \times ( \frac { 7 } { 2 } ) ^ { 2 } \times 10 } \end{array} \right. |
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Answer» = 22/7 × (7/2)² × 10= (220× 49)/7×4= 55 × 7 = 385 |
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| 27. |
H 7. Show that the function defined as follows is continuous at x=1, x-2 but not differentiable at thesepoints5x - 5if x >2 |
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Answer» not perfect ans. |
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| 28. |
The number of decimal places after which the decimal expansionof the number will terminate?(a) 224 x 53(b) 3(c) 4(d 5 |
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| 29. |
4. Which term of the series 2 +5 +8.... is 53 ?(a) 10(b) 12(c) 18o (d) 20 |
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Answer» Given series 2, 5, 8....is in AP First term a = 2, common difference d = 5 - 2 = 3 nth term of an APan = a + (n-1)d Therefore,Let mth term of an AP is 5353 = 2 + (m-1)*353 - 2 = 3m - 33m = 51 + 3m = 54/3 = 18 18th term of an AP is 53 (c) is correct option |
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| 30. |
Find the probability that a leap year selected at random will contain 53 Sunda2(D) 75(A) 73(B) 44(C) 7 |
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| 31. |
x %2B 4 = 10 |
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Answer» x+4=10x=10-4x=yLike if you find it useful = x+4=10 = x=10-4= x=6 (answer) |
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| 32. |
Exercise 1.57.Fill in the blanks using Roman numera) March hasc) A week hase) There aredays.days.days in a year.in true or fa |
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Answer» a =28 and 29 days in leap year a)xxxIc) BIOe)CCCLXV 317365 is the best answer 317365 is the best answer 365 is a good answer 317365 is the best answer (a).March has 31 days(b).a week has 7 days(c).there are 365 days in a year. a)= 31 daysc)= 7 days 365/366 days a) 31b) 7c) 365 ic correct answer (a)March has 31 days.(c)A week has 7 days.(e)There are 365 days in a year. |
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| 33. |
x %2B 4=10 |
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Answer» x+4=10x=10-4=6 Answer =6 X+4=10x=10-4=6 6 is best answer |
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| 34. |
14.Acarismovingwithavelocity20msThebrakes are applied to retard it at a rate of 2 ms2.What will be the velocity after 5 s of applying thebrakes ?.Ans. 10 m s-1 |
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| 35. |
(-10*y^2 %2B y^4 %2B 24*y)/(y %2B 4) |
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Answer» 0 is the right answer of the following 0 is the right answer of the following |
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| 36. |
n method and alsoe quotient and the remainder.0Practice set 3.31. Divide each of the following polynomiathe following polynomials by synthetic division method and aloxlinear division method. Write the quotient and the rem) (2m² - 3m + 10) = (m - 5)* 10) = (m - 5)(ii) (r + 2x +(i) (r +2r+ + 3x2 + 4x + 5) = (x + 2)(iii) ( -216) + (-6)(-6) L(iv) (2IV) (2r+ + 3.x2 + 4x - 2x) = (x + 3)22 (4 - 3x - 8) + (x + 4) (vi) (y - 3y + 5y - 1) + (y - 1) |
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Answer» Solutions:- Synthetic method Dividend:- 2x⁴+3x³-2x²+4xDivisor:- x+3opposite of :- 3 =-3 -3) 2 3 -2. 4 0 -6. 9 -21. 51_____________________ 2. -3. 7. -17. 51 Co-efficient of quotient= (2,-5,7,-17) Quotient=. 2x³-3x²+7x-17 Remainder =. 51 |
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| 37. |
-1/4 %2B 3/10 %2B 4/5 |
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Answer» Q. 1 3/10 + 1 4/5 - 1 1/4 Ans: solving mixed fraction into fraction.. so, =10×1+3/10 + 5×1+4/5 - 4×1+1/5so, =10+3/10 + 5+4/5 - 4+1/5so, =13/10 + 9/5 -5/5so, taking the L. C. M of all the denominator of 10, 5 and 4. so, =10×5×4 = 50×4 = 200so, dividing L. C. M with denominator ==10×20+ 5×40 - 4×50equaling denominator by multiplying the no in both numerator and denominator also to get 200.. a) =13×20/10×20 =260/200b) =9×40/5×40= 360/200c) =5×50/4×50= 250/200so, now.. = 260/200+360/200-250/200= 260+360-250/200=620-250/200=370/200 so now, =370/ 20 Now cutting 0 from both numerator and denominator = 37 / 20 1.85 is correct answer 37/20 is the correct answer |
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| 38. |
Divide 2r? +X-5 by x + 2 and verify the division algorithm. |
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Answer» rong |
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| 39. |
Divide 3x' +x22x+5 by 1 + 2r +r |
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| 40. |
RHILWAY LTNES ARE EXAMPOF |
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Answer» Ans: Parallel lines Railway tracks are made in such a way that they have to be on the same distance at each point so that the wheels of train be on track.The axil size of the train wheels is same for each pair of wheel through out the train.Hence, the railway tracks has to be parallel.The railway line an example of parallel lines |
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| 41. |
ed Examp.Evaluate :a. (-2)-5 |
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Answer» -1/32 is the right answer -1/32 is the right answer -1/32 is the correct answer -32. just simply open it...-2×-2× -2× -2×-2 -1/32 is the correct answer of the following question -32 is the right answer |
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| 42. |
given that √2 is irrational, prove that (5+3√2)is an irrational number. |
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| 43. |
A rectangle measuring 5 cm by 3 cmis scaled up to create an image withside lengths of 7.5 cm and 4.5 cm.How do the areas of thetwo similar figures compare?a) The area of the image is 1.5 times larger.b) The area of the image is 2.25 times larger.c) They have the same area becausethey are similar figures.d) none of the above |
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| 44. |
C.P =$9600, gain= 16×3+2/3℅ S.P =? |
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Answer» Explanation: CP = 9600 GAIN = 16 2/3% = 16.67% SP = CP + (CP*GAIN PERCENT)/100 = 9600 + (9600*16.67)/100 = 9600 + 1600 = 11200 Solution:SP = 11200 If you find this answer helpful then like it. $9600 ,16 ×3+2//jhh 9787 34rv 75 243 |
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| 45. |
2x-1/3–6x-2/5=1/3 |
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Answer» 2x-1/3-6x-2/5=1/3(-1/3)-(2/5)-(1/3)=6x-2x(-2/3)-(2/5)=4xTake LCM of 3,5=15(-2(5)-2(3))/15=4x(-10-6)/15=4x-16/15=4xx=-4/15 |
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| 46. |
S 9&3â: 23 2/39 =1/6an&d% Jre |
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| 47. |
complementary and the smallerדb) The angles arefc) The ancomplementary and the larger is four times the smaller.and |
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Answer» complementary anglesso angles are x and 90-xso x=4(90-x)x=360-4xso 5x=360 so x=72so angles are 18 and 72 |
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| 48. |
Suppose we represent the distance above the ground by a positive Integer anothat below the ground by a negative integer. If an elevator descends at a rate ofSm/min and begins to descend from 15 m above the ground, what will be itsposition after 45 minutes? |
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Answer» Since downwards is negative, the velocity of the elevator is -5 m/min. Displacement from initial position = Velocity x Time = -5 m/min x 45 min = -225 m. However, since we started 15 m above ground, displacement from the ground level = -225 + 15 m = -210 |
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| 49. |
Fill in the blanks:a)b)c)1.Radius of the circle = Ădiameter of the circle.The diameter is theBy joining two points on the circle, we get achord of the circle. |
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Answer» radius of a circle = 1/2* diameter2) diameter is the biggest chord3)chord |
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| 50. |
का स्प-रखा है, का लम्बाई ज्ञात कजए ।Two concentric circles of radii a and b (a > b) are given. Find the length ofthe chord of the larger circle which touches the smaller circle. |
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Answer» Angle OEC=90(tangent and radius at point of contact are perpendicular) by Pythagoras theoremOC^2=OE^2+CE^2a^2=b^2+CE^2√(a^2-b^2)=CECD=2CE[perpendicular drawn from centre bisect the chord]CD=2√(a^2-b^2) |
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