This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A number consists of two digits, the digit at ones place is two times thedigit at tens place. The number, formed by interchanging the digits, is 36more than the original number, find the original number. |
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Answer» please like my answer if you find it useful thank u |
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| 2. |
Q26. There are two concentric circles with centre OAD is a chord of a larger circle intersecting the smallercircle at B and C Prove that AB-CD |
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Answer» Let AD and BC be the chords of bigger and smaller circles. By the definition of segments, we have AP = AB + BP ....(1) and PD = CP + CD....(2) Let OP be the perpendicular line to the chords. Since the perpendicular line to the chord bisects the chord, OP bisects the chord AD and OP bisects the chord BC. Thus, AP = PD...(3) and BP = CP...(4) In equations (1) and (2), use AP = PD AB + BP = CP + CD Since BP = CP, we have AB = CD |
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| 3. |
: Find the work done by the resultant of theforces F1 -3i +4j-5k , F2 i + j + k andF 2i-4j+ 7k in displacing a particle fromthe point (1,2,4) to the point (3,4,7) |
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| 4. |
11. The mean of S numbers is 27. If one more number is inchuded, (dhen the mean is 25. Find the incutemumber |
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| 5. |
x^2-(3√2+2i)x+6√2i=0 |
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Answer» x^2-3√2x-2i(x-3√2)=0(x-3√2)*(x-2i)=0 |
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| 6. |
MATH1. What is integers? Represent Integer on number line. |
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Answer» Integerscan berepresentedon thenumber line. On anumber line, the positive numbers are to the right of zero and the negative numbers are to the left of zero. ... Anintegeron the horizontalnumber lineis greater than thenumberon its left and less than thenumberon its right |
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| 7. |
A capillary tube of radius 0.25 ínm is dippedvertically in a liquid of density 800 kg m3 andof surface tension 3x 102 Nm2.The angle ofcontact of liquid-glass is given by cose 0.3.Ifg 10ms2 the rise of liquid in the capillary2) 0 v 1 0-3 4) 0 00 |
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| 8. |
12. In the following question correctthe given equation by interchangingtwo numbers.8x3+4+9-5 16(a) 3 and 4(c) 5 and3(b) 4 and 8(d) 5 and 9 |
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Answer» c. 5 and 3 ((8×5)/4)+9-3=(40/4)+6=10+6=16 |
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| 9. |
or 6.8 In a right triangle, the square of the hypotenuse is equal to theum of the squares of the other two sides. |
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Answer» Given: A right triangle ABC right angled at B. To Prove: AC^2= AB^2+ BC^2 Construction: Draw BD ⊥ AC Proof: In Δ ADB and Δ ABC, ∠ADB = ∠ ABC (each 90°) ∠BAD = ∠ CAB (common) Δ ADB ~ Δ ABC (By AA similarity criterion) Now, AD/AB =AB/AC(corresponding sides are proportional) AB2= AD × AC … (i) Similarly, Δ BDC ~ Δ ABC BC2= CD × AC … (ii) Adding (i) and (ii) AB^2+ BC^2= (AD × AC) + (CD × AC) AB^2+ BC^2= AC × (AD + CD) AB^2+ BC^2= AC^2 Hence Proved. |
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| 10. |
the circumference 132 cm of a circle A is equal to the sum of the circumference at two circle B and C. The circumference of circle B is 88 cm.find the radius of circle C. |
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Answer» B+C=A2πR+2πr=13288+2πr=1322πr=44r=7cm |
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| 11. |
e2ydydx(İ) If хт , yn(x + yyn + n, show thatdydx xx= (x+y):n + ning log on both sides we get, |
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| 12. |
d' yn (sin x), prove thatįttanx--+ycohe0dr2dydxxample 2. Ify si |
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| 13. |
find dy/dx y=log[X+√x²a²/-x+√x²+a²] |
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| 14. |
0 Find dhe Sum % dhu fivs 3 23 s ďŹ,/ HHu AP* ) lo ")*L J | H |
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Answer» a=7, d=10-7=3Sum of 23 terms=(23/2)[2*7+(23-1)3]=(23/2)[14+66]=(23/2)[80=920 |
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| 15. |
If y = (sin x)log x , finddydx. |
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Answer» Taking log on both sideslogy=logx(logsinx)Differentiate on both sides1/y*dy/dx=logx/sinx*cosx+logsinx*1/Xhencedy/dx=sinx^logx(logx*cotx+logsinx/X) |
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| 16. |
-2/3 %2B 5/9 %2B 1/3 %2B 3/4 |
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| 17. |
(f) There forces2 i+3 j+4 k, i-4 j \text { and }-3 \hat{i}+\hat{j}-4 \hat{h}areacting on a particl |
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Answer» resultant of the forces will be sum of given vectors = (2i+3̂j+4̂k̂)+(i-4̂j)+̂(-3i+̂ĵ-4k̂) = 0So, the particle will be in equillibrium thanks |
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| 18. |
TRY THESE1. A number line representing integers is given belowKH I J LB C D E F G-3 -2-3 and -2 are marked by E and Frespectively. Which integersD. H. J. M and O?Which integers are marketbanding order and then mark them on a |
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Answer» D=(-4)H=0J=1M=5O=7 D = -4 H=0J =2O= 7 these are the answer of your questions D--4H-0J-2M-5O-7 the answer is D= (-4) |
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| 19. |
Express each of the following as a per cent:a.b.C.e. 2.6f 0.38h. 0.25g 1.051.2.75 J 9.18J 3.60,521,043.413.6k. |
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| 20. |
t. Eind the LCof the following members in which one mumber is the factor of thseother(a) S 20 (b 6.18 (e) 12.4s (45 |
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Answer» if one number is factor of other then LCM is the number which is the no. is of factor.a) 5, 20 so 5 is factor of 20 so LCM is 20b) 6,18 here LCM is 18c) 12, 48 here LCM is 48d) 9, 45 here LCM is 45 |
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| 21. |
If tangent at (1, 2) to the circle c: x2 + y2= 5 intersects the circle c2: x2 y2= 9 at A & B and tangentsat A & B to the second circle meet at point C, then the co-ordinates of C is(A) (4, 5)(B) (9/15 , 18/5)(C) (4 , -5)(D) (9/5 , 18/5) |
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| 22. |
order are (,,le sum of a two digit number and the number obtained byreversingthe digits is 66. If the digits of the number differ byunl nrove that theyeavingQ.h d-72, find the number. |
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Answer» Let the digits of number are n and (n + 2) Then number = n*10 + (n + 2)= 10n + n + 2= 11n + 2 If digits are reversed then number = (n + 2)*10 + n= 10n + 20 + n= 11n + 20 According to the given condition (11n + 2) + (11n + 20) = 6622n + 22 = 6622n = 44n = 44/22 = 2 Therefore number = 11n + 2= 11*2 + 2 = 24 |
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| 23. |
((-5)/9)^8*(((-5)/9)^4*((-5)/9)^12) |
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Answer» can you tell me answer in detail by multiplying 24 right answer Hoga Yahi right answer hai |
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| 24. |
\begin { equation } \begin{array}{ll}{\text { Answer the following. }} \\ {\text { i) }(5 / 7+3 / 5) 9 / 5=} \\ {\text { ii) } 3 / 4-2 / 9+5 / 18=}\end{array} \end { equation } |
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| 25. |
iosoof two circles are 19 cm and 9 cm respectively.us of the circle which has circumference equalum of the circumferences of the two circles. |
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| 26. |
Exercise 4.1If a three digit number 24x is divisible by 9. Thenfind out the value of x, where x is a digit |
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Answer» for the number to be divisible by 9the summof digits should be 9hence2+4+X=96+X=9X=3hencethe no should be 243 |
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| 27. |
If a three digit number 24x is divisible by 9.Then find out the value of x, where x is adigit. |
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Answer» It states that “a number divisible by 9 should have the sum of its digits equal to a multiple of 9”. Now, here in this question we know that 24x is divisible by 9. So, the relation between the digits and multiple of 9 will be: Letmmbe a factor of the multiple of 9. 2+4+x=9m2+4+x=9m 6+x=9m6+x=9m 6+x9=m6+x9=m This is here an equation in two variables. So it should have infinite solutions. But sincexxis a digit,xxcould neither be negative nor could be more than 9. Andmmcould only be a natural whole number because the sum of digits of a number could never be negative and in this case it couldn't even be zero because if any of the numbers in an equation of addition is a natural number then the sum should also be a natural number. Therefore, we should have the values ofxxbetween the range 1–9. We should find it by trial and error method. I can't try them all here, so I am giving you the answer to it now. The only possible value forxxwhich would satisfy the situations is 3. Therefore,x=3x=3. |
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| 28. |
1.Ifathreedigitnumber24xisdivisibleby9.Then find out the value of x, where x is adigit. |
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Answer» Three digit number = 24x It is divisible by 9. Now, We know that, a number is divisible by 9 only when the sum of the digits of the number of divisible by 9. Then, Sum of the digits = 2 + 4 + x = 6 + x So, If x = 3 , then , 6 + x = 6 + 3 = 9 Then, 243 will be divisible by 9. |
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| 29. |
(120*(20^(-5)*9^(-5)))/((3^(-3)*(4*5^(-4)))) |
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| 30. |
QUL =X 1kl : o8E}}um — kB ( —__/‘x M) us =4 ‘01 |
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| 31. |
Questions.-between Jiya and Kinn.1. Divide 100 in the ratio 6:4 between Jiya anfris of symmetry. |
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| 32. |
(-7)/5 %2B 4/9 %2B (-5)/9 %2B 4/5 |
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Answer» -0.71 is the answer for ur solution -32/45 is the answer of your question -32/45 is the correct answer of the given question |
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| 33. |
MangÄźu marks a frock for? 875 andallows a discount of 22%. Find theselling price of the frock? |
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Answer» Marked Price=Rs.875Discount=22%∴Selling Price=875(1-22/100)=Rs.682.50 |
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| 34. |
/3 10 V<€ /,/) ? /um रह \/B0 (/ W9l (/(9 o .%raofi,& L ’7l 5 e |
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Answer» If ABC is a triangle then <)ABC + <)BCA + <)CAB = 180 degrees. ProofDraw line a through points A and B. Draw line b through point C and parallel to line a.Since lines a and b are parallel, <)BAC = <)B'CA and <)ABC = <)BCA'.It is obvious that <)B'CA + <)ACB + <)BCA' = 180 degrees.Thus <)ABC + <)BCA + <)CAB = 180 degrees. |
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| 35. |
1.5m l, 1.25m tuide and &5 umthe thithe hlastiasia e whust |
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| 36. |
s hepherd has 2ot sheep witheind the 'number of sheeps uoith himedrs le the increase inF Sheepsum |
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Answer» Number of sheeps = 200Increase in number of sheeps every year = 8% Then, Number of sheeps after 3 years= 200(1 + 8/100)^3= 200(1 + 2/25)^3= 200(27/25)^3= 200(1.08)^3= 200(1.26)= 252 Therefore number of sheeps after 3 years will be 252 |
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| 37. |
2८८१?L 81 Us eonjeAg थे. |
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| 38. |
e "पिन PRIt us o TR s ikt = » A g e . . |
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Answer» answer is 150 hope it will help you First take LCM of 50 and 30 . LCM = 150 Then take common denominator as 150.30/50 × 3/3 = 90 / 150 50/30 × 5/5 = 250 /150 Now add 250 + 90 /150 = 340 /150 When simplified, it gives 34 / 15 ( or ) 2 4/15 |
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| 39. |
L.The quadratic polynomial p(x) with -81 and 3 as productand one of the zeroes respectively is:(a) x2 + 24x - 81 (1) 12.-24-81(0) 22-24x + 81 (d) ? 24.81 |
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| 40. |
x^2+24x+9=0 |
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| 41. |
\lim _{x \rightarrow 0} \frac{1}{x} \log \left(1+\frac{8 x}{3}\right) |
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| 42. |
After elAfter eight years, Raj's ag!Therefore, the ratio of their ages after eight years4x + 8eight years = 5x + 8This is given to be 5:6ar equation. We muo since the expression. This isWe multipleTherefore,Cross-multiplication gives4x+8 55x+8 - 66 (4x + 8) = 5 (5x + 8).24x + 48 = 25x + 4024x + 48 - 40 = 25 x24x + 8 = 25x8 = 25x - 24xNote the2x + 370 (When,8 = xAnu's present age = 4x = 4 x 8Raj's present age = 5x = 5 xve.Therefore,This step can bedirectly obtained by*cross-multiplicationEXERCISE 2.6Solve the following equations.x+1 732r +3 A89 x-=1515211. 31 - 1 = 22. 7-6x -37+4 -27y+4 - 44. 2-6y 5y+2 316. The ages of Hari and Harry are in the ratio 5their ages will be 3:4. Find their present ages.17. The denominator of a rational number is grnumerator is increased by 17 and the denonobtained is 5. Find the rational number |
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Answer» which number question plzz mention which question hai bhai ki pura page hai 8x-3=6x=2x=3=x=3/2 which question has to be solved ? 8x - 3 /3x =2; 8x - 3 = 2(3x) = 6x; 8x - 6x = 3; 2x = 3; x = 3/2 |
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| 43. |
1. Give an example of algebraic expression.2. If the three digit number 24x is divisible by 3, what is the vale of 'x' |
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Answer» 1. 2x² + 5x + 7 is an algebraic equation. 2. when 24x is divisible by 3 then,2+4+x = 6+x must be divisible by 3,so,so x can be 3, 6, 9 thank bro |
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| 44. |
(1) log (log327)(a)-3 (b) 0 (c)1 (d) 3(2)log2x3 el, d(a) 8(b) 512(c) 9(d) 81(3)16-log165 =2 |
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| 45. |
TH4. Show that the perpendiculars let fall from any point on the straight line 2 x +11 y -5upon the two straight lines 24x+7y-20 and 4x-3y-2-0are equal to each other |
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| 46. |
6. Jiya bought a box of pencils for48. If the cost of each pencilwas 4, how many pencils were there in the box? |
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Answer» No of pencils = Total cost/cost of 1 pencil = 48/4 = 12 pencils Like my answer if you find it useful! sir grade means wha? how to use valid grade |
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| 47. |
. The maximum length of a pencil that can be kept in a rectangular box of dimensions12cm ×9cm ×8cm, is |
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Answer» But the answer is 17 So what is the *answer* |
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| 48. |
3t, Sachin bought a bag worth 184, a pencil box worth t8 and a penwothse He gave a s00 rupee note to the shopkeeper. How muchmoney dd he get back? |
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Answer» Money he will get back = 500-184-78-56 = 500-318 = 182 Like my answer if you find it useful! |
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| 49. |
side is 30 metres more than the shorlel Siu7. The difference of squares of two numbers is 180. The square of the smaller number isgIed had been 5 km/h more, it wouldtimes the larger number. Find the two numbers. |
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Answer» Let the larger number = xThen the square of the smaller number = 8 times the larger number = 8xand the square of the larger numbe r = xAccording to the question,x - 8x = 180=> x - 8x - 180 = 0=> x - 18x + 10x - 180 = 0=> x(x - 18) + 10(x - 18) = 0=> (x - 18) (x + 10) = 0=> x - 18 = 0 or x + 10 = 0=> x = 18 or x = -10Thus, the larger number = 18 or -10Then, the square of the smaller number = 8(18) or 8(-10)= 144 or -80The square of a number can't be negative, so, the square of smaller number = 144Hence, the smaller number = sqrt(144) = 12The numbers are 12 and 18 |
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| 50. |
. « Dt Wé‘“fl“ = 22x +1=0 % T ज्ञात FBSEB2016A] |
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