order are (,,le sum of a two digit number and the number obtained byre

1.	order are (,,le sum of a two digit number and the number obtained byreversingthe digits is 66. If the digits of the number differ byunl nrove that theyeavingQ.h d-72, find the number.
Answer» Let the digits of number are n and (n + 2) Then number = n10 + (n + 2)= 10n + n + 2= 11n + 2 If digits are reversed then number = (n + 2)10 + n= 10n + 20 + n= 11n + 20 According to the given condition (11n + 2) + (11n + 20) = 6622n + 22 = 6622n = 44n = 44/22 = 2 Therefore number = 11n + 2= 11*2 + 2 = 24

order are (,,le sum of a two digit number and the number obtained byreversingthe digits is 66. If the digits of the number differ byunl nrove that theyeavingQ.h d-72, find the number.

Answer»

Let the digits of number are n and (n + 2)

Then number = n*10 + (n + 2)= 10n + n + 2= 11n + 2

If digits are reversed then number = (n + 2)*10 + n= 10n + 20 + n= 11n + 20

According to the given condition (11n + 2) + (11n + 20) = 6622n + 22 = 6622n = 44n = 44/22 = 2

Therefore number = 11n + 2= 11*2 + 2 = 24