81279 + Interview Questions in Mathematics QA in Mathematics

1.	4xy+3yz+xy-2xz+(-3yz)+2xz
Answer» 4xy+3yz+xy-2xz-3yz+2xz5xy+0+0

Discussion

2.	Write down the number of vertices each of the followingsolids have.a Cuboidb. Cone c. Tetrahedron
Answer» a) Number of vertices in Cuboid = 8 b) Number of vertices in Cone = 0 c) Number of vertices in Tetrahedron = 4

2.

Write down the number of vertices each of the followingsolids have.a Cuboidb. Cone c. Tetrahedron

Answer»

a) Number of vertices in Cuboid = 8

b) Number of vertices in Cone = 0

c) Number of vertices in Tetrahedron = 4

Discussion

3.	लि किक eT I L L ही लॉ 7”PAl (20 RS T
Answer» In ∆AOB, draw a perpendicular line from O which intersect AB at M. In ∆AOM, angle AMO = 90angle OAM = 30cos 30 = AM/AO√3/2 = AM/21AM = 21×√3/2AB = 2(AM)=2(21×√3/2)=21√3 OM^2 = AO^2-AM^2=21^2-(21√3/2)^2=441-330.51=110.48OM =√110.48OM =10.51 OM = 10.51cm Area of ∆AOM = 1/2 AB × OM=1/2 ×21√3 ×10.51=191.14cm^2 Area of sector AOBY = 120πr^2/360=120×21×21×22/2520=462cm^2 Area of segment AYB = Area of sector OAYB -Area of∆OAB=462-191.14=270.86 Area of segment AYB is 270.86cm^2._______________

3.

लि किक eT I L L ही लॉ 7”PAl (20 RS T

Answer»

In ∆AOB, draw a perpendicular line from O which intersect AB at M.

In ∆AOM, angle AMO = 90angle OAM = 30cos 30 = AM/AO√3/2 = AM/21AM = 21×√3/2AB = 2(AM)=2(21×√3/2)=21√3

OM^2 = AO^2-AM^2=21^2-(21√3/2)^2=441-330.51=110.48OM =√110.48OM =10.51

OM = 10.51cm

Area of ∆AOM = 1/2 AB × OM=1/2 ×21√3 ×10.51=191.14cm^2

Area of sector AOBY = 120πr^2/360=120×21×21×22/2520=462cm^2

Area of segment AYB = Area of sector OAYB -Area of∆OAB=462-191.14=270.86

Area of segment AYB is 270.86cm^2._______________

Discussion

4.	If # is an operation such that for integers a and b we have a # b = -a +b-(-3), then find thevalue of the following:(a) - 4 # 3(b) - 7 # (-3)
Answer» -4#3=-4+3-(-3) =-4+3+3 =-4+6=2

Discussion

5.	The perimeter of the foor of a hall is300 m and its height is 6 m. Find the cost ofthe·painting the four walls at the rate of 15per square metre.1S
Answer» Perimeter = 300m2(l+b)= 300=> l+b= 150 mheight = 6mlateral surface area = 2(l+b)h= 2 1506 m²= 3006 m²= 1800m²Cost = 1800×15 = 27000 wrong and 27000

5.

The perimeter of the foor of a hall is300 m and its height is 6 m. Find the cost ofthe·painting the four walls at the rate of 15per square metre.1S

Answer»

Perimeter = 300m2(l+b)= 300=> l+b= 150 mheight = 6mlateral surface area = 2(l+b)*h= 2* 150*6 m²= 300*6 m²= 1800m²Cost = 1800×15 = 27000

wrong and 27000

Discussion

6.	220=퀸ǐ 7.3The sum of numbers when a number is noe sed by 10% and deceased by 10% is no what shenumber
Answer» Let the no. be x increase by 10% x+x/10=11x/10 now decrease 10%11x/10-(11x/10)/10=99x/100 99x/100 = 100 x = 10000/99 x = 101.0101

6.

220=퀸ǐ 7.3The sum of numbers when a number is noe sed by 10% and deceased by 10% is no what shenumber

Answer»

Let the no. be x

increase by 10%

x+x/10=11x/10

now decrease 10%11x/10-(11x/10)/10=99x/100

99x/100 = 100

x = 10000/99

x = 101.0101

Discussion

7.	7.Fig. 5.10Why is Axiom 5, in the list of Euclid's axioms, consthe question is not about the fifth postulate.)Olęconsidered a 'universal truth'? (Noe
Answer»

Discussion

8.	-1(d Noehese
Answer» option c

Discussion

9.	dividea) 22(x³yz³-x²y²z²+x²y³z²) by 11x²yzb) 26l³m⁴-52l²m+13l⁴m³ by 13l²m
Answer»

Discussion

10.	Fig. 8.34YZ is an isosceles triangle such that XY =X2, thenIfAXprove that altitude XT fromXbisects YZ.
Answer» (we have drawn a triangle XYZ and XT is the altitude)Given : A triangle ABC in which XY = XZ to prove : YT= TZProof:In triangle ABD and triangle ADC XT = XT ( common)∠XTY=∠XTZ(90° each)XY = XZ(given) soΔ ABD≡ΔACD( byRHS) So YT = TZ (by cpct) thanks please can you give 2more questions which I am posted

10.

Fig. 8.34YZ is an isosceles triangle such that XY =X2, thenIfAXprove that altitude XT fromXbisects YZ.

Answer»

(we have drawn a triangle XYZ and XT is the altitude)Given : A triangle ABC in which XY = XZ

to prove : YT= TZProof:In triangle ABD and triangle ADC

XT = XT ( common)∠XTY=∠XTZ(90° each)XY = XZ(given)

soΔ ABD≡ΔACD( byRHS)

So YT = TZ (by cpct)

thanks please can you give 2more questions which I am posted

Discussion

11.	s. The length and breadth of a rectangular piece of land are in the ratio of 5:3. If the total costof fencing it at 24 permetre isて9600, find its length and breadth.
Answer»

Discussion

12.	Using vectors show that the points A (-1, 4,-3), B (3, 2, -5), C(-3, 8,-5) andD(-3,2,1) are coplanar.Q23:
Answer»

Discussion

13.	Asma has a total of Rs 590 as currency notes in the Henominations ofand Rs 10. The ratio of the number of Rs 50 notes and Rs 20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?
Answer» Since Rs 50 & Rs 20 are in the ratio we can write,No. of Rs 50 notes= 3xNo. of Rs 20 notes= 5xAsShe has a total of 25 notes,So, we can write,No. of Rs 10 notes= 25-(3x+5x) = 25-8x Now we calculate the actual amount of each notes,Rs 50 note amount to = 50×3x = 150xRs 20 note amount to = 20×5x = 100xRs 10 note amount to = 10×(25-8x) = 250-80x Total sum of money he has = Rs590According to the problem,150x + 100x + 250 - 80x = 590170x = 340x = 2 Now we find out the actual no of notes in each case,No. ofRs 50 notes = 3 × 2 = 6 ; No. ofRs 20 notes = 5 × 2 = 10 ; No.ofRs 10 notes = 25-(8× 2) = 9

13.

Asma has a total of Rs 590 as currency notes in the Henominations ofand Rs 10. The ratio of the number of Rs 50 notes and Rs 20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?

Answer»

Since Rs 50 & Rs 20 are in the ratio we can write,No. of Rs 50 notes= 3xNo. of Rs 20 notes= 5xAsShe has a total of 25 notes,So, we can write,No. of Rs 10 notes= 25-(3x+5x) = 25-8x

Now we calculate the actual amount of each notes,Rs 50 note amount to = 50×3x = 150xRs 20 note amount to = 20×5x = 100xRs 10 note amount to = 10×(25-8x) = 250-80x

Total sum of money he has = Rs590According to the problem,150x + 100x + 250 - 80x = 590170x = 340x = 2

Now we find out the actual no of notes in each case,No. ofRs 50 notes = 3 × 2 = 6 ; No. ofRs 20 notes = 5 × 2 = 10 ; No.ofRs 10 notes = 25-(8× 2) = 9

Discussion

14.	if \left(m^{3}+2^{3}+3^{3}\right)^{-\frac{5}{2}}=(6)^{-5}then m ca
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Discussion

15.	. The length and the breadth of a rectangular field are in the ratio 5:3. I its perimeter128 m, find the dimensions of the field.The cost of fencing a rectangular field at 1s per metre is 1980.If the width of the telal23 m, find its length.7.A The cost of fencing th
Answer»

Discussion

16.	if the cost of 1 m fencing is ? 3.80, find the cost of fencing around a square of 196 mside.
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Discussion

17.	. Show that the points A (4, 5, 1), B (5, 3, 4), C (4, 1, 6) and D (3, 3,3) are coplanar.
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Discussion

18.	The cost of fencing a rectangular fieldat Rs. 7.50 per metre is Rs. 600. If itslength is 24 m, find its breadth:
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Discussion

19.	If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of thefield is 24 m, then the breadth of the field is
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Discussion

20.	Show that the four points A (-6,3,2), B (3,-2,4),C (5, 7,3) and D (-13, 17,-1) are coplanar.
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Discussion

21.	Show that the following vectors are co-planarand a+ b+ 2 where a, b and C are three noe3 a-7 b-4 c, 3 a 2 B+coplanar vectors.
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Discussion

22.	Q. Sonia went to a bank with Rs 2,00,000. She asked the cashier to give her Rs 500 andRs 2000 currency notes in return. She got 250 currency notes in all. Find the number ofeach kind of currency notes
Answer»

Discussion

23.	5.Vikas has a total of 100 currency notes in the denominations of 75 and 10. If the total valueof all the currency notes is 1625, then how many 5 notes does he have?
Answer»

Discussion

24.	Dxevesis has a total of 590 as currency notes in the denominations of2a10 The ratio of the nmker of 50 sctes andt20 notes in 35.aoa of 25 notes, how many netes of eachs denomination she has?
Answer» LetNo. of currency notes of Rs 50 = 3xNo. of currency notes of Rs 20 = 5xNo. of currency notes of Rs 10 = 25 - (3x+5x) = 25 - 8x Amount made by Rs 50 notes = 50 × 3x = 150xAmount made by Rs 20 notes = 20 × 5x = 100xAmount made by Rs 10 notes = 10 × (25-8x) = 250 - 80x Total money = 590 ⇒ 150x + 100x + 250 - 80x = 590 ⇒ 170x = 340 ⇒ x = 2 Denominations:Rs 50 = 3 × 2 = 6Rs 20 = 5 × 2 = 10Rs 10 = (25 - 8× 2) = 9

24.

Dxevesis has a total of 590 as currency notes in the denominations of2a10 The ratio of the nmker of 50 sctes andt20 notes in 35.aoa of 25 notes, how many netes of eachs denomination she has?

Answer»

LetNo. of currency notes of Rs 50 = 3xNo. of currency notes of Rs 20 = 5xNo. of currency notes of Rs 10 = 25 - (3x+5x) = 25 - 8x

Amount made by Rs 50 notes = 50 × 3x = 150xAmount made by Rs 20 notes = 20 × 5x = 100xAmount made by Rs 10 notes = 10 × (25-8x) = 250 - 80x

Total money = 590

⇒ 150x + 100x + 250 - 80x = 590

⇒ 170x = 340

⇒ x = 2

Denominations:Rs 50 = 3 × 2 = 6Rs 20 = 5 × 2 = 10Rs 10 = (25 - 8× 2) = 9

Discussion

25.	sNidhi nasdenomination does she have?Radhika has a total of7590 as currency notes in the denominations of 720 and 10. The ratio of thenumber of t50 notes and 220 notes is 3:5. If she has a total of 25 notes, how many notes of each denominationshe has?New Learnwell Mathematics-VIll
Answer»

Discussion

26.	henaieS or ClassThe length and breadth of a park are in the ratio 2: 1 and its perimeter is 240 m. A path 2 m wide mit, along its boundary. Find the cost of paving the path at 80 per m2
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Discussion

27.	The length and breadth of a rectangular piece of land are m he PaoUlD!J.lof fencing it at 24 per metre is? 9600, find its length and breadth.
Answer»

Discussion

28.	The length and breadth of a rectangilar piece of land are in the rati 5:3he total costaf fencing at 24 per metre is ? 9600, tind its lengh and breadt
Answer»

Discussion

29.	height of the cone2 Abucket of height 24 cm is in the form of frustum of a cone whosecircular ends are of diameter 28 cm and 42 cm. Find the cost of milk atICBSE 2013C]the rate of30 per litre, which the bucket can hold.Ilan İs in the form of a right circular cylinder of
Answer»

Discussion

30.	The length and breadth of a rectangular piece of land are in the ratio of 5:3.If thof fençing t t 24 per metre is 9600, find its length and breadth.
Answer»

Discussion

31.	The length and breadth of a rectangular piece of land are in the ratio of 5:3. If the tof fencing it at 24 per metre is 9600, find its length and breadth.
Answer»

Discussion

32.	Example 1: The cost of fencing a circular field at the rate of Rs 24 per metre isRs 5280. The field is to be ploughed at the rate of Rs 0.50 per m'. Find the cost ofploughing the field (Take t= ).100
Answer» Length of the fence (in metres) = Total cost / Rate = 5280/24 = 220 So, circumference of the field = 220 m Therefore, if r metres is the radius of the field, then 2πr = 220 or, 2 × 22/7× r = 220 or, r = (220 × 7)/(2 × 22) = 35 i.e., radius of the field is 35 m. Therefore, area of the field = πr2 = 22/7 × 35 × 35 m2 = 22 × 5 × 35 m2 Now, cost of ploughing 1 m2 of the field = Rs 0.50 So, total cost of ploughing the field = Rs 22 × 5 × 35 × 0.50 = Rs 1925

32.

Example 1: The cost of fencing a circular field at the rate of Rs 24 per metre isRs 5280. The field is to be ploughed at the rate of Rs 0.50 per m'. Find the cost ofploughing the field (Take t= ).100

Answer»

Length of the fence (in metres) = Total cost / Rate = 5280/24 = 220 So, circumference of the field = 220 m Therefore, if r metres is the radius of the field, then 2πr = 220

or, 2 × 22/7× r = 220 or, r = (220 × 7)/(2 × 22) = 35

i.e., radius of the field is 35 m.

Therefore, area of the field = πr2 = 22/7 × 35 × 35 m2 = 22 × 5 × 35 m2

Now, cost of ploughing 1 m2 of the field = Rs 0.50 So, total cost of ploughing the field = Rs 22 × 5 × 35 × 0.50 = Rs 1925

Discussion

33.	mue allu 2.8higrn8. Find the number of 4 cm cubes that can be cut out from a cuboid, whose dimensions are 32 cm by21 cm by 6 cm.
Answer» Volume of cuboid = lbhGiven l = 32, b = 21, h = 6 Volume of cuboid V1= 32216 = 4032 cm^3 Volume of cube = (side)^3Given side = 4cm Volume of cube V2= 444 = 64 cm^3 Let number of cubes that can be cut out = n Then, nV2 = V1n64 = 4032n = 4032/64 = 63 Therefore number of cubes can be cut out = 63

33.

mue allu 2.8higrn8. Find the number of 4 cm cubes that can be cut out from a cuboid, whose dimensions are 32 cm by21 cm by 6 cm.

Answer»

Volume of cuboid = l*b*hGiven l = 32, b = 21, h = 6

Volume of cuboid V1= 32*21*6 = 4032 cm^3

Volume of cube = (side)^3Given side = 4cm

Volume of cube V2= 4*4*4 = 64 cm^3

Let number of cubes that can be cut out = n

Then, n*V2 = V1n*64 = 4032n = 4032/64 = 63

Therefore number of cubes can be cut out = 63

Discussion

34.	or the room.The length and breadth of a rectangular piece of landof fencing it at 24 per metre is 9600, find its length and breadth.s.are in the ratio of 5 : 3. If the total cost
Answer» Thank you so much more than,, 🙂😇

Discussion

35.	the l length and breadth of a rectangular piece of land are in the ratio 5 is to 3 if the total cost of fencing it at rupees 24 per metre is rupees 9600 find its length and breadth
Answer»

Discussion

36.	How many square tiles of side 20 cm will be needed to pave a foot path which is 2 metreswide and surrounds a rectangular plot 40 m long and 22 m wide?
Answer» For rectangular floor,Length = 6m = 6 x 100 cm = 600 cmBreadth = 4m = 4 x 100cm = 400cmSo area of the floor = l x b= 600cm x 400 cm = 240000 Now, side of one square tile = 20cmSo area occupied by one square tile = 20cm x 20cm = 400 Thus, Number of square tiles = Area of floor/Area of 1 tile= 240000/400= 600 tiles

36.

How many square tiles of side 20 cm will be needed to pave a foot path which is 2 metreswide and surrounds a rectangular plot 40 m long and 22 m wide?

Answer»

For rectangular floor,Length = 6m = 6 x 100 cm = 600 cmBreadth = 4m = 4 x 100cm = 400cmSo area of the floor = l x b= 600cm x 400 cm = 240000

Now, side of one square tile = 20cmSo area occupied by one square tile = 20cm x 20cm = 400

Thus, Number of square tiles = Area of floor/Area of 1 tile= 240000/400= 600 tiles

Discussion

37.	Value is greatel allu TUW!4. Suresh wants to arrange the following rational numbers in ascending order. How will hearrange them?z1z idei
Answer» first take lcm of denominator then make equal all denominators equal to lcm by multiplying in numerator and denominator by same number then you can arrange easily.-3/5< -13/20< 6/15< 7/12< 9/10 . the answer is-3/5<-13/20<6/15<7/12<9/10like my answer 3-/5<13/20<6/15<7/12<9/10 is the correct answer the answer is-3/5<-13/20<6/15<7/12<9/10 answer

37.

Value is greatel allu TUW!4. Suresh wants to arrange the following rational numbers in ascending order. How will hearrange them?z1z idei

Answer»

first take lcm of denominator then make equal all denominators equal to lcm by multiplying in numerator and denominator by same number then you can arrange easily.-3/5< -13/20< 6/15< 7/12< 9/10 .

the answer is-3/5<-13/20<6/15<7/12<9/10like my answer

3-/5<13/20<6/15<7/12<9/10 is the correct answer

the answer is-3/5<-13/20<6/15<7/12<9/10 answer

Discussion

38.	pully, allu verify the result for the given values(+3x)(437°) for x= and y=3Mathem
Answer» Kindly post the full questionthanks (-3x²)(4xy³)(-2/3x³)put x=3/4 y=3 we get{(-3)(3/4)²}{4(3/4)(3)³}{(-2/3)(3/4)³}=(-27/16)x(81)x(-54/192)=19683/512 19683/512 is the correct answer of the given question 19683/512 is the best answer

38.

pully, allu verify the result for the given values(+3x)(437°) for x= and y=3Mathem

Answer»

Kindly post the full questionthanks

(-3x²)(4xy³)(-2/3x³)put x=3/4 y=3 we get{(-3)(3/4)²}{4(3/4)(3)³}{(-2/3)(3/4)³}=(-27/16)x(81)x(-54/192)=19683/512

19683/512 is the correct answer of the given question

19683/512 is the best answer

Discussion

39.	rauipath 2 m wide surrounds a circular pond of diameter 40 m. How manymetres of gravel are required to grave the path to a depth of 20 cm?%. Acubic1. Cumit is spreac
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Discussion

40.	Aroad which is 7 m wide surrounds acircular park whose circumference is352 m. Find the area of road. CBSE 2012
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Discussion

41.	2. A bus driver filled the bus tank with 33 litre of diesel. Next day hefilled it with 17 litre of diesel. If the cost of diesel is Rs.28 per litre,how much did he spend in all?
Answer» ans=rs.1400bcoz, 33×28=924and , 17×28=476 924+476 =1400Rs the total diesel consumed is 28(33+17)=1400 a bus driver filled the bus tank of diesel =33 liters next day he filled =17 liters 33×28 =924so we multiply 17×28= 476we add 924+476= 1400 the answer is the bus driver spend 1400 1400

41.

2. A bus driver filled the bus tank with 33 litre of diesel. Next day hefilled it with 17 litre of diesel. If the cost of diesel is Rs.28 per litre,how much did he spend in all?

Answer»

ans=rs.1400bcoz, 33×28=924and , 17×28=476 924+476 =1400Rs

the total diesel consumed is 28(33+17)=1400

a bus driver filled the bus tank of diesel =33 liters next day he filled =17 liters

33×28 =924so we multiply 17×28= 476we add 924+476= 1400 the answer is the bus driver spend 1400

1400

Discussion

42.	11. The radius of a circular field is 20 m. Inside it runs a path 5 m wide all around. Find the area of thepath. (Take Ď =-)7
Answer» Area of circular field Af = pirr Given, r = 20 m Then,Af = 22/72020 = 8800/7 Area of inner circle Ai = pi(r - 5)(r - 5) = 22/7(20-5)(20-5) = 22/71515 = 4950/7 Area of circular path= Af - Ai= 8800/7 - 4950/7= 3850/7= 550 m^2

42.

11. The radius of a circular field is 20 m. Inside it runs a path 5 m wide all around. Find the area of thepath. (Take Ď =-)7

Answer»

Area of circular field Af = pi*r*r

Given, r = 20 m

Then,Af = 22/7*20*20 = 8800/7

Area of inner circle Ai = pi*(r - 5)*(r - 5) = 22/7*(20-5)*(20-5) = 22/7*15*15 = 4950/7

Area of circular path= Af - Ai= 8800/7 - 4950/7= 3850/7= 550 m^2

Discussion

43.	9. A 50 litre of solution of acid and water contains 10 litre of acid. How much water must beadded to make the solution 10 % acidic.
Answer» in 50 litre 10 litre is acid so 40 litre is waterso to get 10% acidic we need to add 50 litre of water so acid percentage=10/100*100=10%

Discussion

44.	A cรณntainer shaped like a right circular cylinder having diameter 12 cm and heis full of ice cream. The ice cream is to be filled into cones of height 12 cm an6 cm, having a hemispherical shape on the top. Find the number of such conebe filled with ice cream.ciliirmsss2 mm.must be m
Answer»

Discussion

45.	17. A container shaped like a right circular cylinder has a diameter 12 cm and height 15 cm, isfull of ice-cream. The ice-cream is to be filled into 10 equal cones having a hemisphericalshape on the top. If the height of the cone is 4 times its radius, then find the height of thecone.
Answer» For right circular cylinder Diameter = 12 cm Radius(R1) = 12/2= 6 cm & height (h1) = 15 cm Volume of Cylindrical ice-cream container= πr1²h1= 22/7 × 6× 6× 15= 11880/7 cm³ Volume of Cylindrical ice-cream container=11880/7 cm³ For cone, Diameter = 6 cm Radius(r2) =6/2 = 3 cm & height (h2) = 12 cmRadius of hemisphere = radius of cone= 3 cm Volume of cone full of ice-cream= volume of cone + volume of hemisphere = ⅓ πr2²h2 + ⅔ πr2³= ⅓ π ( r2²h2 + 2r2³) = ⅓ × 22/7 (3²× 12 + 2× 3³) = ⅓ × 22/7 ( 9 ×12 + 2 × 27) = 22/21 ( 108 +54) = 22/21(162) = (22×54)/7 = 1188/7 cm³ Let n be the number of cones full of ice cream. Volume of Cylindrical ice-cream container =n × Volume of one cone full with ice cream 11880/7 = n × 1188/7 11880 = n × 1188 n = 11880/1188= 10 n = 10 The children are joyful on seeing the ice cream man

45.

17. A container shaped like a right circular cylinder has a diameter 12 cm and height 15 cm, isfull of ice-cream. The ice-cream is to be filled into 10 equal cones having a hemisphericalshape on the top. If the height of the cone is 4 times its radius, then find the height of thecone.

Answer»

For right circular cylinder

Diameter = 12 cm

Radius(R1) = 12/2= 6 cm & height (h1) = 15 cm

Volume of Cylindrical ice-cream container= πr1²h1= 22/7 × 6× 6× 15= 11880/7 cm³

Volume of Cylindrical ice-cream container=11880/7 cm³

For cone,

Diameter = 6 cm

Radius(r2) =6/2 = 3 cm & height (h2) = 12 cmRadius of hemisphere = radius of cone= 3 cm

Volume of cone full of ice-cream= volume of cone + volume of hemisphere

= ⅓ πr2²h2 + ⅔ πr2³= ⅓ π ( r2²h2 + 2r2³)

= ⅓ × 22/7 (3²× 12 + 2× 3³)

= ⅓ × 22/7 ( 9 ×12 + 2 × 27)

= 22/21 ( 108 +54)

= 22/21(162)

= (22×54)/7

= 1188/7 cm³

Let n be the number of cones full of ice cream.

Volume of Cylindrical ice-cream container =n × Volume of one cone full with ice cream

11880/7 = n × 1188/7

11880 = n × 1188

n = 11880/1188= 10

n = 10

The children are joyful on seeing the ice cream man

Discussion

46.	XA4I1५ Motहि.-5
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Discussion

47.	÷ (xa)bcOCthat xa (a-c)ProvexaCb-c)
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Discussion

48.	Q.4.Find the value of xa-bxb-c xc-a
Answer» X^(a-b+b-c+c-a) =X^0 = 1

Discussion

49.	11. The difference between circumference and diameter of a circular plot is 52.5 m. Find thearea of the circular plot.
Answer»

Discussion

50.	9 A circular path runs around a circular plot. If thecircumference of the plot and the path are 44 mand 88 m, respectively, find the width of thepath.
Answer» Circumference of circular plot = 2pir1222/7r1 = 44r1 = 7 m Circumference of circular path = 2pir2222/7r2 = 88r2 = 14 m Width of circular path= r2 - r1= 14-7 = 7m

50.

9 A circular path runs around a circular plot. If thecircumference of the plot and the path are 44 mand 88 m, respectively, find the width of thepath.

Answer»

Circumference of circular plot = 2*pi*r12*22/7*r1 = 44r1 = 7 m

Circumference of circular path = 2*pi*r22*22/7*r2 = 88r2 = 14 m

Width of circular path= r2 - r1= 14-7 = 7m

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

4xy+3yz+xy-2xz+(-3yz)+2xz

Write down the number of vertices each of the followingsolids have.a Cuboidb. Cone c. Tetrahedron

लि किक eT I L L ही लॉ 7”PAl (20 RS T

If # is an operation such that for integers a and b we have a # b = -a +b-(-3), then find thevalue of the following:(a) - 4 # 3(b) - 7 # (-3)

The perimeter of the foor of a hall is300 m and its height is 6 m. Find the cost ofthe·painting the four walls at the rate of 15per square metre.1S

220=퀸ǐ 7.3The sum of numbers when a number is noe sed by 10% and deceased by 10% is no what shenumber

7.Fig. 5.10Why is Axiom 5, in the list of Euclid's axioms, consthe question is not about the fifth postulate.)Olęconsidered a 'universal truth'? (Noe

-1(d Noehese

dividea) 22(x³yz³-x²y²z²+x²y³z²) by 11x²yzb) 26l³m⁴-52l²m+13l⁴m³ by 13l²m

Fig. 8.34YZ is an isosceles triangle such that XY =X2, thenIfAXprove that altitude XT fromXbisects YZ.

s. The length and breadth of a rectangular piece of land are in the ratio of 5:3. If the total costof fencing it at 24 permetre isて9600, find its length and breadth.

Using vectors show that the points A (-1, 4,-3), B (3, 2, -5), C(-3, 8,-5) andD(-3,2,1) are coplanar.Q23:

Asma has a total of Rs 590 as currency notes in the Henominations ofand Rs 10. The ratio of the number of Rs 50 notes and Rs 20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?

if \left(m^{3}+2^{3}+3^{3}\right)^{-\frac{5}{2}}=(6)^{-5}then m ca

. The length and the breadth of a rectangular field are in the ratio 5:3. I its perimeter128 m, find the dimensions of the field.The cost of fencing a rectangular field at 1s per metre is 1980.If the width of the telal23 m, find its length.7.A The cost of fencing th

if the cost of 1 m fencing is ? 3.80, find the cost of fencing around a square of 196 mside.

. Show that the points A (4, 5, 1), B (5, 3, 4), C (4, 1, 6) and D (3, 3,3) are coplanar.

The cost of fencing a rectangular fieldat Rs. 7.50 per metre is Rs. 600. If itslength is 24 m, find its breadth:

If the cost of fencing a rectangular field at Rs. 7.50 per metre is Rs. 600, and the length of thefield is 24 m, then the breadth of the field is

Show that the four points A (-6,3,2), B (3,-2,4),C (5, 7,3) and D (-13, 17,-1) are coplanar.

Show that the following vectors are co-planarand a+ b+ 2 where a, b and C are three noe3 a-7 b-4 c, 3 a 2 B+coplanar vectors.

Q. Sonia went to a bank with Rs 2,00,000. She asked the cashier to give her Rs 500 andRs 2000 currency notes in return. She got 250 currency notes in all. Find the number ofeach kind of currency notes

5.Vikas has a total of 100 currency notes in the denominations of 75 and 10. If the total valueof all the currency notes is 1625, then how many 5 notes does he have?

Dxevesis has a total of 590 as currency notes in the denominations of2a10 The ratio of the nmker of 50 sctes andt20 notes in 35.aoa of 25 notes, how many netes of eachs denomination she has?

sNidhi nasdenomination does she have?Radhika has a total of7590 as currency notes in the denominations of 720 and 10. The ratio of thenumber of t50 notes and 220 notes is 3:5. If she has a total of 25 notes, how many notes of each denominationshe has?New Learnwell Mathematics-VIll

henaieS or ClassThe length and breadth of a park are in the ratio 2: 1 and its perimeter is 240 m. A path 2 m wide mit, along its boundary. Find the cost of paving the path at 80 per m2

The length and breadth of a rectangular piece of land are m he PaoUlD!J.lof fencing it at 24 per metre is? 9600, find its length and breadth.

The length and breadth of a rectangilar piece of land are in the rati 5:3he total costaf fencing at 24 per metre is ? 9600, tind its lengh and breadt

height of the cone2 Abucket of height 24 cm is in the form of frustum of a cone whosecircular ends are of diameter 28 cm and 42 cm. Find the cost of milk atICBSE 2013C]the rate of30 per litre, which the bucket can hold.Ilan İs in the form of a right circular cylinder of

The length and breadth of a rectangular piece of land are in the ratio of 5:3.If thof fençing t t 24 per metre is 9600, find its length and breadth.

The length and breadth of a rectangular piece of land are in the ratio of 5:3. If the tof fencing it at 24 per metre is 9600, find its length and breadth.

Example 1: The cost of fencing a circular field at the rate of Rs 24 per metre isRs 5280. The field is to be ploughed at the rate of Rs 0.50 per m'. Find the cost ofploughing the field (Take t= ).100

mue allu 2.8higrn8. Find the number of 4 cm cubes that can be cut out from a cuboid, whose dimensions are 32 cm by21 cm by 6 cm.

or the room.The length and breadth of a rectangular piece of landof fencing it at 24 per metre is 9600, find its length and breadth.s.are in the ratio of 5 : 3. If the total cost

the l length and breadth of a rectangular piece of land are in the ratio 5 is to 3 if the total cost of fencing it at rupees 24 per metre is rupees 9600 find its length and breadth

How many square tiles of side 20 cm will be needed to pave a foot path which is 2 metreswide and surrounds a rectangular plot 40 m long and 22 m wide?

Value is greatel allu TUW!4. Suresh wants to arrange the following rational numbers in ascending order. How will hearrange them?z1z idei

pully, allu verify the result for the given values(+3x)(437°) for x= and y=3Mathem

rauipath 2 m wide surrounds a circular pond of diameter 40 m. How manymetres of gravel are required to grave the path to a depth of 20 cm?%. Acubic1. Cumit is spreac

Aroad which is 7 m wide surrounds acircular park whose circumference is352 m. Find the area of road. CBSE 2012

2. A bus driver filled the bus tank with 33 litre of diesel. Next day hefilled it with 17 litre of diesel. If the cost of diesel is Rs.28 per litre,how much did he spend in all?

11. The radius of a circular field is 20 m. Inside it runs a path 5 m wide all around. Find the area of thepath. (Take Ď =-)7

9. A 50 litre of solution of acid and water contains 10 litre of acid. How much water must beadded to make the solution 10 % acidic.

A cรณntainer shaped like a right circular cylinder having diameter 12 cm and heis full of ice cream. The ice cream is to be filled into cones of height 12 cm an6 cm, having a hemispherical shape on the top. Find the number of such conebe filled with ice cream.ciliirmsss2 mm.must be m

17. A container shaped like a right circular cylinder has a diameter 12 cm and height 15 cm, isfull of ice-cream. The ice-cream is to be filled into 10 equal cones having a hemisphericalshape on the top. If the height of the cone is 4 times its radius, then find the height of thecone.

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Q.4.Find the value of xa-bxb-c xc-a

11. The difference between circumference and diameter of a circular plot is 52.5 m. Find thearea of the circular plot.

9 A circular path runs around a circular plot. If thecircumference of the plot and the path are 44 mand 88 m, respectively, find the width of thepath.

11. The radius of a circular field is 20 m. Inside it runs a path 5 m wide all around. Find the area of thepath. (Take Ď =-)7