Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In each of the following figures, find the valusof x:4.0

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thank you

2.

22.If ne=360 then find value ofn.

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3.

(299-" find the value ofn.find the value of n.27)21v

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Value of n in the given equation is 8.

the value of n is 8 in the given question

4.

e कत्ल e frdbund s ey मै.e et YT bt i S e st e |

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cosx=1/2x=cos^-1(1/2)x=cos^-1(cos(π/3))x=π/3

5.

7 2 K-10k-4-12

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6.

093 Convert 7103 Cm into m and cm

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7103cm= 100cm = 1mthen= 71.03 m

71.006

100 cm=1m=7103 cm/100=71m 3 cm Ans

answer is 7103 = 71.03m

7.

Find the perimeter of the rectangular flower bed which is 56 m long and 29 mbroad. Also find its area.

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perimeter =170,area=1624

perimeter=170 and area=1624

1624m to the power2.

area =l•b=56•29=1624perimeter=2(l+b)=2(56+29)=2×

perimeter = 170m area =1624 sq m

perimeter =170marea=1624 sq mis the correct answer.

area=l*b=56*29m^=1624m^perimeter=2(l+b)=2(56+29)m=170m

Perimeter- 170Area-1624m2

hnddu.hv isolated uf icon x training

Finding Perimeter and Area of rectangle ....

Perimeter of rectangle = 2(L+B) P(r)=2(56+29) =2*75 =150cm

Area of rectangle =L*B

A(r)=56*29 =1624cm.sq.

so, Perimeter is 150 cm and Area is 1624cm.sq.

p=2(85)=170area=lb=56*29=1624

perimeter = 170area = 1624is the best answer.

permiter: 170 and area;1624

8.

convert 8mm into cm

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1cm= 10mmso 1mm=1/10cmso 8mm= 8×1/10cm= 0.8cm

9.

Convert 57 cm to m

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1cn =100m57 cm = xmX= 57 ×100=5700 m

0.57 is the answer ....

57cm=57/100mas 1m=100cmtherefore 57/100m=0.57m

10 cm - 100mmtherefore - 57cm - 5.7mm

0.57 m is the correct answer...

Please mark my answer as the best because i am new

57/100 = 0.57 m is the answer because we know that in 1 m there is 100 cm , so to convert can into m we have to divide by 100

10.

convert 500 cm to km

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11.

Convert(a) 283459 mm into cm

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283459 cm

= 283459/10 mm

= 28345.9 mm

12.

8.1 12.10x-60 2 01. 2x-6s0

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1 .

2x - 6 ≤ 0

2x ≤ 6

x ≤ 3

2.

10x - 60 ≥ 0

10x ≥ 60

x ≥ 6

13.

Factorise ea2.1+ 10x 25x

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14.

Check whether 7 +3x is a factor of 3x3 + 7x.

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15.

3. Check whether 7 +3x is a factor of 3x37x.

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16.

Check whether 7+ 3x is a factor of 3x) +7x.

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17.

8. For a set A, A × A contains 16 elements andtwo of its elements are (1,3) and (0, 2). Findthe elements of A.

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Hamara desh ka mukhya mantri kon

can't understand the question

can't understand the question

18.

Check whether 7 + 3x is a factor of 3x +7x

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19.

Check whether 73x is a factor of 3x3 7x.

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20.

0 is 2.nkx2-14x + 8Find the value of k, for which one root of the quadratic equation ka2ORLond aual rogts.

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Like my answer of you find it useful

21.

3. Check whether 7 + 3x is a factor of 3x3 + 7x.

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in this type of question first start with7+3x=03x=-7x=-7/3now blindly put 😀 value of x in 3x^3+7xand check whether it becomes zero or not..3(-7/3)^3+7(-7/3)=-3(7×7×7)/(3×3×3)-49/3is not equal to zerohence we can say that it is not the factor

22.

What is the length of a wire required to fence a rectangular flower bed?

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Perimeter of the rectangle field=2(l+b) this will be the length required

23.

The breadth of a rectangular bed sheet is 5 m morethan half the length of the bed sheet. What is theperimeter of the bed sheet, if the length is x m?A. 3r + 12) mB. 2(x + 5) mC. (3x+ 10) mD. (4x+12) m.

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24.

If by selling a bed sheet forgain 20%?22150, a person loses 4%, for what amount should be sell it so as to

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Let cost price= X and given selling price= 150loss = 4% of cost price= 4 X /100loss = cost price- selling price4X/100 = X - 150X/25 = X - 150X - X/25 = 15024X/25 = 150X= 150 x 25/24= 625/4 = 156.25cost price = 156.25for 20%. gain selling price should be 156.25+156.25 × 20/100 =156.25 + 31.25 = 187.50

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25.

4 cm and5. A cylinder is made of a rectangular sheet, whose length and breadth are 418 cm respectively, by rolling it along its length. Find the volume of the cylinder.

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26.

Q.11. An ice cream cone has the radius of base 3.5 cm. If its height is 6 cm, find its volume.-

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27.

When freezing, water increases itsvolume by 1/11 . By what part of its volumewill ice decrease when it melts and turnsback into water?

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28.

15, 16 ** = 45find the values of x't, and x + 2If X +dth

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1) 32) 7 these are the correct answer for these questions Thank you

29.

Verify that 1/2-4axis a solution of the different al equation y=x-a ar .dx dy

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30.

If log12 18 = x and log24 54-y, prove that5(x-)) + xy = 1.

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please like the solution 👍 ✔️👍

please like the solution 👍 ✔️👍✔️

31.

14. I a -5 -- 3 and 8 =+3j-s, then show that the vectors+ 8 and 2-7 are perpendicular.

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32.

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find0) its inner curved surface area,(ii) the cost of plastering this curved surface at the rate of R 40 per m?

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33.

If tan'lx + tan-1 y = πany = ā, xy < 1, then Write the value ofx + y + xy4

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34.

cost of carpeting a room 15 m long with a carpet of wi200. Find the width of the room.dth 75 cm at 80 per met

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35.

xy 1x + y 5xy 11

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36.

Name1. A metal sheet 27 cm long, 8 cm broad and 1 cmthick is melted into a cube. What is the differencebetween surface areas of two solids?

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37.

xy + 1y-x-1(i) tanx + cot-ly = tan-

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38.

The area bounded by xy = 1, x = 0, y = 1and y = 2 is

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wseNotesearch Math Menu

use the method of cylindrical shells to find the souls obtained by rotating the region bounded by the given curves about the x axis

print print

document PDF

39.

जा oy%)oL gn)olSडॉन सर, k.¢ansS%g4.+doAN= e a4[ otoहे(a

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Distance between points (a, b)and (-a, - b)= sqrt[(-a - a)^2 + (-b - b)^2]= sqrt[(-2a)^2 + (-2b)^2]= sqrt(4a^2 + 4b^2)= 2sqrt(a^2 + b^2)

40.

N umb s Ol!) Joums , In He e xpansion 0b,J'OI\om!‘a,L (3-%')'(0_)4}_. T

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41.

LOL.Find the points on the Curve ay+4=0 at which thetangents are inclined at angle of 450 with the x-axis.

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42.

he perimeter of a square plot 360 m. Find(i) its area.(i) cost of fencing its boundary at the rate of R 40 per met(ii) cost of levelling the plot at 60 per square metre.0 per metre.

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43.

20. The circumference of a circular park is 660 m. A 7 m wide path surrounds it. Findof fencing the outer boundary at the rate of t 60 per metre.

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2πr=660so,r=660/2πso,r=105so outer radius=105+7=112so circumference=2π×112=(2×22×112)/7=704m^2so per metre square cost Rs60so704meter square =704×60=Rs42240

44.

If at-by-cz and b2-ac, prove that2xz

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A^x= b^y = c^z , from this if we like to express A & c in terms of b —-

A^x = b^y, => A = b^(y/x) , similarly , as c^z = b^y Therefore , c = b^(y/z). It is also given that ——

b^2 = Ac,

or,b^2 = {b^(y/x)}*{b^(y/z)} ( putting the value of A & c defined in terms of b )

Or, b^2= b^(y/x+y/z)

or, b^2 = b^{( yz +xy)/xz }

or, (xy + yz)/xz =2 (as base on the both side equals (b) , power is equal)

or, xy + yz = 2xz

or, y(x+z) = 2xz

So,y = 2xz/(x+z)

45.

If a-b ce and beac, prove that2xz

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46.

If one angle of triangle is 15° more than its second angle. The third angle is 25more than double the second angle. Find the three angles of the triangle.

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st angle =x2 nd angle =2x-153 rd angle =2x-15+20

so,x + 2x-15+2x-15+20=1805x-10=1805x=190x=382x-15=612x-15+20=81

47.

of the trnangle is Bmination in which one-fifth of the whole plusminus 25the remaining 60 candidates failed, find the total number of candidatesAcertain number ofcandidates appeared for an examination m which ore-ärst division, one-fourth plus 15 secured second division and one-fourth

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48.

Ex. 1. 15 chests of tea, each chest containing 20 kg costs R 350. What will be the price at this rate of 12chests each containing 25 kg?

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49.

40. A certain number of candidates appeared for an examination in which one-fifth of the whole plus16 secured first division, one-fourth plus 15 secured second division and one-fourth minus 25secured third division. If the remaining 60 candidates failed, find the total number of candidatesappeared.

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Let total number of candidates be Xso candidates who secured first Division=1/5x+16second division=1/4x+15third division=60-1/4x+25so, X=1/5x+16+1/4x+15+60-1/4x+25X=1/5x+1164/5x=116X=145

50.

AT R हि~43 BBकि 3(5-

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