This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In each of the following figures, find the valusof x:4.0 |
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Answer» thank you |
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| 2. |
22.If ne=360 then find value ofn. |
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| 3. |
(299-" find the value ofn.find the value of n.27)21v |
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Answer» Value of n in the given equation is 8. the value of n is 8 in the given question |
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| 4. |
e कत्ल e frdbund s ey मै.e et YT bt i S e st e | |
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Answer» cosx=1/2x=cos^-1(1/2)x=cos^-1(cos(π/3))x=π/3 |
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| 5. |
7 2 K-10k-4-12 |
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| 6. |
093 Convert 7103 Cm into m and cm |
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Answer» 7103cm= 100cm = 1mthen= 71.03 m 71.006 100 cm=1m=7103 cm/100=71m 3 cm Ans answer is 7103 = 71.03m |
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| 7. |
Find the perimeter of the rectangular flower bed which is 56 m long and 29 mbroad. Also find its area. |
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Answer» perimeter =170,area=1624 perimeter=170 and area=1624 1624m to the power2. area =l•b=56•29=1624perimeter=2(l+b)=2(56+29)=2× perimeter = 170m area =1624 sq m perimeter =170marea=1624 sq mis the correct answer. area=l*b=56*29m^=1624m^perimeter=2(l+b)=2(56+29)m=170m Perimeter- 170Area-1624m2 hnddu.hv isolated uf icon x training Finding Perimeter and Area of rectangle .... Perimeter of rectangle = 2(L+B) P(r)=2(56+29) =2*75 =150cm Area of rectangle =L*B A(r)=56*29 =1624cm.sq. so, Perimeter is 150 cm and Area is 1624cm.sq. p=2(85)=170area=lb=56*29=1624 perimeter = 170area = 1624is the best answer. permiter: 170 and area;1624 |
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| 8. |
convert 8mm into cm |
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Answer» 1cm= 10mmso 1mm=1/10cmso 8mm= 8×1/10cm= 0.8cm |
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| 9. |
Convert 57 cm to m |
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Answer» 1cn =100m57 cm = xmX= 57 ×100=5700 m 0.57 is the answer .... 57cm=57/100mas 1m=100cmtherefore 57/100m=0.57m 10 cm - 100mmtherefore - 57cm - 5.7mm 0.57 m is the correct answer... Please mark my answer as the best because i am new 57/100 = 0.57 m is the answer because we know that in 1 m there is 100 cm , so to convert can into m we have to divide by 100 |
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| 10. |
convert 500 cm to km |
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| 11. |
Convert(a) 283459 mm into cm |
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Answer» 283459 cm = 283459/10 mm = 28345.9 mm |
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| 12. |
8.1 12.10x-60 2 01. 2x-6s0 |
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Answer» 1 . 2x - 6 ≤ 0 2x ≤ 6 x ≤ 3 2. 10x - 60 ≥ 0 10x ≥ 60 x ≥ 6 |
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| 13. |
Factorise ea2.1+ 10x 25x |
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| 14. |
Check whether 7 +3x is a factor of 3x3 + 7x. |
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| 15. |
3. Check whether 7 +3x is a factor of 3x37x. |
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| 16. |
Check whether 7+ 3x is a factor of 3x) +7x. |
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| 17. |
8. For a set A, A × A contains 16 elements andtwo of its elements are (1,3) and (0, 2). Findthe elements of A. |
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Answer» Hamara desh ka mukhya mantri kon can't understand the question can't understand the question |
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| 18. |
Check whether 7 + 3x is a factor of 3x +7x |
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| 19. |
Check whether 73x is a factor of 3x3 7x. |
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| 20. |
0 is 2.nkx2-14x + 8Find the value of k, for which one root of the quadratic equation ka2ORLond aual rogts. |
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Answer» Like my answer of you find it useful |
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| 21. |
3. Check whether 7 + 3x is a factor of 3x3 + 7x. |
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Answer» in this type of question first start with7+3x=03x=-7x=-7/3now blindly put 😀 value of x in 3x^3+7xand check whether it becomes zero or not..3(-7/3)^3+7(-7/3)=-3(7×7×7)/(3×3×3)-49/3is not equal to zerohence we can say that it is not the factor |
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| 22. |
What is the length of a wire required to fence a rectangular flower bed? |
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Answer» Perimeter of the rectangle field=2(l+b) this will be the length required |
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| 23. |
The breadth of a rectangular bed sheet is 5 m morethan half the length of the bed sheet. What is theperimeter of the bed sheet, if the length is x m?A. 3r + 12) mB. 2(x + 5) mC. (3x+ 10) mD. (4x+12) m. |
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| 24. |
If by selling a bed sheet forgain 20%?22150, a person loses 4%, for what amount should be sell it so as to |
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Answer» Let cost price= X and given selling price= 150loss = 4% of cost price= 4 X /100loss = cost price- selling price4X/100 = X - 150X/25 = X - 150X - X/25 = 15024X/25 = 150X= 150 x 25/24= 625/4 = 156.25cost price = 156.25for 20%. gain selling price should be 156.25+156.25 × 20/100 =156.25 + 31.25 = 187.50 Like my answer if you find it useful! |
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| 25. |
4 cm and5. A cylinder is made of a rectangular sheet, whose length and breadth are 418 cm respectively, by rolling it along its length. Find the volume of the cylinder. |
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| 26. |
Q.11. An ice cream cone has the radius of base 3.5 cm. If its height is 6 cm, find its volume.- |
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| 27. |
When freezing, water increases itsvolume by 1/11 . By what part of its volumewill ice decrease when it melts and turnsback into water? |
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| 28. |
15, 16 ** = 45find the values of x't, and x + 2If X +dth |
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Answer» 1) 32) 7 these are the correct answer for these questions Thank you |
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| 29. |
Verify that 1/2-4axis a solution of the different al equation y=x-a ar .dx dy |
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| 30. |
If log12 18 = x and log24 54-y, prove that5(x-)) + xy = 1. |
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Answer» please like the solution 👍 ✔️👍 please like the solution 👍 ✔️👍✔️ |
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| 31. |
14. I a -5 -- 3 and 8 =+3j-s, then show that the vectors+ 8 and 2-7 are perpendicular. |
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| 32. |
The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find0) its inner curved surface area,(ii) the cost of plastering this curved surface at the rate of R 40 per m? |
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| 33. |
If tan'lx + tan-1 y = πany = ā, xy < 1, then Write the value ofx + y + xy4 |
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| 34. |
cost of carpeting a room 15 m long with a carpet of wi200. Find the width of the room.dth 75 cm at 80 per met |
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| 35. |
xy 1x + y 5xy 11 |
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| 36. |
Name1. A metal sheet 27 cm long, 8 cm broad and 1 cmthick is melted into a cube. What is the differencebetween surface areas of two solids? |
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| 37. |
xy + 1y-x-1(i) tanx + cot-ly = tan- |
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| 38. |
The area bounded by xy = 1, x = 0, y = 1and y = 2 is |
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Answer» wseNotesearch Math Menu use the method of cylindrical shells to find the souls obtained by rotating the region bounded by the given curves about the x axis print print document PDF |
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| 39. |
जा oy%)oL gn)olSडॉन सर, k.¢ansS%g4.+doAN= e a4[ otoहे(a |
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Answer» Distance between points (a, b)and (-a, - b)= sqrt[(-a - a)^2 + (-b - b)^2]= sqrt[(-2a)^2 + (-2b)^2]= sqrt(4a^2 + 4b^2)= 2sqrt(a^2 + b^2) |
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| 40. |
N umb s Ol!) Joums , In He e xpansion 0b,J'OI\om!âa,L (3-%')'(0_)4}_. T |
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| 41. |
LOL.Find the points on the Curve ay+4=0 at which thetangents are inclined at angle of 450 with the x-axis. |
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| 42. |
he perimeter of a square plot 360 m. Find(i) its area.(i) cost of fencing its boundary at the rate of R 40 per met(ii) cost of levelling the plot at 60 per square metre.0 per metre. |
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| 43. |
20. The circumference of a circular park is 660 m. A 7 m wide path surrounds it. Findof fencing the outer boundary at the rate of t 60 per metre. |
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Answer» 2πr=660so,r=660/2πso,r=105so outer radius=105+7=112so circumference=2π×112=(2×22×112)/7=704m^2so per metre square cost Rs60so704meter square =704×60=Rs42240 |
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| 44. |
If at-by-cz and b2-ac, prove that2xz |
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Answer» A^x= b^y = c^z , from this if we like to express A & c in terms of b —- A^x = b^y, => A = b^(y/x) , similarly , as c^z = b^y Therefore , c = b^(y/z). It is also given that —— b^2 = Ac, or,b^2 = {b^(y/x)}*{b^(y/z)} ( putting the value of A & c defined in terms of b ) Or, b^2= b^(y/x+y/z) or, b^2 = b^{( yz +xy)/xz } or, (xy + yz)/xz =2 (as base on the both side equals (b) , power is equal) or, xy + yz = 2xz or, y(x+z) = 2xz So,y = 2xz/(x+z) |
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| 45. |
If a-b ce and beac, prove that2xz |
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| 46. |
If one angle of triangle is 15° more than its second angle. The third angle is 25more than double the second angle. Find the three angles of the triangle. |
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Answer» st angle =x2 nd angle =2x-153 rd angle =2x-15+20 so,x + 2x-15+2x-15+20=1805x-10=1805x=190x=382x-15=612x-15+20=81 |
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| 47. |
of the trnangle is Bmination in which one-fifth of the whole plusminus 25the remaining 60 candidates failed, find the total number of candidatesAcertain number ofcandidates appeared for an examination m which ore-ärst division, one-fourth plus 15 secured second division and one-fourth |
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| 48. |
Ex. 1. 15 chests of tea, each chest containing 20 kg costs R 350. What will be the price at this rate of 12chests each containing 25 kg? |
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| 49. |
40. A certain number of candidates appeared for an examination in which one-fifth of the whole plus16 secured first division, one-fourth plus 15 secured second division and one-fourth minus 25secured third division. If the remaining 60 candidates failed, find the total number of candidatesappeared. |
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Answer» Let total number of candidates be Xso candidates who secured first Division=1/5x+16second division=1/4x+15third division=60-1/4x+25so, X=1/5x+16+1/4x+15+60-1/4x+25X=1/5x+1164/5x=116X=145 |
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| 50. |
AT R हि~43 BBकि 3(5- |
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