Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
30. If sec θ + tan θp, then find the ualue of cosec θ |
|
Answer» Secθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) |
|
| 2. |
1. A man invests Rs. 4,000 in shares each of Rs. 10. He sells them whentheir cost becomes Rs. 12. Find his profit. |
| Answer» | |
| 3. |
A man invests 9600 on 100 shares atcompany pays him 18% dividend, find:(i) the number of shares he buys.(ii) his total dividend.80. If the |
| Answer» | |
| 4. |
+8-0(a " 0) by the method of completing the square. |
| Answer» | |
| 5. |
\left. \begin{array} { l } { 3 + 5 + 6 = 151872 } \\ { 5 + 5 + 6 = 253094 } \\ { 5 + 6 + 7 = 303585 } \\ { 5 + 5 + 3 = 251573 } \\ { \text { Then } } \\ { 9 + 4 + 7 = ? ? ? ? ? ? } \end{array} \right. |
|
Answer» The number would (a×b),(a×c),{(a×b)+(a×c)-c} reverse. using this technique,to get answerSo for 1st one: 3+5+6=151872axb = 3×5 = 15; axc = 3×6 = 18{(a×b)+(a×c)-c} = ((3×5)+(3×6)-6} = 27— Reverse of 27 is 72So 9+4+7=.................axb = 9×4 = 36axc = 9×7 = 63{(a×b)+(a×c)-c} = ((9×4)+(9×7)-7} = (36+63-7)=92 —>Reverse of 92 is 29.Hence 9+4+7 = 36632 |
|
| 6. |
A man invests 9600 on 100 shares at R 80. If thecompany pays him 18% dividend, find:(1) the number of shares he buys.(ii) his total dividend. |
|
Answer» thanks |
|
| 7. |
[ \{ \frac { - 5 } { 6 } \} ^ { 4 } \times \{ \frac { - 5 } { 6 } \} ^ { 6 } ] \div ( \frac { 25 } { 36 } ) ^ { 3 } |
| Answer» | |
| 8. |
t-b 0% 5 6| 5-76 x 6 - + |
|
Answer» C 3/2 and-1/3 answers... 6x^2-7x-3=6x^2-9x+2x-33x(2x-3)+1(2x-3)=(2x+3)(3x+1) (2x-3)(3x+1) is the correct answer of the given question x=2/3 and x=-1/3 ans. |
|
| 9. |
5 x ^ { \frac { 5 } { 6 } } \times 6 x ^ { \frac { 1 } { 6 } } |
| Answer» | |
| 10. |
ŠThe ama of a square ü 59536 Squan mitrufind the tingth of its side |
|
Answer» Given, Area=59536m^2 S^2 =59536m^2 S =√59536m^2 S =244mTherefore, length of side =244m |
|
| 11. |
2.remaindlen i 32%Ahat are the values of a b. Ama,o)uoHentis 지ате |
| Answer» | |
| 12. |
show that the cube of any positive imtegerte or the form am amt) or ama 8 for someinteres m |
|
Answer» Let a be any positive integer and b = 3 a = 3q + r, where q ≥ 0 and 0 ≤ r < 3 ∴ r = 0,1,2 . Therefore, every number can be represented as these three forms. There are three cases. Case 1: When a = 3q, Where m is an integer such that m = Case 2: When a = 3q + 1, a = (3q +1) ³ a = 27q ³+ 27q ² + 9q + 1 a = 9(3q ³ + 3q ² + q) + 1 a = 9m + 1 [ Where m = 3q³ + 3q² + q ) . Case 3: When a = 3q + 2, a = (3q +2) ³ a = 27q³ + 54q² + 36q + 8 a = 9(3q³ + 6q² + 4q) + 8 a = 9m + 8 Where m is an integer such that m = (3q³ + 6q² + 4q) Therefore, the cube of any positive integer is of the form 9m, 9m + 1, or 9m + 8. Hence, it is proved . |
|
| 13. |
21. If x=a+4a2-1, then a is equal to2 x2 x22. If ama a", then find the value of m(n- 2)+ n(m-2).(A) 3(B) 2 |
|
Answer» thanks you |
|
| 14. |
an examination are 1200 and a candidate has to secure 36%innation. If a student failed by 15 marks, find the marks securedUl lTDn in the alloy.10. The maximum marks ofexaminaby him.11. Ama |
|
Answer» thank you |
|
| 15. |
13 9 6 5 6 9Word Problems or Addition:3. A man purchased a land for Rs 3540290. He spent Rs 19657600 in establishing afactory and Rs 516389 on the decoration of the office. How much did he spend in all4. A cloth mill made 2533288 m, 2635160 m and 2395290 m of cloth in three yearsrespectively. How much cloth did it make in all the three years? |
|
Answer» price of land= 3540290 rshe spent in establishing a factory =19657600 rshe spent on decoration = 516389 rshe spent in all = 473142 7 9 Price of land= 3540290 rshe is spent in establishing a factory = 19657600rs he spent on decoration= 516389rs he spent in all= 2,37,14,279 23,714,279 is the answer of this question |
|
| 16. |
lving by completing6quare method |
|
Answer» Please hit the like button if this helped you |
|
| 17. |
10. By using the method of completing the squaresreal roots.of completing the square. Show that the equation 4x + 3x + 5 = Ohas no(NCERT |
| Answer» | |
| 18. |
find the ualuecompleting-aquare method |
| Answer» | |
| 19. |
* - 5x + 5= 0method of 'completing the |
|
Answer» In our case,A= 1B= -5C= 5 Accordingly,B2-4AC=25 - 20 =5 Applying the quadratic formula : 5 ± √5x=————2 x^-5x+5=0A=1 B=-5 C=5 -b^+wruteover b^-4ac by 2a =)-(-5)+-wruteover -5^-4×1×5 by 2×1 =)25+-wrutover 25×5 by 2 =)25+-wruteover 125Either 25+wruteover 125 by 2Or25-wruteover 125 by 2 |
|
| 20. |
solve by completing square methodx2 + 11x +2450 |
|
Answer» x ka square+11x+24=0x ka square+(8+3)x+24=0x ka square+8x+3x+24=0x(x+8)+3(x+8)=0(x+8)(x+3)=0x=-8,-3 answer |
|
| 21. |
1.5äş0bolying-by, completing6quore method |
|
Answer» Please hit the like button if this helped you |
|
| 22. |
fe in ० = Cos 8 और 0°<8 <90°, तव sin 8 और cos B के मान बताये ।। |
|
Answer» SinФ = cosФsinФ/cosФ = 1tanФ = 1tanФ = tan 45°Ф = 45 sinA=cosAsinA= sin(90-A)A=90-A2A= 90A= 45cosAcos45=1/√2 sinx= cosx; sinA= sin(90-A); A=90-A, 2A=90, A=45, cosA= cos45=1/V2 |
|
| 23. |
ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If DBCz70BAC is 30°, find < BCD. Further, ifAB-BC, findECD. |
| Answer» | |
| 24. |
tfsinA'; and sin B Tİ. find the values of cos A and cos B Hence using theformula cos (A+ 9) - caS A cos 8-sinA sih 8, show that (A + 8)-45 |
| Answer» | |
| 25. |
\cos 8^{\circ}-\sin 8^{\circ} / \cos 8^{\circ}+\sin 8^{\circ}=\cot 53^{\circ} |
|
Answer» sin8 + cos8 / sin8 - cos8=1 + cot8 / 1 - cot8= 1 + cot45 cot8 / cot45 - cot8= cot (45-8)= cot37= 1 / tan37=tan37= tan( 90 - 53)= cot 53 |
|
| 26. |
f. ABCD is a cyclic quadrilateral whose diagonals intersect at a point EDBC70BAC is 30°, find ZBCD. Further, if AB-BC, find ZECD. |
| Answer» | |
| 27. |
Solve by completing square method : 6x2 - 3x + 4 = 0 |
| Answer» | |
| 28. |
s a cyclic quadrilateral whose diagonals intersect at a point E. If Z DBC-70,2 BAC is 30°, findBCD. Further, ifAB = BC, find < ECD. |
|
Answer» no idea😊 ankita mallick |
|
| 29. |
ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. 112 DBC= 700< BAC is 30°, find < BCD. Further, ifAB = BC, find < ECD., |
| Answer» | |
| 30. |
6.ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. lfLDBC=70BACis 30. find ZBCD. Further, if AB BC, find ZECD |
| Answer» | |
| 31. |
ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If ZDBC-70BAC is 30°, find 2 BCD. Further, ifAB BC,find ZECD.6. |
| Answer» | |
| 32. |
How much would a sum of16000 amount to in 2 years time at 10% per annum compound interest, interest being payable half-yearly? |
|
Answer» ci = p(1+r)^nhere r= 0.1/2 = 0.05 since compounded half yearlyn = 4 for 2 years ci = 1600(1+0.05)^4ci = 1600 (1.05)^4ci = 1944.81 rupeesans. |
|
| 33. |
15. ABCD is a cyclic quadrilateral whose diagonals intersect atP. If < DBC = 80° and < BAC = 40°, then < BCD =(A) 40°(C) 60。(B) 90°(D) 120° |
| Answer» | |
| 34. |
In 12% per annum compoundinterest if some principal in 2 yearshas become P3,136 with interest,then the principal will be |
|
Answer» A= P(1+r/100)^n3136= P(1+12/100)^23136= P(112/100)^23136= P(1.2544)P= 2500 |
|
| 35. |
Find g.c.d of 736 and 85 by using Euclid's algorithm. |
| Answer» | |
| 36. |
How much would a sum of Rs. 16000 amount to in 2 years at 1 0% per annum compoundinterest, interest beingpaid halr yearly |
|
Answer» questions no.5 can you please write in detail because we have to write in detail |
|
| 37. |
I borrowed 12,000 from Jamshed at 6% per annum simple interest for 2 yearsHad I borrowed this sum at 6% per annum compound interest, what extra amountwould I have to pay? |
| Answer» | |
| 38. |
In the given figure, AB||CD, angleABO=40°angleCDO=35°.Find the value of the reflexangleBOD and hence the value of x. |
|
Answer» just draw a line parallel to both lines and passing through O. then the value of angle reflex BOD = 40°+35° = 75° so, x = 360-75° = 285° |
|
| 39. |
. Given that cose = , then the value of taneis-Given that cos 8 = |
|
Answer» Cos Φ=a/btherefore B/H=a/bB=a, H=bNow using pythagoras theoremH²=P²+B²b²=P²+a²P²=b²-a²P=√(b²-a²)thereforeTanΦ= P/B =√(b²-a²)/a tanx=√b²-a²/a is trigonometric ratio |
|
| 40. |
14 7N ÂŁ }h} |
|
Answer» yas |
|
| 41. |
(i) 10² - 992 |
|
Answer» 100-9801-9701 is correct answer 9701 is write answers this question 1000-9801=-199i hope you need this answer so, 10 * 10 - 99 * 99= 100 - 9801= - 9701 -9701 is the right answer according to your question -9701 is the right answer -9701 is the correct answer of this question like a2-b2(10+99)(10-99)109*(-89)-9701 9701 is the correct answer of a question -9701 is the correct answer |
|
| 42. |
1. Which of the following numbers are divisible by 2?57, 34, 60, 93, 126, 365, 890, 992 |
|
Answer» 34 60 126 890 and 992. 34 60 126 890 992 |
|
| 43. |
If the quadratic equation 8 x^{2}-2 \sqrt{5} p x+15=0 has two equal roots, then find the value of p. |
| Answer» | |
| 44. |
) the cost of plastering the mùèr curved sunace al lal U4.8 cm. Find the (i) inner curved surface area (ii) outer curved surface area (ii) total surface areafrom both sides (inside as well as outside) at 2 per m2 if length is 3.5 m.8. A metal pipe is 77 cm long, the inner diameter of the cross-section is 4 cm and the outer diameter 1s9. A hollow cylindrical pipe has inner circumference 44 dm and outer 45 dm. Find the cost of painting it |
|
Answer» 9)Inner circumference = 44dm = 4.4mouter circumference = 45dm = 4.5 mlength = 3.5minner CSA = 4.4×3.5 = 15.4 m²outer CSA = 4.5×3.5 = 15.75 m²total = 15.4 + 15.75 = 31.15 m²cost = Rs. 2 per m²total cost = 31.15×2 = Rs.62.30 |
|
| 45. |
8?Find the roots of the Quadratic equation x + 2x - 3 = 0.bu |
| Answer» | |
| 46. |
5982 +1345 + 736-? = 4588 + 992 |
| Answer» | |
| 47. |
FACE AREAS5. It costs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. Ilfthe cost of painting is at the rate of R 20 per m2, find(0) inner curved surface area of the vessel,(ii) radius of the base,(ii) capacity of the vessel |
| Answer» | |
| 48. |
Into a cyinder arong its es21 m and14 m respectively. Find the cost of renovating the inner curved surface acurved surface at the rate of 3 25 per m.11. A cylindrical well is 21 m deep. Its outer and inner diameters are |
|
Answer» inner C.S.A =2×(22/7) ×(14/2)×21=924m^2outer C.S.A=2×(22/7)×(21/2)×21=1386m^2total area=1386+924=2310m^2total cost=2310×25=Rs57750 wrong answer.answer is 57750 |
|
| 49. |
Solve 7x2-30-25-0 by completing square method. |
| Answer» | |
| 50. |
x square - 4 x + 1 is equal to zeroby using completing square method |
|
Answer» x square-4x+1=0x sq - 4x+1+2 sq =0+2 sq(x-2) whole sq +1=4 |
|