fe in ० = Cos 8 और 0°<8 <90°, तव sin 8 और cos B के – InterviewSolution

1.

fe in ० = Cos 8 और 0°<8 <90°, तव sin 8 और cos B के मान बताये ।।

Answer»

SinФ = cosФsinФ/cosФ = 1tanФ = 1tanФ = tan 45°Ф = 45

sinA=cosAsinA= sin(90-A)A=90-A2A= 90A= 45cosAcos45=1/√2

sinx= cosx; sinA= sin(90-A); A=90-A, 2A=90, A=45, cosA= cos45=1/V2

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