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in first quadrant sin and cos equal when x = 45

Let breadth=x mLength=x+12 mArea=Perimeterlength*breadth=4*2(length+breadth)x(x+12)=8(x+x+12)x(x+12)=8(2x+12)x²+12x=16x+96x²-4x-96=0x²-12x+8x-96=0x(x-12)+8(x-12)=0(x-12)(x+8)=0x=12,-8

So breadth=12 mlength=24 m

Use formula Kp=Kc(RT)ⁿ

where n is difference of moles between product side - reactant side

N2+3H2----->2NH3

n=2-3-1=-2

Kp=Kc(RT)-²

Kp=6×10-²(0.0821×773)-²

Kp=6×10-²/(0.0821×773)²

Kp=6×10-²/(63.46)²

Kp=6×10-²/(4027)

Kp=1.5×10-5 (Ans)

thank u so much for your precious help

. THE CAR HAS TWO WIPER S

. LET THITA BE ' ' SO

. THE LENGTH OF WIPER . = 25 CM = R

. WHICH IS RADIUS

. THEN

. THE TOTAL AREA CLEANED

. = 2 { / 360 * p R ² }

. 2 { 115 / 360 * 22 / 7 * 25 * 25 }

. 2 { 23 / 72 * 22 / 7 * 625 }

. 23 / 36 * 22 / 7 * 625

. 23 / 18 * 11 / 7 * 625

. 1254 . 96 CM ²

right answer thank you

Surface area of sphere = 4πr^2therefore A/Q4πr^2 = 346.5r^2 = 213444r = √213444 = 462 cm

volume = 4πr^3 /3=(4*22/7*462*462*462) /3= 413227584 cm^3

SaReGaMaPhaDhaNi

🎼Sa🎵Re🎶Ga🎶Ma🎵Pa🎼Dha🎵Ni🎼is the best answer.

After putting x= -1/2we can get it as5*(-1/2)^2-4(-1/2)^3+3(-1/2)+1

5/4+4/8+3/2+1= 2/4= 1/2

not define as tan (90°) is not defined

tan 15° × tan 60 ° × tan 75°cot (90 ­- 75)° × tan 60° × tan 75°cot 75° × tan 60° × tan 75°_1_ × tan 60° ×° tan 75°tan 75

tan 60° = √3

Please check the misprinted last angle is 75° not 70°.

Note : value of tan 70° cannot be found analytically, but it's approximate value is

tan(70°)=2.74747.

For eq x^2 - 4root(3)x + 3 = 0alpha and beta are zeroes.

Then,alpha + beta = 4root(3)alpha * beta = 3

Therefore,Value of (alpha + beta - alpha*beta)= 4root(3) - 3

If x=0 and x=-1 are the root of the polynomial f( x) =2×3-3×2+a×b

If we consider any right angled triangle ADB, we havebase=BD=a,

perpendicular=AD=√3a,

hypotenuse=AB=2a and∠ABD=60°

tan60°=AD/BD=√3a/a=√3.

The values of the trig functions of 30° and 60° can be written like this:(15) sin 30° = ½, sin 60° = (√3)/2. cos 30° = (√3)/2, cos 60° = ½

1/2 answer is the right answer

CP = 2850 LOSS = 15% SP = 2850*0.85 = 2422.5

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5x+2x+12==7x+12; 7x=-12, x=-12/7

high and low for a rare? r and got a new phone and lost all my contacts

5 x + 2 X + 12 = 7 x + 12;7x=-12,X=-12/7

answer is 4 for your question

Let r is radius of sphereThen,Volume of sphere v = 4/3*pi*(r)^3

If radius is increased by 5 % then r1 = r(1 + 5/100) = 21r/20

Then volume of sphere will become v1 = 4/3*pi*(21r/20)^3= 4/3*pi*(1.157 r^3)

Therefore, Percentage increase in volume = [(v1 - v)/v]*100= [(4/3*pi*(1.157r^3) - 4/3*pi*r^3) /4/3*pi*r^3] * 100= (1.157 - 1)*100= 15.7%

the Answer is 8 of this question

76 is correct answer.



Secondary School

Math13 points

Average of 10 matches is 32 how many runs one should score to increase his average by 4 runs

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FollowReportbyGurpreet367309.11.2018

Answers

Me·Beginner

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riya1000

Expert

Average of 10 matches = 32 runs

So, total runs = Average runs * Number of matches

= 32 * 10

= 320 runs

If average was of 4 more runs, then average = 32 + 4 = 36 runs

So, total runs = Average runs * Number of matches;

= 36 * 10 ( as the number of matches remains the same)

= 360 runs

Difference in total runs = 360 - 320 = 40 runs

Answer: 40 more runs should be scored in order to increase the average by 4 runs. OR 360 runs should be scored in order to increase the average runs by 4 runs.

Hindi me Question Dalo

Ali Share = [80/300 ]*100= 80/3 %

Abdul share = [120/300]*100= 40 %

Avi share = [100/300]*100= 100/3 %

Now, Total profit = 900

Ali Share in profit= [900 * 80/3]/100= 300*80/100= Rs 240

Abdul Share in profit = [900 * 40]/100= Rs 360

Avi Share in profit = [900 * 100/3]/100= Rs 300

5x + 35 + 45 = 180 5x + 80 = 180 5x = 100 x = 20

Cost price of TV CP= 6000

LOSS = 15%

Therefore,Selling price of TV= 6000(1 - 15/100)= 60*85= Rs 5100

thx

36+50+29+91=206 is right answer

when we add 36+50+29+91= 206

206 is the right answer

206 is the right answer.

206 is right answer of this question

36+50+29+91=206your answer is 206.

0.5gm/cc is 0.5 × 10-3 kg/ (10-2)3 m3

therefore, 0.5 × 10-3+6 kg/ m3 =0.5 × 103 kg/ m3=500 kg/ m3

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cosec= 1/sinsec= 1/cosso 1/sin^2-1/cos^2

= cos^2-sin^2/cos^2sin^2

now tan = P/B= 13/1H= √(13^2+1^2)√170now sin= P/H= 13/√170cos= B/H= 1/√1701/170-13/170/(13/170)-12/170/13/170

= -12/13

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1.Area is 1/2 base * height . So for the same triangle area can be 1/2*b*a and can be 1/2*p*c. Hence cp = ab

2 . From above p2 = a2b2/c2

1/p2 = c2/ a2b2

but for right triangle c2 = a2 +b2

Hence 1/p2 = (a2+b2)/ a2b2

Hence 1/p2 = 1/a2+1/b2

thank you