The reaction between N2 and H2 to form ammonia hasK. = 6 × 10-2 at th

1.	The reaction between N2 and H2 to form ammonia hasK. = 6 × 10-2 at the temperature 500°C. The numericalvalue ofK for this reaction is
Answer» Use formula Kp=Kc(RT)ⁿ where n is difference of moles between product side - reactant side N2+3H2----->2NH3 n=2-3-1=-2 Kp=Kc(RT)-² Kp=6×10-²(0.0821×773)-² Kp=6×10-²/(0.0821×773)² Kp=6×10-²/(63.46)² Kp=6×10-²/(4027) Kp=1.5×10-5 (Ans) thank u so much for your precious help

The reaction between N2 and H2 to form ammonia hasK. = 6 × 10-2 at the temperature 500°C. The numericalvalue ofK for this reaction is

Answer»

Use formula Kp=Kc(RT)ⁿ

where n is difference of moles between product side - reactant side

N2+3H2----->2NH3

n=2-3-1=-2

Kp=Kc(RT)-²

Kp=6×10-²(0.0821×773)-²

Kp=6×10-²/(0.0821×773)²

Kp=6×10-²/(63.46)²

Kp=6×10-²/(4027)

Kp=1.5×10-5 (Ans)

thank u so much for your precious help