Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

((2/5)*(3*(2/4)))/((7/10))

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49/17 is right answer....

49/17 is the right answer

49/17 is the correct answer of the given question

2.

20. (i) Prove that the points (2,3), (-2, 2), (-1,-2) and (3,-1) are the vertices of aICBSE 2013](ii) Prove that the points (1,7), (4,2), (-1,-1) and (-4,4) are the vertices of asquaresquare.

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3.

Arrange in descending order3 4 75 7' 10

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Take LCM of 5,7,10 = 70(3/5)*70=42(4/7)*70=40(7/10)*70=49Ascending order:(40,42,49): 4/7, 3/5, 7/10

4.

17. A solid cone of base radius 10 cm is cut into two parts through themidpoint of its height, by a plane parallel to its base. Find the ratio ofICBSE 2013]the volumes of the two parts of the cone.

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5.

Example 2 If cos θ + sec θ2, the value of cos 6 θ + sec 6 θis(a) 1(b) 2(c) 4(d) 8

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6.

10. The lengths of the diagonals of a rhombus are 24 am and 1srespectively. Find the length of each side of the thombus.ˋ-chuc 1s 10cm long and one ofits diagonas measuresd hence find the area of

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7.

Find the area of the quadrilateral ABCbHere, AC 22 cm, BM-3 cm,DNisa3 cm, andm BM LAC, DN LAC3cmnd:of

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8.

3. If the volume of a cube is 3V3 a3, then find itsICBSE 2011, 2013] (1)total surface area.

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9.

Find x such that 1S andequivalent numbers.-15are

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When equivalent,

-15/7 = x/21

x = ((-15) × (21))/7

x = -15 × 3

x = -45

10.

17. Find a cubic polynomial with sum of ts zeroes is 5sum of theprodcts of ts aeroes taken beat a time is-7 and product of its zeroes is- 4

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Let α, β and ɣ be the roots of the cubic polynomial

Given (α + β + ɣ) = 5/2(αβ+ βɣ + ɣα) = - 7 and (αβɣ) = - 4

The cubic polynomial with roots α, β and ɣ is x^3 - (α + β + ɣ)x^2 + (αβ+ βɣ + ɣα)x - (αβɣ) = 0 x^3 - (5/2)x^2 + (- 7)x - (- 4) = 0 2x^3 - 5x^2 - 14x + 8 = 0

11.

hourus 40 miutes Find ts gpes

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The distance covered is 850KMand in doing that , the time taken by the car is 10 hrs 40 minutes that is 10hrs + 40/60hrs = 10+2/3 = 32/3

so speed = distance/time =850/(32/3) = 79.68Km/h that is equal to 80km/h

12.

LasmalgJ-1s. Find the value of a'

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13.

solve by Cramer,ule

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1st

2nd

14.

Example 2 : Find five rational numbers between 1 and 2.

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5/4 ,11/8 ,13/8and11/6

15.

Example 2 : Find five rational numbers bctween I and 2

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16.

Example 2: Simplify

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If you find this solution helpful, Please like it.

17.

Iidles4-an.isodeles t innalo-LA-Th rn. Jasatha 4-trote.the-lengthー4-theFind the dimentons of theㄧ

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18.

Example 2: Multiply:1224

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(4a²b - 3ab³) × ( a²/12 + 5b²/24)

a⁴b/3 + 5a²b³/6 - a³b³/4 - 5ab^5/8

tnx

19.

4 7 103. Find th and the sum to n terms of 15 52.5

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13/5⁴'16/5⁴..............

20.

\Delta=\left| \begin{array}{ccc}{1} & {\omega} & {\omega^{2}} \\ {0} & {\omega^{2}} & {1} \\ {\omega^{2}} & {1} & {\omega}\end{array}\right| where omega is a non-real cube root of unity.

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21.

EXAMPLE 2 Solve:= a + b

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x=a^2 and y=b^2 answers.

22.

Example 2 Find the following integrals:

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23.

-6example 2. Add17and

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-6/5 + 17/25

= -30 + 17-------------------- 25.

-13 = -------- 25

24.

EXAMPLE 2 Expressas a decimal fraction.

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25.

Example - 2. Prove the followings(i) cottan2

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26.

\left. \begin{array} { l } { \text { The value of } \frac { a + b \omega + c \omega ^ { 2 } } { c + a \omega + b \omega ^ { 2 } } = } \\ { 1 \quad b ) \omega } & { c ) \omega ^ { 2 } } \end{array} \right.

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(a+bw+cw^2) = a + bw + c/w (as w^2 = 1/w) = 1/w(aw+bw^2+c)

So (a+bw+cw^2)/ (c+ aw+bw^2 ) = 1/w = w^2

27.

\begin{array}{l}{\text { If } 1,\omega, \omega^{2} \text { are the cube roots of unity, }} \\ {\text { then } P . T . \frac{1}{1+2 \omega}+\frac{1}{2+\omega}=\frac{1}{1+\omega}}\end{array}

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28.

( 1 - \omega + \omega ^ { 2 } ) ^ { 25 } + ( 1 + \omega - \omega ^ { 2 } ) ^ { 25 }

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29.

1, ω, ω2 are the cube roots of unity, then\left| \begin{array}{ccc}{1} & {\omega^{n}} & {\omega^{2 n}} \\ {\omega^{n}} & {\omega^{2 n}} & {1} \\ {\omega^{2 n}} & {1} & {\omega^{n}}\end{array}\right| is equal to

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thanku so much gomati 😘

30.

( 1 + \omega ) ( 1 + \omega ^ { 2 } ) ( 1 + \omega ^ { 4 } ) ( 1 + \omega ^ { 8 } )

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31.

1 हो, तो \left| \begin{array}{cc}{a} & {\omega} \\ {\omega} & {-\omega}\end{array}\right|=1 का मान ज्ञात कीजिए ।

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a= 1as 1+w+w^2=0

32.

18A straight highway leads to the foot of a tower of height 50m. From the top of a tower,the angles of depression of two cars standing on the highway are 30° and 60o. What isthe distance between the two cars and how far is each car from the tower ?

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thank you

33.

Find the radius of the cone if the height and the slant height of a cone are 21 crmand 28 cm respectively

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By Pythagoras theorem,(slant height)² = (radius )² + ( height)²⇒radius² = (28)² - (21)² = (28 +21) (28- 21) = 49× 7radius = 7√7 cm

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34.

A man donates 10 aluminium buckets to an orphanage. A bucketof height 20 cm and has its upper and lowest ends of radius 36 crmFind the cost of preparing 10 buckets if the cost of aluminiumWrite your comments on the act of the man.made of aluminium isand 21 cm respectivelysheet is ? 42 per 100 cm228.

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Answer:

Rs 4950

Step-by-step explanation:

Find the surface area of 1 bucket:

Surface Area = π(R - r)√[(R - r)² + h²]

Surface Area = π(36 - 21)√[(36 - 21)² + 20²]

Surface Area = 375π cm²

Find the surface area of 10 buckets:

1 bucket = 375π cm²

10 buckets = 375π x 10 = 3750π cm²

Find the cost:

100 cm² = Rs 42

3750π cm² = 42/100 x 3750π = Rs 4950

Answer: The cost is Rs 4950

35.

How many silvercoins, 1.75 cm in diameter and of thickness 2 mm, must be melted to forma cuboid ofdimensions 5.5 cm × 10 cm x 3.5 cm?

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36.

A car is running on a highway at a constant speed.of gokm/he find:a The distance travelled by the car in the comintaken by the car to covena distance of 5uokmb) Time taken by the care

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a=105,b= 6 is the answer

a=105 and b=6 is the correct answer of this question

a=105 b=6 is the correct answer of the given question

a) 105 kmb) 6 h is correct answer.

37.

. Find th4 is 2, calculate thevalue ofxThe mean of 1, 2, x, 3 and

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38.

13. Find ths of the following polynomial: 5M1+2 1x+8.5

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39.

A highway leads to the foot of 300 m high tower. An obeservatory is set at the top of the towerIt sees a car moving towards it at an angle of depression of 300. After 15 seconds angle ofdepression becomes 60°. (a) Find the distance travelled by the car during this time. (b) How thisobservatory is helpful to regulate the traffic on the highway?

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40.

A highway leads to the foot of 300 m high tower. An obeservatory is set at the top ofthe towerIt sees a car moving towards it at an angle of depression of 30°. After 15 seconds angle ofdepression becomes 60, (a) Find the distance travelled by the car during this time. (b) How thisobservatory is helpful to regulate the traffic on the highway?

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41.

A rectangular sheet of paper is 12-crm long and 10二cm wide.2-cm2meind its perimeter

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42.

The minute hand of a clock is 10 cm long. Find the area of the face of the clock described by the minute hand210.between 10: 20 AM to 10:35 AM.10 crm引M召10:35 AM襾卿殉何

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43.

be filled with ice cream.How many silver coins, 1.75 cm in diameter and of thickness 2 mm, must be melteda cuboid of dimensions 5.5 cm x 10 crm x 3.5 cm?

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44.

Findthe area of the following circles; given that:2.(a) radius = 14 mm (Take π=-)(b) diameter = 49 m(c) radius5 cm

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45.

15,000 to run a business frong, the interestm a bank atI1. Two friends together took a loan amount ofrate of simple interest of 12% per annum. Let us write, by calculatito pay after 4yrs.

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Given P = 15000, R = 12%, T = 4 years

SI = P*R*T/100 = 15000*12*4/100 = 150*48 = 7200

Therefore, interest they have to pay after 4 years = Rs 7200

46.

Find the area of the following circles, that radius= 3.14 mm, diameter = 49 cm and radius = 5 cm

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47.

the circumference of the circles, given that:(a) radius 21 mml. Find the circ(b) diameter 14 cm

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1. circumference = 2pir

a) 2pir = 2× 3.14 × 21 mm = 131.88mm

b) r = d/2 = 14 cm/2 = 7

2pir = 2× 22/7 × 7 = 44cm

48.

The diameter of a cycle wheel is 21 cm. How many revolutions will it make to travel 1.98km?inn 1 75 m in diameter and 2 mm thick must be melted to form a cubcid of dimer

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Number of revolutions = Total distance / Circumference of circle= (1.98*100000) / (2*(22/7)*21)= 198000 / 132= 1500 revolutions.

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49.

EReTFCTS1. Find th2. Find the aree circumference of the circles, given that: (a) radius = 21 min (b) diameter =20 cm (b) diameter 42 cma of the circles. given that: (a) radiusCim

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50.

ALI 25. K, L, M and N are points on the sides AB, BC, CD and DA respectivelyofa square ABCD such that AK BL CM DN. Prove that KLMN is asquare.

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