1.

\left. \begin{array} { l } { \text { The value of } \frac { a + b \omega + c \omega ^ { 2 } } { c + a \omega + b \omega ^ { 2 } } = } \\ { 1 \quad b ) \omega } & { c ) \omega ^ { 2 } } \end{array} \right.

Answer»

(a+bw+cw^2) = a + bw + c/w (as w^2 = 1/w) = 1/w(aw+bw^2+c)

So (a+bw+cw^2)/ (c+ aw+bw^2 ) = 1/w = w^2



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