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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
7. A man said to a lady, “Your mother's husband'ssister is my aunt". How is the lady related tothe man?A. DaughterB. Grand daughterC. MotherD. SisterToaसंबंप्तिA.B.8. Today is Monday. After 61 days, it will beA. WednesdayB. SaturdayC. TuesdayD. Thursday9. If it takes two workers, working separately but atthe same speed, 2 h and 40 min to complete a |
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Answer» Today is Monday after 61 day is Saturday |
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| 2. |
7. Express the matrixlo sit: 2]andtas the linear comibination of the matriees10 3) |
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(D)6464. Pointing to a lady, a man said. "The son of her onlybrother is the brother of my wife." How is the ladyrelated to the man?(A) Mother's sister \B) Grandmother(C) Mother-in-law (D) Sister of father-in-law65. Find correct replacement for "?"18 243265 |
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Answer» pointing to a man a girl said he is the only son in law of the grandfather of my mother's only daughter how is the man related to brother for their uncle or son |
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| 4. |
3 x+4 y=10 \quad \text { sit } \quad 2 x-2 y=2 |
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| 5. |
24. Tて(x+y):(x-)) = 4 : 1頁,하 (x2 +y2 ) : (x2-y2)=? |
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Answer» x+y=4x-4y5y=3xso x=5y/3(25y^2/9+y^2)/(25y^2/9-y^2)=34y^2/16y^2=17/8 |
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| 6. |
a = 10 , \quad d = 10 |
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Answer» AP will be a(n) = a + (n-1)da(n) = 10 + (n-1)10a(n) = 10 + 10n -10 = 10nAP is 10, 20 ,30, 40..... |
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| 7. |
The mean proportional between 45 and acertain number is three times the mearproportional between 5 and 22. Thenumber is |
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| 8. |
4 weeks andThe table below shows the number of miles Me Searth dreng for enchamount of as his causedMr. Smith's TripGas used igallons) 105Distance Traveled (miles) 184.8 115.572161. 4 6.8Which statement correctly describes whether the cable represents a proportional relationshipfor the number of miles traveled and the amount of gas used?A. The relationship is proportional, because for each column, the ratio is the same.B. The relationship is proportional, because for each column, the ratio is not the same.C. The relationship is not proportional, because for each column, the ratio is the same.D. The relationship is not proportional, because for each column, the ratio is not the same. |
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Answer» the relationship is not proportional,because for |
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| 9. |
% ?What number should be added to 6, 15, 20 and 43 to make the numbers anproportional. |
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Answer» Let us add, say x to all the four numbers, (6+x):(15+x) = (20+x):(43+x), or (6+x)(43+x) = (15+x)(20+x), or 258 + 49x + x^2 = 300 +35x + x^2, or 49x-35x = 14x = 300–258=42, or x = 3. So you need to add 3 to 6, 15, 20 and 43 to make them 9:18 ::23:46 which in the proportion of 1:2::1:2. |
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| 10. |
(1/2 x2 + y2) (x2- 1/2 y2) |
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| 11. |
Ifx : y :: 2 : 1, then (x2-y2) : (x2 + y2)-?'(A) 3:5(B) 5:3 |
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| 12. |
22.The angle of elevation of a cloud from a point 60 metres above a lake is 30째 and theangle ofdepression of its reflection of the cloud in the lake is 60째. Find the height ofthe cloud. |
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| 13. |
a Find the equations to the common tangents of the circles x? + y2 - 2x-6y+ 90 andx2 + y2 + 6x-2y + 10 |
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Answer» thanks |
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| 14. |
1.The price of a music system is 23,000.The sales tax charged on it is at the rateof 12%. Find the amount that the buyerwill have to pay if he buys it.Protein:CarbohIf she ecalorie2. TH |
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Answer» price of music system=23000rate of sales tax =12%then according to question=23000*12/100=276000/100=2760tax will be music system=2760then,, whole price of music system after tax=price plus tax =23000+2760=25760so, show the value of music system after tax=25760 25,760 rupees is the right answer |
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| 15. |
The angle of elevation of a cloud from a point 60 m above a lake is 30o andtangle of depression of the reflection of cloud in the lake is 60o. Find the heighthe cloud. |
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| 16. |
The angle of elevation of a cloud from a point 60 metres above a lake is 30째 andangle of depression of its reflection of the cloud in the lake is 60째. Find the heighthe cloud.22.thedf |
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Answer» in question given AP =60 but you AP=200 please correct answer reply |
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| 17. |
Q10. The angle of elevation of the cloud from a point 60m above a lake is 30째 andthe angle of depression of the reflections of the cloud is 60째. Find the height of thecloud above the lake. |
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| 18. |
The angle of elevation of a cloud from a point 20 m above a lake is 30 andthe angle of depression of the reflection of cloud in the lake is 60. Height ofthe cloud is given by |
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Answer» Solution : tan30∘=EC/AD=1/√3(ED=h) =>AD==h√3-----------(1) tan60∘=FD/AD=√3 FD=h+40 AD=h+40/√3---------------(2) h√3=h+40/√3 3h=h+40 2h=40=>h=20m EC=h+20=20+20 =40m |
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| 19. |
57.What will be the rate of interest if Rs. 5000 fetch Rs. 1350 as simple interest after 360.years ?(I) 5p.cpa.(3) 9 p.c.p.a.(2) 8 p.c.p.a.р.с.р.а.(4) 7 p.c.p.a. |
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| 20. |
\left. \begin{array} { l } { 21 ) \text { If } x + 2 \text { divides } 2 x ^ { 3 } - 5 x ^ { 2 } + 4 x + p \text { without remainder, P is } } \\ { a ) 44 } \end{array} \right. |
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Answer» tq |
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| 21. |
8 \quad 10 |
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Answer» LCM=lcm of (numerators)/hcf of (denominators) HCF=HCF of (numerators)/LCM of (denominators) L.C.M. of 8,10,16 = 80 H.C.F of 8,10,16 = 2 L.C.M. of 9,27,81= 81 H.C.F of 9,27,81 = 9 L.C.M. = 80/9 =80/980/9 H.C.F = 2/81 =2/812/81 The HCF of8/9,10/27,16/81=8/9,10/27,16/81=2/812/81 The LCM of8/9,10/27,16/81=80/9 |
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| 22. |
The angle of elevation of a cloud from a point 60 metres above a lake is 30° and theangle of depression of its reflection of the cloud in the lake is 60o. Find the height ofthe cloud.22. |
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| 23. |
52. Ifsinx + sin 2x=1, thencos12 x + 3 cos10 x + 3cos+ cos° x is equal toAMU, WB JEE(b) 2(d) 0(c) 3 |
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Answer» If you like the solution, Please give it a 👍 |
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| 24. |
2+3+56+64 |
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Answer» The right answer is 125 = 2+3+56+64=2+56+3+64=58+67=125The right answer is 125 |
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| 25. |
3. In Fig. 10.24, find x.20169 cm(arus)10 cm6 cmFig. 10.24 |
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Answer» 15 is the right answer ∆POB & ∆ AQO<PBO=<QAO (EACH 90°)<POQ=<AOQ(VERTICALLY OPPOSITE ANGLE)SO REKENING <BPO= <AQO WILL ALSO EQUAL.∆POB~∆AOQSO PB/AQ= BO/AO9/X= 6/106X=90X= 90/6= 15 CM = 15 is right answer |
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| 26. |
(3) 56 किमी० 8 हेमी० 5 मी० को मीटर में लिखिये। |
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Answer» (56×1000)+(8×100)+05 =56000+800+05=56805 m 56805 m is the correct answer 56805 m is the correct answer 56im 8 Hm 5mt56×1000=56000( 1km= 1000m)8Hm= 8×100= 800 m( 1Hm= 100m)total = 56000+800+5 = 560805m 1 km = 1000 mt 1Hm = 100 m56km= 56×1000= 56000 m8Hm = 8×100= 800 mtotal = 56808 mt |
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| 27. |
1. 3 का 56% बराबर है।।।। |
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Answer» answer= 25/7 *56 =200 |
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| 28. |
(n+3) !=56 .(n+1) ! |
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Answer» (n+3)(n+2)(n+1)!=56(n+1)! n*n+3n+2 = 56 n*n+3n-54 =0 (n+9)(n-6) = 0 so n-6 = 0 so n=6 |
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| 29. |
56+53/3 |
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Answer» by basic calculation(56×3+53)/3=(168+53)/3=221/3 |
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| 30. |
10JA stream goes down stream and covers the same distance upstream in Shours. If thespeed of the stream is 2km/h. find the speed of stream in still water |
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Answer» Let the speed of the steamer in still water = x km/hr ER. RAVI KUMAR ROY Speed downstream = (x + 2) km/hr Distance between two ports = 4(x + 2) km .........1 Speed downstream = (x - 2) km/hr Distance between two ports = 5(x - 2) km .........2 From equation 1 and 2, we get 4(x + 2) = 5(x - 2) => 4x + 8 = 5x - 10 =>4x + 8 + 10 = 5x =>4x + 18 = 5x => 5x - 4x = 18 => x = 18 km/hr So,the speed of the steamer in still water = 18 km/hr |
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| 31. |
11. Evaluatea.20 X 3° x (-1/2) 1 |
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| 32. |
Example 0.15 Evaluate the followingt/42(iü) J cos 2x2 + 2x) dr0 |
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Answer» put in the limitshencee^2+4-e^1+4e^6-e^4e^4(e^2-1) plz send me solution of second question |
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| 33. |
\begin{array}{l}{\text { Evaluate }} \\ {\left(\frac{2}{11}\right)^{4} \cdot\left(\frac{11}{3}\right)^{2} \cdot\left(\frac{3}{2}\right)^{3}}\end{array} |
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Answer» achi tarah answer dede aata nio kuch bhi 6/121 hai ans. |
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| 34. |
If a main rows 20 km with the stream and 15km against the stream takes 2 hours in eachcase, then find speed of the stream |
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Answer» wrong ans |
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| 35. |
7. If (a - 1) divides the polynomial k x^{3}-2 x^{2}+25 x-26 without remainder, thethe value of k. |
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Answer» if x-1 is a factor the x=1 satisfies the equationk-2+25-26=0k-2-1=0k=3 |
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| 36. |
10. Divide Rs 1350 between Ravish and Shikha in the ratio 2:3. |
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Answer» Let sum of ratio=2x+3x=5xSo 5x=1350X=1350/5 =270So,ravish=2x=2*270=540rsShikha=3x=3*270=810rs |
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| 37. |
15 сопрouTutu папуеапу.Shikha borrowed 20000 from the Bank for 2 years. If the rate of interest is 12% per annum,calculate the amount she has to pay at the end of 2 years.I NOTE 8QUAD CA |
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Answer» 24800 is the right answer |
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| 38. |
|| ' (x+eâ˘)dx0 |
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| 39. |
\begin{array}{l}{4 x\left(3 x^{2}-7 x\right)} \\ {5 x / 7=9 x-1 / 5} \\ {16 x^{2}-25 y^{2}}\end{array} |
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| 40. |
4[ (eÂĽ)dx0 |
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Answer» please like my answer if you find it useful |
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| 41. |
The simplest form of V 8+,28ă8-v28 |
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Answer» thanks thanks |
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| 42. |
Iy v (g o V™) (8 21T = v} (vgmo0 - 5% ot |
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Answer» LHS: (tan^2 A - tan^2 B) = (sin^2 A/cos^2 A - sin^2 B/cos^2 B) = (sin^2 A.cos^2 B - sin^2 B.cos^2 A) /cos^2 A.cos^2 B = (1 - cos^2 A)cos^2 B - (1-cos^2 B)cos^2 A/cos^2 A. cos^2 B = (cos^2 B - cos^2 A.cos^2 B + cos^2 A.cos^2 B - cos^2 A)/cos^2 A.cos^2 B = (cos^2 B - cos^2 A)/cos^2 A.cos^2 B(firsrt proof) = (1 - sin^2 B) - (1 - sin^2 A)/ cos^2 A.cos^2 B = (sin^2 A - sin^2 B)/ cos^2 A.cos^2 B (second proof) |
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| 43. |
विद दाह Lty 1 vom g v 8 =Y OS5I Y |
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| 44. |
v) (v 2)3)8) (3)+ 56 |
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Answer» please post the full question that is full question |
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| 45. |
(&#+८*) फ् - (€ - ८“) dx =0 |
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| 46. |
Evaluate Vxe* dx0 |
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Answer» hii thank you |
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| 47. |
दरdWbaX—O हेb |
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Answer» ( x -a)/(x -b) + ( x -b)/( x - a) =a/b + b/a {(x -a)² + (x -b)² }/(x -a)(x -b) ={ a² +b²}/ab ab{ (x² -2a +a² + x² -2b +b²) = (a² + b²)(x² -ax -bx + ab) ab{ 2x² -2(a + b)x +(a² + b²)} =(a² +b²)x² -(a² +b²)(a +b)x +(a² + b²)ab (2ab -a² -b²)x² -(a +b)(2ab -a² -b²)x =0 (a² + b² -2ab)x² -(a +b)(a² +b² -2ab)x =0 (a -b)²x² -(a+b)(a-b)² x =0 x² -(a + b)x =0 x{ x -(a + b)} =0 x =0, (a + b) |
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| 48. |
2| 3*dx0 |
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Answer» We know that intregalbxdx= bx/ ln b + Cso in this case it will be |
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| 49. |
2EXAMPLE 11 Evaluate: | x |dx2 |
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| 50. |
EXAMPLE 16 Evaluate:12dx |
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