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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Area of a parallelogram whose base is 17cm and height is 80cm will be-(a) 136cm2(b) 1360cm2(e) 13600cm2(d) none |
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Answer» Area of //gm = Altitude × Base= 80cm × 17cm= 1360cm². |
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| 2. |
Give the full form of the following wordsa) FOTPb) DCPc) NGO1)nt chosing the followit |
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Answer» FOTP- Fiber Optic Test Procedure.DCP-Deputy Commissioner of PoliceNGO- Non Governmental Organization |
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| 3. |
व (तो =920 ¢ Atv M e o ¥ A orLQ + C=(e)८नमन |
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Answer» tan {(B+C)/2}= tan A/2= tan 90°/2= tan 45°= 1 since A+B+C=180° a+b+c/2=180/2 {because abc is a triangle sum of angles of a triangle is 180°} a/2+b+c/2=90. b+c/2=90-a/2 taking tan on both sides tan b+c/2=tan(90-a/2) tan b+c/2=cot a/2 |
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| 4. |
a room 5m long and 4m wide needs 500 tiles for its floor. how many tiles will be needed for a hall 8m wide and 15 m long ? |
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Answer» tq |
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| 5. |
length, breadth and height of a room are 5 m, 4 m and 3 m respectively, Find thecost of white washing the walls of the room and the ceiling at the rate of1.50 per m'rectangular hall has a perimeter 250 m. If the cost of painting the four |
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| 6. |
9. Find the length of the largest pole that can be placed in a hall 10 m long, 10 m wide and5 m high.Hint. Length of the diagonal of the room v2+b2 +h2 |
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| 7. |
rectangular room has a perimeter of 182 metres. If the length of the roommeasures 5m, calculate its width.3. A |
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| 8. |
if the equationK-11 represents a circle, then K(B) 1(A) 34(C) 4/3(D) 12 |
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| 9. |
dimensions of a room are 12.5 m by 9 m by 7 m. There are 2 doors and 4 windows in theTheroom; each door measures 2.5 m by 1.2 m and each window 1.5 m by 1 m. Find the cost ofpainting the walls at ? 3.50 per square metre.16 |
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| 10. |
dimensions of a room are 12.5 m by 9 m by 7 m. There are 2 doors and 4 windows in theTheo each door measures 2.5 m by 1.2 m and each window 1.5 m by 1 m. Find the cost ofainting the walls at 3.50 per square metre.16. |
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| 11. |
7 If the volume of a cylinder of height 7 cm. is 448 π cm, find its lateral surface areaand total surface area.dan nala is 7 m highd 20cm in di |
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Answer» Dimensions of the cylinder : i ) Volume = v = 448/ pi cm^3------( 1 ) Height of the cylinder = 7 cm Let radius = r cm ____________________________ Volume of thecylinder = pi × r^2 × h----( 2 )_____________________________ Put the values in ( 2 ) pi × r^2 × h = 448 / pi pi × r^2 × 7 = 448/ pi r^2 = ( 448 ) / ( pi × pi × 7 ) r^2 = 64 / ( pi × pi ) Therefore , r^2 = ( 8 / pi )^2 r = 8/ pi cm ii ) Lateral Surface Area ( LSA ) = 2 × pi × r × h = 2 × pi × 8/ pi × 7 = 2 × 8 × 7 = 112 cm^2 iii) Total surface area ( TSA ) = 2 × pi × r ( r + h ) = 2 × pi × 8/ pi ( 8/ pi + 7 ) = 2 × 8 [ ( 8 × 7)/ 22 + 7 ] = 16 ( 28 / 11 + 7 ) = 16 ( 28 + 77 )/ 11 = ( 16 × 105 )/ 11 = 1680/11 = 152. 72 cm^2 |
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| 12. |
एक त्रिभुज का क्षेत्रफल 1176 वर्ग सेमी. है। इसकेआधार तथा उसकी संगत ऊँचाई का अनुपात 3 : 4है। त्रिभुज की यह ऊँचाई कितनी है ?(a) 42 सेमी. (b) 52 सेमी.(C) 54 सेमी. (d) 56 सेमी. |
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Answer» (b) correct answer ans. is 52cm Answer =52 centimeters |
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| 13. |
26. The surface area of a cube is 1176 cm2. Find its volume. |
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| 14. |
1176=7^c*(2^a*3^b) |
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| 15. |
Ar64 pa, ab are the length of two chords wntersectseach other at eight angle find the rodeusthe circle and the distance from their intersectingpoint to the centre of circle ise, ca radius.the ci |
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| 16. |
Consider the following situation:Raju's father's age is 5 years more than three times Raju's age. Raju's father is 44 yearsold. Set up an equation to find Raju's age. |
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| 17. |
Write a linear equation to represent the following situations.(i) 2 chairs and 3 tables cost 150.(ii) Present age of son is 5 less thanth to the age of his father. |
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| 18. |
DESEU ULLUMPURTA) Choose and write the correct alternatyand write the correct alternative from those given below(1) 2 subtracted from four times a number results in 30.from four times a number results in 30. Which of the following equationrepresents this?(c) 4x - 2 = 30 (d) 4x - 4x = 30al 23 - 4 = 30 (b) 4x - 2x= 30 |
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Answer» answer is ( B ) 4x-2x=30 (c) 4x - 2 = 30 answer the answer is (c)4x-2=30 |
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| 19. |
(From the top of a tower of height 50 m, the angles of depression of the top and bottomof a pole are 30° and 45° respectively. Find the height of the pole. (√3=1.73) |
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Answer» LetABbethetowerandCDbethepole. Now,AB=50m. Lettheheightofthepole=hmetre. DrawCL⊥AB. Now,LB=hmetresandAL=(50−h)mts LetBD=xmts Now,LC=BD=xmts. In∆ABD, tan45°=ABBD⇒1=50x⇒x=50 In∆ALC,tan30°=ALLC⇒1√3=50−h/x⇒50=503√−3√h⇒3√h=50(3√−1)⇒h=50(3√−1)/√3=50(√3−1)/√3×√3/root 3 =150−50√3/3=50(3−√3)/3=50[3−1.732]/3=50×1.2683=21.13 m |
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| 20. |
(1) From the top of a tower of height 50 m, the angles of depression of the top and bottomof a pole are 30° and 45° respectively. Find the height of the pole. (3 1.73)C. |
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| 21. |
(14) Sketch the following graphs:(i) y=3 sinx |
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Answer» like if you find it useful |
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| 22. |
lle height of the tow24 A pole stands slanting on the ground maksangle of 60 with the ground. At high noothe length of the shadow of the pole is 3danFind the length of the pole. |
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| 23. |
8. A statue, 1.6 m tall, stands on the top of a pedestal. From a point on the ground, theangle of elevation of the top of the statue is 60° and from the same point the angle ofelevation of the top of the pedestal is 45°. Find the height of the pedestal.9. The angle of elevation of the top of a building (rom the |
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| 24. |
(14) Sketch the following graphs:(i) y 3 sin x |
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| 25. |
le 1 : Rasheed got a playing top latlu) as hrssample Ihday present, which surprisingly had no colour onHe wanted to colour it with his crayons. The topdaped like a cone surmountedby a hemisphereiee Fig 13.6). The entire top is 5 cm in height andis 3.5 cm. Find the area,hehe diameter of the tophas to colour. (Take Ď =-_-) |
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| 26. |
the triangle8. The area of a triangle is 1176 cm2. The ratio of the base to the corresponding altitude is 3:4. Find thealtitude of the triangle. |
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Answer» Base : Altitude = 3 : 4 Base = 3x Altitude = 4x Area = 1176 cm*cm Area = base*height/2 2×1176 = 3x*4x x*x = 2352/12 = 196 x = 14 Altitude = 4x = 4×14 = 56 cm If you find this answer helpful then like it. |
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| 27. |
(v) cos 130° cos 40°+ sin 130° sin 40° = 0 |
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Answer» cos (A-B) = cosA×cosB + sinA×sinBA=130B=40A-B = 130-40 = 90 so cos (90) = 0proved |
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| 28. |
B.Answer the following questions.100 ka) Ivaries directly as m and /is equal to 5, when mFind/when m67. Thesusca64 |
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| 29. |
find the value of the variables 5-t=12 |
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Answer» 5 - t = 12 Subtract 5 on both sides -5 + 5 - t = 12 - 5 - t = 7 multiply -1 on both sides t = -7 |
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| 30. |
(I) m2- 14m+ 130 |
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| 31. |
15. In the given figure LCD-130°80 , then finde130る |
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Answer» by property of exterior angleangA+80°=130°angA=130°-80°angA=50° a+b= ca+80 =130a= 50 |
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| 32. |
27. In the given figure, O is the centre of the circle.Arc ABC subtends an angle of 130° at the centreO. AB is extended upto P. Find PBC.130°130°B P28. |
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| 33. |
28. In the given figure, ifPQIISTZPQR= 110°and ZRST 130°, find ZQRS.130°110 |
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Answer» 60° is the answer for this question Draw lineXY parllel to PQ and ST and then angle XRQ would be 70° and angle YRS would be 50° (angles on the same side of the tranversal) and then by linear pair angle QRS =180°-(70°+50°)= 60° |
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| 34. |
FIND THE LENGTH OF THE LARGEST POLE THAT CAN BE PLACED IN A HALL 10 M LONG 10 M WIDE AND 5M HIGH |
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Answer» in a hostel there were provisions for 300 student for 45 days after 31 days 195 student leave the hostel how long did the remaining provisions last for remaining students |
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| 35. |
The horizontal distance between two pole is 15m. The angle of depression of the top of the second pole as seen from the top of first pole is 30 degree. If the height of the second pole is 24m. Find the height of the first pole. [use root 3 = 1.732] |
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Answer» Let AB be the 1st pole and CD be the 2nd poleAC=15mCD=24mlet AB=xCE=xED=24-xconsider triangle BEDtan30° = DE/BE1/√3 =(24-x)/1515=√3(24-x)5√3 = 24-xx = 24-5√3 = 15.33m plz share the figure |
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| 36. |
12. A man stands 9 m away from a flag-pole. Heobserves that angle of elevation of the top ofthe pole is 28° and the angle of depression ofthe bottom of the pole is 13º. Calculate theheight of the pole. |
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| 37. |
pole stands vertically on the ground, If the angle of elevation of the top of the pole frompoint 90 m away from the pole has measure 30, find the height of the pole.l. A |
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Answer» thanks but who are you teacher or student |
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| 38. |
7. sinŽ+cosccO=2¢l4 dl sind9+ coseclp WAL |
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Answer» If you like the solution, Please give it a 👍 |
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| 39. |
walхуProve analytically "An angle in a semicircle is right angle".for |
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Answer» express the following in p q from 0.4 |
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| 40. |
l reachun the topuBit the wal |
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| 41. |
The internal measures of a cuboidal room,are 12 m × 8 m × 4 m. Find the total cost ofwhitewashing all four walls of a room, if the cost of white washing is 8 per m^2. Whatwill be the cost of white washing if the ceiling of the room is also whitewashed? |
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Answer» 2(l+b)h = LSA2(12+8)4 =2(20)4 = 40*4 = 160m²cost of whitewashing 4 walls =160*8 = Rs 1280area of 5 walls = LSA+ length*breadth = 160 + (12*8) = 160 + 96 = 256m²cost of whitewashing with ceiling = Rs 1280 +(96*8)1280+7682048rupee
Thanks sir |
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| 42. |
·23×34 × 43 x 32 |
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| 43. |
34. Express : in terms of the other variables in the picture. |
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Answer» use similar trianglesa.t/h = (x+t)/rx+t = rt/hx = rt/h - t.. . . b. same concept is applied to different sidesbut with an additional use of the pythagorean theoremx/t = r/√(r^2-h^2)x = rt/√(r^2-h^2) |
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| 44. |
34+23 |
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Answer» the answer of 34+23 is 57 the answer is 57 so easy...... 57 is answer 😀😀😀😀😀 57 is answer this question the correct answer is 34+23 = 57 by simple addition method of the mathematics the correct answer is 57 |
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| 45. |
an x - sin x). Ligg —— % W जेx>0 x 3 |
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Answer» thanku sir thanks sir |
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| 46. |
DATE:nts for the measured2103-10395°0386 |
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Answer» Crop that question that you want to ask |
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| 47. |
s Doound each number to the nearest hundred to estimate thevalue of each of the followinga) 384 + 296b) 1095 + 211o 2014 Scholastic Education International (S) Pte |
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Answer» 380+300 = 680 1100+210 = 1310 |
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| 48. |
ă Esto two. Consecutive lede paative intege st for Atak sede |
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Answer» let the no.s be 2x+1 , 2x+3(2x+1)²+(2x+3)²=2904x²+4x+1+4x²+12x+9=2908x²+16x-280=0x²+2x-35=0(x+7)(x-5)=0x=5,-7 no.s are 2x+1=112x+3=13 |
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| 49. |
I)Express 23 km 34 m as m and em |
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| 50. |
A2चित्र में 40 । 80 तथा ह-1/800 है, तो सिद्ध कीजिए कि“2CA% =2AB? + BC? 21 |
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Answer» In right DADB, AB2= AD2+ BD2[By Pythagoras theorem] – (1)In right triangleADC, AC2= AD2+ CD2[By Pythagoras theorem] – (2)Subtract (1) from (2), we getAC2– AB2= AD2+ CD2– AD2– BD2AC2– AB2= CD2– BD2 --- (3)Given BD =1/3 CD From the figure, BD + DC = BC⇒ (1/3)CD + CD = BC⇒ (4/3)CD = BC∴ CD = 3BC/4⇒ BD = BC/4Equation (3) becomes,AC2– AB2= (3BC/4)2– (BC/4)2 = (8/16)BC2⇒ AC2– AB2= (1/2) BC2⇒ 2AC2– 2AB2= BC2⇒ 2AC2= 2AB2+ BC2 |
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