1.

The horizontal distance between two pole is 15m. The angle of depression of the top of the second pole as seen from the top of first pole is 30 degree. If the height of the second pole is 24m. Find the height of the first pole. [use root 3 = 1.732]

Answer»

Let AB be the 1st pole and CD be the 2nd poleAC=15mCD=24mlet AB=xCE=xED=24-xconsider triangle BEDtan30° = DE/BE1/√3 =(24-x)/1515=√3(24-x)5√3 = 24-xx = 24-5√3 = 15.33m

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