Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

MODERN'S abc OF MATHEMATIOS.lrr the fig., o<AOB = 70°. Cis the centre of the circle andalculate the values of (i) LOCA1centre o(ii) ZOAC.70°

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2.

(i) 6g+4b2a+5b

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8a + 9b

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3.

37. In the given figure TA is a tangent to thecircle ABC at A. If mZTAB=80° andmZBAC=30°, then what is m ABC ?(A) 50°(C) 70°(B) 60°(D) 80°

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As its linear anglesso 80+30+CAT= 180CAT= 70°now angle BAT= 80° = ABC= 80°

4.

2a+3b =83a-4b=-5

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2a + 3b = 8a = (8 - 3b)/2.......(1)

3a - 4b = - 5..........(2)

Put value of a from eq(1) in eq(2)3(8-3b)/2 - 4b = - 524 - 9b - 8b = - 1034 = 17bb = 34/17 = 2

From eq(1)a = (8 - 3*2)/2 = 2/2 = 1

5.

(i)y +18=-70

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6.

17) If 2A-4B-5C, find A:B:C.

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Assume 2a = 4bso a/b = 4/2 = 16/4(cross multiply and multiply 4.we do this in order to get b=b for the next step)also 4b = 5cso b/c = 5/4

7.

IV) 4If A 2a - 4b, B 3a 5b and C -a + 2b, then A + B-C is

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8.

13.Find the sum and product of zeros of the polynomial 6x² - 3 - 7x

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9.

(iv) Determine, the type of triangleAB= 4cm,BC=5 cm,CA=5 cm

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10.

of- find the value of the polynomial6x-2x2 +3 at

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first ka bhi dusre ka mines

11.

find the value of the polynomial 6x-2x²+3 at (i) X=0 (ii) X=-1

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i)3ii)-5 just put the value of x in the equation

ansafter putting given value in 6x-2x^2+3i) putting x=0=6(0)-2(0)^2+3=0-0+3=3 ans

ii) putting x=-1=6(-1)-2(-1)^2+3=-6-2+3=-8+3=-5 ans

12.

In △ABC, LB = 45° and LC= 65°.In △ABC, state greatest side with reason.

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13.

2. If A is a square matrix of order 3 and 2A k|Al, then find the value of k.

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For a squarematrix of order n, |kA| = k^n|A||2A| = k |A|2^3|A| = k |A|k=8

14.

( \frac \operatorname sin 77 ^ \circ \operatorname cos 13 ^ \circ ) ^ 2 %2B ( \frac \operatorname cos 77 ^ \circ \operatorname sin 13 ^ \circ ) ^ 2 - 2 \operatorname cos ^ 2 45 ^ \circ

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15.

EXERCISE 11.21. Construct a triangle ABC in which BC 7cm, 4B 75° and AB +AC 13 cm.

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16.

Construct a triangle ABC in which BC7cm, LB # 75° and AB+A

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17.

-isoscelestarianglewith AB=AC and LB=7018ABC

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18.

EXERCISE 11.2a triangle ABC in which BC-7cm, 4B-75 and AB-AC-18m

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post clear photo of the question

19.

EXERCISE 11.2ruct a triangle ABC in which BC-7cm, 4B-75 and AB +AC-13 cm.

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20.

(1) 6a+4b2a+ 5b

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21.

if alpha and beta be the zeros of the polynomial 2 X square + 5 x plus Que such that Alpha square plus beta square + alpha beta equal to 21 by 4 find k

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22.

X square plus 8x plus 16

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Plz can you tell me this answer with using identity a square plus 2ab plus b square

23.

what is c to 5 square plus 13 square

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C = 5²+13²C = 25 + 169C = 194

24.

if a + b + c equal to 6 and a square + b square + c square equals to 34 ,then ab+bc+ca=

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Given :

a+b+c = 6

a² + b² + c² = 34

We know,

(a+b+c)² = a² + b² + c² + 2(ab+bc+ac)

6² = 34 + 2(ab+bc+ac)

36 - 34 = 2(ab+bc+ac)

2/2 = (ab+bc+ac)

(ab+bc+ac) = 1

25.

a plus b whole square

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(a+b)^2= a square + b square+ 2ab

26.

a^ 2 + 4b^2 = 12ab log(a + 2b)

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a^2 + 4b^2 = 12ab

a^2 + (2b)^2+4ab = 12ab + 4ab

(a+2b)^2 = 16ab

Take log on both sides

2log(a+2b) = log16 + logab

log(a+2b) = 1/2 (4log2+logab)

log(a+2b)=2log2+1/2logab

tq

27.

solve the equation 9xsquare-9(a+b) x+ (2a square +5ab +2b square) =0

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28.

(2a-b)square+(2a-b)-8

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(2a-b)^2+(2a-b)-84a^2+b^2-4ab+2a-b-84a^2+2a+b^2-b-4ab-8

29.

solve the value of xand y 2(ax_by) +(a+4b)=02(bx+ay) +(b_4a)=0

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30.

(76 + 29) (0 рдиреЗ 4b)

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(7a + 2b) ( a + 4b)

7a² + 28ab + 2ab + 8b²

7a² + 8b² + 30ab

31.

Expand : (3a —4b + "oc)2|

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Two adjacent sides of a parallelogram are 10cm and 12cm. If it's one diagonal is 14cm long, find the area of the parallelogram.

32.

foctorize the following.(1)a^2+4b^2-4ab

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a² + 4b² - 4ab = (a)² + (2b)² - (2)(a)(2b) = (a - 2b)²

33.

16 (a + b)2- 4a -4b

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Factorization

(a+b)² - 4a - 4b

(a+b)² - 4 ( a + b)

Take ( a + b) common

(a+b) ( a + b - 4)

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34.

(8) ञ. कम नयदि बहुपद 7 0 +5 के शून्यकों का योग 1 की |1(b) -5 (© 5L o 4B (2) 1

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35.

EXERCISE 4B1. Draw the graph of each of the following equations(ii) x + 4i) x = 40

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1) red line2) blue line

36.

x3 + 3x² + 3xt!divided by at

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We use the remainder theorem here

Given divider = x + 1

So of it is a factor p (x) = 0

x + 1= 0 => x = -1

When will it be a factor, when we subtract the remainder

According to the question

P ( -1 ) - r = 0

Polynomial =x^3+3x^2 -3x-1

Therefore-1^3 +3 × -1 ^2 -3 ×-1 - 1 -r =0-1 +3+3-1 = r

Remainder = 4

iska answer hai fourhai

37.

EXERCISE 2.3Find the remainder when x + 3x + 3x + 1 is divided by1.(i)+1

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0, 5/2 is the correct answer of the given question

38.

Find the remainder when x, 3x' + 3x + 1 is divided byO r+1(ii) x(i

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39.

1. Find the square of:(i) 2a +b

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40.

B. The area of a square is 4a2 sq. metres. Whatis its boundary?1. 2a2. 4 a3. 8 a4. 16 a.

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41.

यदि वर्ग आव्यूह A की कोटि 3 और [A] = 4 है, तो |-2A का मान लिखिए ।If A is a square matrix of order 3 with | A] = 4, then write the value of- 2A|.

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If |A|=4 then |-2A|=8

42.

EXERCISE 10AFind each of the following ratios in the simplest form:(i) 24 to 56(i) 84 paise to 3(il1) 4 kg to 750 goitto I hour(vil 2.4 km to 900 m

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43.

6. Find the smallest number which when divided by 15, the remainder is 10, whendivided by 25, the remainder is 20 and when divided by 35, the remainder is 30.(1) 530 (2) 525 (3) 520 (4) 515

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NONE OF THE ABOVE THIS IS THE WRONG QUESTION

this question is wrong

option 2 is the correct answer

44.

When a polynomial f(x) is divided by (x - 1), the remainder is 5 and when it is divideby (r -2), the remainder is 7. Find the remainder when it is divided by (x-1) (2)

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45.

Manjit bought an iron safe for 12160 and paid䚏340 for its transportation. Then, he sold itfor䚏12875, Find his gain percent.

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Cost price for iron safe=₹12160+₹340=₹12500

Selling price=₹12875

Gain=Selling price-Cost price=₹12875-₹12500=₹375

Gain percent=(375/12500)*100= 3%

46.

24 and 36.Find the largest four-digits number which when divided by 47leaves a remainder of 3 in each case.1 which should be added to 2497 so that the sum

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L.c.m of 4,7,13=364we known that the greatess 4 digit no. is 9999now we divide the l.c.m by greatness no. 9999we get 27 as quotient and 171 as remainder now substrate the remainder by 99999999-171=9828

47.

है ७८ समकोण त्रिभुज है, जिसमें 24 = 90° SR 4B = AC है। 4B

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48.

24b 100

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49.

If sin (A+2B)-and cos (A+4B)-0, A B and A +4B < 90°, then find the value of A and B.

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sin(A+2B)=sin60°.=>A+ 2B=60°. cos(A+4B)=cos90° =>A+4B=90°. Now we have

Subtract both equation. - 2B=-30° =>B=15°. Hence A+2.15°=60°=>A=60°-30°=30°. A=30°,B=15°

As we have sin(A+2B)=sin60°.=>A+ 2B=60°. cos(A+4B)=cos90° =>A+4B=90°. Now we havenow

50.

31. If ZA and 4B are acute angles such that tan A tan B then prove thatLA 4B.

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If angle A and angle B. are acute angle and tanA = tanB so, sinA/cosA = sinB/cosB => sinAcosB -sinBcosA. = 0=> sin(A-B) = 0 ... ( standard identity ) so A-B = 0 or A = B.