Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The shape of a garden is rectangular in the middle and seni cncalat the ends as shown in the diagram. Find the area and the perimeterT of this garden [Length of rectangle is7m 20- (3.5+3.5) metres).

Answer»
2.

Square: A rectanglewith sides of equallengthAll the properties of a prhombus and a rectangl

Answer»

It can also be defined as an equiangular quadrilateral, since equiangular means that all of its angles areequal(360°/4 = 90°). It can also be defined as a parallelogram containing a right angle. Arectangle with foursidesofequallength is a square.

3.

This is the thira alt(-35) 719 15

Answer»

(-35)/19 - 7/15

Take LCM

=[(-35)*15 - 7*19] / 19*15=(- 525 - 133) /285= - 658/285 ans

4.

Find the area of a square of side 13 3/4 m

Answer»

Side= ((13*4)+3)/4m=55/4 marea of square=side*side=(55/4)*(55/4)m^2=189m^2

5.

100 is sulferad FindBy selling a tape recorder for Rs 600 a loss ofAlso, find loss per cent.its Gost prica

Answer»

S.P.=600loss=100so C.P.=700so loss percentage=100/700*100=14.28%

6.

12,100 in few years, find the duration of investment if the rate ofi10.000 amounts tocompounded annually(3) Ifinterest isSolution:.

Answer»

Please hit the like button if this helped you

hi

7.

ExePeISEA train leaves Chennai at 10:30 p.m. on Saturday and reaches Bangaloreon Sundsy Find the duration of the journeynd the time taken by the Nijamuddin A

Answer»
8.

13. Find the side of a square whose area is 825 cm

Answer»
9.

13. Find the side of a square whose area is 625 cm

Answer»

I don't understand this hand-writing

10.

13. Find theside of a square whose area is 825 cm2

Answer»
11.

A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2, findthe area of the lawn.

Answer»
12.

16. A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2, find thearea of the lawn.

Answer»
13.

A square lawn is surrounded by a path 2.5 m wide. If the athe area of the lawn.rea of the path is 165 m2. find

Answer»
14.

\frac{\left(2^{n}+2^{n-1}\right)}{\left(2^{n+1}-2^{n}\right)}

Answer»

right answer

15.

244Example4 Mayank made a bird-bath for his garden 30 cmin the shape of a cylinder with a hemisphericaldepression at one end (see Fig. 13.9). The height ofthe cylinder is 1.45 m and its radius is 30 cm. Find the

Answer»
16.

ull Cost of developing a garden arounthe house at the rate of R 55 per m.The shape of a garden is rectangular in the middle and semi circulat the ends as shown in the diagram. Find the area and the perimeT of this garden [Length of rectangl7m 20-(3.5+3.5) metres].20m

Answer»
17.

John sold an article to Peter at 20% profit andPeter sold it to Mohan at 5% loss. If Mohanpaid 912 for the article; find how much didJohn pay for it ?

Answer»

Let John buy the article at a cost C.

Peter buys it at (100+20)C/100 = 1.2 C

Peter sells to Mohan at = [ (100-5) /100 ] * 1.2 C = 0.95 * 1.2 C = 1.14 C

Mohan buys it for 1.14 C = Rs 912

C = Rs 912 / 1.14 = Rs 800

John paid Rs 800 for the article.

18.

Rajesh12, John sold an article to Peter at 20% profit andPeter sold it to Mohan at 5% loss. If Mohanpaid 912 for the article; find how much didJohn pay for it ?

Answer»

Let John buy the article at a cost C.

Peter buys it at (100+20)C/100 = 1.2 C

Peter sells to Mohan at = [ (100-5) /100 ] * 1.2 C = 0.95 * 1.2 C = 1.14 C

Mohan buys it for 1.14 C = Rs 912

C = Rs 912 / 1.14 = Rs 800

John paid Rs 800 for the article.

19.

Gopi sold a watch to Ibrahim at 12% gain and Ibrahim sold it to John at a loss of 5%. IfJohn paid 330, then find how much did Gopi sold it?

Answer»
20.

aganlal bought trousers for 400 and a shirt for R 200 and sold them forand 250 respectively. Which of these transactions was more profitable?1. M

Answer»
21.

nnum. iEXERCISE 8.3Tell what is the profit or loss in the following transactions. Also findloss per cent in each case.(a) Gardening shears bought for ?250 and sold for? 325.(b) A refrigerater bought for 12,000 and sold at 13,500.(c) A cupboard bought for ? 2,500 and sold at 3,000.(d) A skirt bought for 250 and sold at 150.

Answer»
22.

Fint the ratio in which the line x -y 2 divides the line segment joining the points A(3,-1) and B(8,9).

Answer»
23.

king Mr. Gupta's office starts at 10:15 a.m. and closes at 7: 15 p.m. Find thetime duration ofher office.

Answer»
24.

Tell what is the profit or loss in the following transactions. Also find profit per cent orloss per cent in each case.(a) Gardening shears bought for 250 and sold fort 325,(b) A refrigerater bought for ? 12,000 and sold at 13,500.(c) A cupboard bought for 2,500 and sold at 73,000(d) A skirt bought for ? 250 and sold at 150.1.

Answer»

Very nice

25.

a)A skirt bought for250 and sold at150.

Answer»

Cost price of skirt = Rs. 250

Selling price of skirt = Rs. 150

Since, C.P. > S.P., therefore here is loss.

∴∴Loss = C.P. – S.P. = 250 – 150 = Rs. 100

Now Loss% =Loss/C.P.×100

=100/250×100= 40%

Therefore, Profit = Rs. 100 and Profit% = 40%

26.

A skirt bought for Rs 250 and sold Rs150

Answer»

please complete the question, fully.

CP=250SP=150PROFIT=250-150=100PROFIT PERCENTAGE=100/250*100=40%

thanku😊

27.

ta itA-Bland A114]then A is equal to-5 3(2) 2(4)-3,(3) 3

Answer»
28.

1. A rectangular garden 30 m long and 25 m wide has a path 2.5 m wide running all aroundinside it. Find the area of the path.205

Answer»

Outer Area = 30m × 25 m=750 m^2Iner length = 30 m - (2.5m + 2.5m )= 25mIner breadth = 25m - ( 2.5 m + 2.5 m )= 20mIner Area = 25m × 20m= 500 m^2Area of the path = Outer Area - Iner Area= 750 m^2 - 500m^2=250m^2

Thanks

29.

5. The length and breadth of a rectangular park are in the ratio 5 : 2. A 2.5 m wide path running allaround the outside the park has an area 305 m2. Find the dimensions of the park.

Answer»

Thank you Bhai

30.

The length and breadth of a rectangular park are in the ratio 5: 2. A 2.5m wide path running all aroundthe inside of the park has an area of 290m2. Find the dimensions of the park.12.

Answer»

If the area is 290 sq m then,

let the length of the rectangular park be 5x∴ breadth will be 2xso area= l*b 5x*2x =10x²width of the park all around the park=2.5m∴lenght and breadth including path (5x+2.5 +2.5)m=(5x+5) and breadth of rectangular park=(2x+2.5+2.5)=(2x+5)thus, area of the park=[(5x+2)(2x+5)-10x²]m²=(35x+25)m²it is given that 35x +25 =290⇒35x=265x=53/7thus the lenght of the park=5*53/7=265/7m and breadth of the park=2*53/7=106/7m

hit like if you find it useful

31.

. The length and breadth of a rectangular park are in the ratio 5: 2. A 2.5 m wide path runningaround the outside of the park has an area of 305 m2. Find the dimensions ofthe park.

Answer»
32.

The length and breadth of a rectangular park are in the ratio 5:2. A 2.5-m-wide pathrunning all around the outside of the park has an area of 305 m2. Find the dimensions ofthe park.

Answer»
33.

0. The length and breadth of a rectangular park are in the ratio 5:2. A 2.5-m-wide pathrunning all around the outside of the park has an area of 305 m2. Find the dimensions of,De park.

Answer»

thanks

34.

10. The length and breadth of a rectangular park are in the ratio 5:2. A 2.5-m-wide pathrunning all around the outside of the park has an area of 305 m2. Find the dimensions ofthe park.

Answer»
35.

A path 2.5 m wide is running around a square field whose side is 45 m. Determine the areaof the path.1im long and 125m wide. A carpet is to be laid on the floor

Answer»
36.

He costof constructngheToausatthoTto15. The length and breadth of a rectangular park are in the ratio 5:2. A 2.5 m wide path running allaround the outside the park has an area 305 m2. Find the dimensions of the park.

Answer»
37.

1) Find the value of (-10m?n) x (-20mn45) for m= 1.2 and n=-1.

Answer»

(-10×1.44×-1)×(-20×1.2×1)=(14.4)×(-24)=-345.6

38.

The rates of working of A and B are in the ratio 3: 4. The number of days taken by them to finish the work are in the ratio(a) 3:4(b) 9:16(c) 4:3

Answer»

I can't able to understand

39.

The present ages of Anita and Vinita are in the ratio 4:5. Ten years ago, their ageratio 3:4. What are their present ages ?16.s were in the

Answer»
40.

Find the coordinates of the point which divides the linesegment joining (-1, 3) and (4, -7) internally in the ratio3:4.1.

Answer»
41.

If two towers of height hi and h2 subtend angles 60° and 30 respectively at the mid-point of line joining their bases them hi

Answer»
42.

given a choice toGG for short. You luould you like to meet?Jyotindra Mohan Challuse in his time old GG was fallOUhen went on to write grammar booksght an almirah forき2000 and spentts of money2254. What per cent did he gain or lose?300 on getting it painted. He then sold it foror16 000 and spent150

Answer»
43.

Sub MatTo scupsu sen 3 digu mumben on amcacusA) move s stats sd8) maut stepsmove ass backwandEill in thu blanks3 equal taFasntoCourting used to

Answer»

5-3=2

it can be written like this

44.

DO8. The weight ofis the weight84ofidentical books is 12 kg. what35 such books?

Answer»

84books=12kg then 1book=12/84 then 35books=12/84×35=5kg

45.

4. The diameter of the sun is 1.4 × 109 m and the diameter of the earth is 1.2756 × 10, m. snowdiameter of the sun is nearly 100 times the diameter of the earth.

Answer»

Diameter of sun = 1.4 * 10 mDiameter of earth = 1.2756 * 10 mHence Diameter of sun = 109.75 * radius of earthSo sun is nearly 109 times larger than earth in diameter

how do you convert the exponent bro

46.

I.(i) Find the sum ofn terms ofa series l+-+-i--+…

Answer»
47.

ハ29. ll' the sum ofn, terms of an AP is the same as the sumoller,they meet in I hour. What are the spceds of the two cars?(m + n) terms is 0.of n terms, show that the sum of

Answer»
48.

7.TheFne diarneter of the modiameterofthemoonisapproximatelyxmne fourth of the diameter of the earth.onefourthofthediameteroftheearth.

Answer»

Let diameter of earth = D

diameter of moon =D/4

=) radius of earth = D/2

=) radius of moon = D/8

earth and moon are like spheres.

curved surface area of earth = 4π(D/2)^2

curved surface area of moon = 4π(D/8)^2

so ratio of their surface area

= 64/4 = 16:1

49.

Also the sum or the l rnas casefindfitsconIfthe sum of the first a term of an APithe fist torm charis sWaais the sum of first two terns? What is the second serm? Samilarbh, find the Jrd, the 10th ansdthe nth terms.

Answer»
50.

The diameter of the sun is 1.4 x 10m and the diameter of Pluto is 23 x 10 m. How many times moreis the diameter of sun as compared to that of Pluto?

Answer»

what is your question