This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
. How many coneslow many spheres 12 cm in diameter can be made from a metalliccylinder of diameter 8 cm and height 90 cm?11. The diameter of a he |
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| 2. |
hihe values of the letters in3 A+2 5B 2 |
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Answer» 3 A+2 5---------- B 2--------A=7B=6 |
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| 3. |
solutb=-1 +21+k, c-3i + j are such thatnaih Itǐ are such thata+ jb 1s perpendicularT2/t2k,to c, find the value of j |
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| 4. |
a2+ ad abbd ad-be oac + cd ad + d20 ad -h |
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Answer» tum pagal hotum pagal hotum pagal ho |
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| 5. |
बीनऊक$ हू0 8 %0 २०८8 ६५९४०6) moesgee 3xi) (0, 6) i) (9 1) iii) (—1, 3) iv) (2, 0)a) (i) SO (iii) b) (i) 3, (iv)d) (if) 3 (i)0) (ii) B (0 |
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Answer» If you find this solution helpful, Please like it. |
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| 6. |
2000oExample 7: Meenu bought two fans for 1200 each. She sold one ata loss of 5% and the other at a profit of 10%. Find the selling price ofeach. Also find out the total profit or loss. |
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| 7. |
(0 4 рди 8 T, x -GN9 3 ┬о) 3 |
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| 8. |
(i) 2x2-7x+3=0(iii). 4x2t4V3x + 3-0 |
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| 9. |
L, + 6= 04 X0 dhouss AN6) Tooesves 3xiii) (â 1, 3) ) (2 0)i) (0, 6) i)(9. 1)a) (i) SO (i) b) (i) D, (V)o) (i) D (v) DD 3 (iii) |
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Answer» If you find this solution helpful, Please like it. |
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| 10. |
(ii) If first of the n GM between two positive numbers a and bis G , then show that Gn+1 = a".b |
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Answer» The nth term of a GP series is Tn = arn-1, where a = first term and r = common ratio = Tn/Tn-1) . The sum of infinite terms of a GP series S∞= a/(1-r) where 0< r<1. If a is the first term, r is the common ratio of a finite G.P. consisting of m terms, then the nth term from the end will be = arm-n |
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| 11. |
k if the sum of n terms of an A.P. is (pn+ gn), where pind the common difference. |
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| 12. |
L Ifthe sum ofn terms of an A. P. is (pm + gn?), where p and q are constants, find the common difference. |
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| 13. |
9. Nine boards are stacked on the top of each other. The thickness of each board is 32How high is the stack? |
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| 14. |
9. Nine boards are stacked on the top of each other. The thickness of each board is 3-How high is the stack?CON |
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Answer» thanks |
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| 15. |
9. Nine boards are stacked on the top of each other. The thickness of each board is 34 cm.How high is the stack? |
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Answer» the answer of the question is 33cm |
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| 16. |
amount has been collected?Nine boards are stacked on the top of each other. The thickness of each board is 3How high is the stack?CIN |
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Answer» right |
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| 17. |
9. Nine boards are stacked on the top of each other. The thickness of each board is 3rd is 3cm.How high is the stack? |
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| 18. |
A solid right circular cone has a diameter of 14cm and height 24cm. |
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Answer» Given: the right circular cone has a diameter of 14 cm and height = 4 cm=>diameter of the right circular cone=(14 / 2 )cm=7 cm. This right circular cone is melted and moulded into a hollow hemisphere ,the hollow hemisphere has an external diameter of 10 cm. =>radius=5 cm Let the inner radius of the melted or the resulting hemisphere be 'r' cm. ∴Volume of the cone=Volume of the hollow hemisphere =>π×7²×4/3=2π(5³-r³)/3=>r=4.14 cm ∴Its internal diameter=8.28 cm And its total curved surface area={(2×π×7²)+(2×π×4.14²)}=415.35 cm² thanks I will sent more questions |
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| 19. |
wall isLidgn another- Hous nuch |
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| 20. |
The base radius of a solid right circular cone is equal to the length of the radius ofasolid sphere. If the volume of the sphere is twice of that of the cone, then let us writeby calculating the ratio of the height and base radius of the cone. |
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| 21. |
thmetic mean of x and y is a, that of y and z is b and x, y, z are in A.P. then show that thearithmetic mean of a and b is y3. If ari |
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| 22. |
ey पर ४ पल: िलियादन 15 [कसर बसु,( है 2) 1 iy |
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Answer» 11/3=3.67 17/5=3.4 19/6=3.17 3/8=0.375 |
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| 23. |
OL NOMIALSEXERCISE 2.21. Find the zeroes of the following quadratic polynomials and verify thethe zeroes and the coefficients.(ii) 4s2-4s + 1(ăŞF-15(iii)(vi)(iy) 4u + 8u |
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Answer» there is your ans there is your ans |
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| 24. |
IR\O Drawe the venn ciogrom For folls iy Vb ) ” (AND ) (०iy A R il Ay |
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Answer» Like if you find it useful |
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| 25. |
4) For an event E, If P(E)= then find P(Ä). |
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Answer» We know P(E) + P(E') = 1 P(E') = 1 - 3/7 = 4/7 |
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| 26. |
iyDEEINIT! |
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| 27. |
Qs.uf P(E)-0.67 then find P(not E)-? |
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Answer» P(E) = 0.67 P(E) + P(not E) = 1 P(not E) = 1 - 0.67 = 0.33 |
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| 28. |
\frac { f ( x + h ) - f ( x ) } { h } , \text { where } \quad ( a ) f ( x ) = 2 x + 3 \quad ( b ) = \frac { 1 } { x + 1 } ( c ) f ( x ) = x ^ { 2 } |
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| 29. |
(i)(x+Iy=2(x-3) |
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Answer» x²+1+2x=2x-6x²=-7x=7i |
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| 30. |
rify (= xâ=) = (=x3) |
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Answer» 3/4 × 8/24 = 1/4 8/24 × 3/4 = 1/4 so (3/4 × 8/24) = (8/24 × 3/4) |
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| 31. |
13. If the supplement of ari angle is 650 then find its complement. |
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| 32. |
limxâ0 |
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| 33. |
x²-x-72 |
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| 34. |
Yok |xâ-1 |
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| 35. |
x²-2x-8 |
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Answer» Thank you |
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| 36. |
J. The coach of a cricket team bltys 3 hats and oballs for t3900. Later, she buys anothaerLater, she buys anotherF 1300. Represent this situation algebraicallybat and 3 more balls of the same kind forand geometrically |
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Answer» Let the cost (in Rs.) of 1 bat and 1 ball be x and y respectively.Hence, from the given information the pair of equations will be3x + 6y = 3900; 1x + 2y = 1300which can also be written as:3x + 6y – 3900 = 0; x + 2y – 1300 = 0Note that what we got here is a dependent pair as a1/a2= b1/b2= c1/c2Hence this does not have a unique solution and instead has infinitely many solutions.Let us understand this geometrically. For 3x + 6y – 3900 = 0 x 700 300 Y 300 500 Forx + 2y – 1300 = 0 X 800 500 Y 250 400 The points are plotted and joined to get lines forming the following graph:From the graph it is clear that the lines are coincident and hence each point on them represents a solution of the pair. Hence the pair has infinitely many solutions. |
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| 37. |
why x°=1 |
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Answer» In short, the multiplicative identity is the number1, because for any other number x,1*x = x. So, the reason that any number to the zeropowerisoneis because any number to the zeropower is just the product of no numbers at all, which is the multiplicative identity,1. wrong |
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| 38. |
x²-2x-99 |
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| 39. |
x²-22x+72 |
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Answer» thanks |
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| 40. |
12)Find the derivative of: f(x) = **COSAta: |
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| 41. |
Write Euler's formula and then find E?, if F 20and V 12. |
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Answer» Euler's Formula states that if we add the number of faces and vertices together and then subtract the number of edges, we will get 2 as our answer. The formula is written as F + V - E = 2 For F = 20, V = 12E = F + V - 2E = 20 + 12 - 2E = 32 - 2E = 30 Value of E = 30 |
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| 42. |
“कट्"Iy’ |
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Answer» x = 5 |
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| 43. |
f x y12 and y32, find the value of x2 y |
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Answer» please give me answer of all questions please post your all question in app. |
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| 44. |
iy — D6 + D 6 |
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Answer» a(m^2 + 49 - 14m)=a(m^2 -7m -7m + 49)=a(m-7)(m-7) |
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| 45. |
l Swork done by a body on application of a constant force is directly proportionalIf theto the distance travelled by the body, express this in the form of an equation in twoariables and draw the graph of the same by taking the constant force as 5 units. Alsoead from the graph the work done when the distance travelled by the body is(i) 2 units(ii 0 unit |
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| 46. |
In Î ABC, ADä¸BC and AD"AD x CD Prove that/BAG-900BD |
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Answer» Given : In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADCSo, Pythagoras theorem should be apply , Then we have , AB² = AD² + BD² ----------(1)AC²= AD²+ DC² ---------(2) AB² + AC² = 2AD² + BD²+ DC²= 2BD . CD + BD² + CD² [ ∵ given AD² = BD.CD ] = (BD + CD )² = BC²Thus in triangle ABC we have , AB² + AC²= BC² hence triangle ABC is a right triangle right angled at A ∠ BAC = 90° Like my answer if you find it useful! thnku😊 |
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| 47. |
Uft 2, 를, 3, 2Find common difference in the given A.Ps 2}, 3,1.弧ㄒ何3.R軻貳TTI57ft 2, 7, 12Find the 5th term of the AP 2,7, 122· |
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| 48. |
(i) If 5 cos θ-12 sin θ0, find the value of sin θ+cos2cos θ-sin θ(ii) If cosec θ = 13, find the value of 2 sine-3 cosa12Hint.(i)5 cos θ-12 sin θ05 cos θ-12 sin θ-> cot8-12.2(ii) cot2 θcosec2 θ-1-(12)-1-1644-1-144cot"i |
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Answer» This is the answer |
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| 49. |
if f(x) =2x^3_13x^2+17x+12find f(2) |
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| 50. |
find m if (m-12)x²+2(m-12)x+2=0 |
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Answer» For roots to be Real and Equal B^2-4AC = 0 Thus , We get m=12 or m=20 |
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