Saved Bookmarks
| 1. |
In Î ABC, ADä¸BC and AD"AD x CD Prove that/BAG-900BD |
|
Answer» Given : In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADCSo, Pythagoras theorem should be apply , Then we have , AB² = AD² + BD² ----------(1)AC²= AD²+ DC² ---------(2) AB² + AC² = 2AD² + BD²+ DC²= 2BD . CD + BD² + CD² [ ∵ given AD² = BD.CD ] = (BD + CD )² = BC²Thus in triangle ABC we have , AB² + AC²= BC² hence triangle ABC is a right triangle right angled at A ∠ BAC = 90° Like my answer if you find it useful! thnku😊 |
|