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1) 210-(-150)=1(360) which are multiple of 360so 210,(-150) are co terminals

2) 360-(-30)=390=3(130)which are notmultiple of 360so 360(-30) are not co terminal angles

1) i) 210-150=210-(-150)=210+150=360, so, 210, (-150) are co terminals;

1)¡) 210-150=210-(-150)=210+150=360, so,210,(-150) are co terminals

Increase of cost 5-4 = 1% of increase = 1/4 × 100 = 25%

Let ABCD be the trapezium in which AB is parallel to DC.

Let AB = 30cm, DC=20 cm,and the non parallel sides AD =6cm and BC = 8cm.

Draw perpendiculars DE and CF from D and C to AB respectively. So DE = CF. DC=EF = 20cm.

Let AE = x cm . Then BF = 10-x.

In right triangle ADE DE^2 = AD^2 - AE^2

In right triangle BCF , CF^2 = BC^2 - BF^2

=> AD^2-AE^2 = BC^2-BF^2

=> 36-x^2 = 64 -(10-x)^2 => 20x = 72 => x=3.6

So DE^2 = 36 - 3.6^2 = 36 - 12.96 =23.04

So DE =√23.04 = 4.8 cm

So area of trapezium = (1/2)h(a+b)

= (1/2)×4.8×(30+20) = 2.4×50 =120cm²

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Total earnings = 160Total expenses= 26 3/5 + 50 1/2 + 16 2/5= 133/5 + 101/2 + 82/5= 215/5 + 101/2= 43 + 101/2= (86 + 101)/2= 187/2 = 93.5

Total savings= 160 - 93.5= Rs 66.5

Let the speed of sailor in still water is x km/hr and the speed of stream is y km/hr.

Now, the speed of boat (upstream) = (x - y) km/hr

and the speed of boat (downstream) = (x + y) km/hr

Now, according to question,

8/(x + y) = 40/60 {Since time = distance/speed}

=> 8/(x + y) = 4/6

=> 4(x + y) = 8*6

=> 4(x + y) = 48

=> x + y = 48/4

=> x + y = 12 ................1

Again, 8/(x - y) = 1

x - y = 8 ...............2

Add equation 1 and 2, we get

2x = 20

=> x = 20/2

=> x = 10

From equation 1, we get

10 + y = 12

=> y = 12 - 10

=> y = 2

Hence, the speed of sailor in still water is 10 km/hr and the speed of stream is 2 km/hr

Thank u so much

2052 metre awayhenceto come back he has to cover same distancehence2*2052=4104metres.

Thank u

Indian national congress was formed on 1885.

Opposite Ray of ray PQ is Ray QP.

thanks

8.5 is correct hoga answer

area=36side=6cm is the best answer

area =36side =6cm is the right answer

Sideofthesquare(a)=6cm

Explanation:

Let thesideofasquare=acm

Areaofthesquare=36cm²

[given]

________________________

Weknowthat,

\boxed{Area \: of \: the \: square \: (A) = a^{2}}Areaofthesquare(A)=a2​

________________________

Now,

=>a²=36cm²

=>a²=(6cm)²

=>a=6cm

Therefore,

Sideofthesquare(A)=6cm

Sideofthesquare(a)=6cm

Explanation:

Let thesideofasquare=acm

Areaofthesquare

________________________

Now,

=>a²=36cm²

=>a²=(6cm)²

=>a=6cm

Therefore,

Sideofthesquare(A)=6cm

area = length x breadth180= 18 x bbreadth = 10cm

perimeter= 2(l + b)= 2 (18+10)= 56cm

correct answer is1/-32

Let the sides of the first square be denoted byx.

Therefore,x²+x²=a²by the Pythagorean theorem

2x²=a²

Therefore, the area of the first square is0.5a²

If the area of the second square is double that of the first square, the area of the second square isa²

Therefore, the sides of the second square has lengthaa.

Therefore, the second square has diagonal of length(2^1/2)a= √2a²

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Let the side of square be x

Area of square = x²

By reducing a side by 2m the side becomes x-2

by increasing the other side by 1m side becomes =x+1

The area of rectangle = (x-2) (x+1)

x²= (x-2) (x+1) + 9

x²= x²+x-2x -2 +9

x²-x2²+x = 7

x=7

Therefore the side of square = 7m

but why did you add 9 over there???

please reply

please reply

Krupa Gopal please answer

Thanks

-1/√2 ,3/√2 the correct answer of the given question

-1/√2,3/√2 is correct answer

( 11CC9 )16

final answer

Area of shaded portion=(5*35)+(5*50)-(5*5)

=175+250-25=425-25=400m²

√625=√25×25=25because 25×25=625

sun rays go on the water And its called water cycle

Every triangle has exactly three medians, one from each vertex, and they all intersect each other at the triangle'scentroid. In the case ofisoscelesandequilateraltriangles, a medianbisects any angleat a vertex whose two adjacent sides are equal in length

(a). x+2=4=>x=4-2=>x=2

(b) x+5=7 => x = 7-5 =>x = 2

x+2=4 x=4-2,x=2 2.x+5=7,x=7-5,x=2

(a) x+2 =4 =x=4-2=x=2

(a)x – 1 = 0

Answer:Step 1: The number 1 will be moved to RHS of equation with suitable change in sign.So, x – 1 = 0Or, x = 0 + 1 = 1

(b)x + 1 = 0

Answer:Step 1: The number 1 will be moved to RHS of equation with suitable change in sign.So, x + 1 = 0Or, x = 0 – 1 = - 1

(c)x – 1 = 5

Answer:The number 1 will be moved to RHS of equation with suitable change in sign.So, x – 1 = 5Or, x = 5 + 1 = 6

(d)x + 6 = 2

Answer:The number 6 will be moved to RHS of equation with suitable change in sign.So, x + 6 = 2Or, x = 2 – 6 = - 4

(e)y – 4 = - 7

Answer:The number 4 will be moved to RHS of equation with suitable change in sign.So, y – 4 = 7Or, y = 7 + 4 = 11

(f)y – 4 = 4

Answer:The number 4 will be moved to RHS of equation with suitable change in sign.So, y – 4 = 4Or, y = 4 + 4 = 8

(g)y + 4 = 4

Answer:The number 4 will be moved to RHS of equation with suitable change in sign.So, y + 4 = 4Or, y = 4 – 4 = 0

(h)y + 4 = - 4

Answer:The number 4 will be moved to RHS of equation with suitable change in sign.So, y + 4 = - 4Or, y = - 4 – 4 = - 8

Adding +1on both sides,X - 1+1=0+1X=1

Daly prashth =12Total prashth = 11980= 11980/12 = 998. 3

=12×11980=143760 ans

637882553 IS A RIGHT ANSWER

143760 is the right answer of this question

Put the valuesx^2-7x+12=0henceroots=-b+-√b^2-4ac/2a=7+-√49-48/2=7+-1/2x=3,4