51. A sailor goes 8 km downstream in 40 minand comes back in 1 h. Find

1.	51. A sailor goes 8 km downstream in 40 minand comes back in 1 h. Find the speed ofsailor in still water and the speed ofCBSE 2010current.
Answer» Let the speed of sailor in still water is x km/hr and the speed of stream is y km/hr. Now, the speed of boat (upstream) = (x - y) km/hr and the speed of boat (downstream) = (x + y) km/hr Now, according to question, 8/(x + y) = 40/60 {Since time = distance/speed} => 8/(x + y) = 4/6 => 4(x + y) = 8*6 => 4(x + y) = 48 => x + y = 48/4 => x + y = 12 ................1 Again, 8/(x - y) = 1 x - y = 8 ...............2 Add equation 1 and 2, we get 2x = 20 => x = 20/2 => x = 10 From equation 1, we get 10 + y = 12 => y = 12 - 10 => y = 2 Hence, the speed of sailor in still water is 10 km/hr and the speed of stream is 2 km/hr Thank u so much

51. A sailor goes 8 km downstream in 40 minand comes back in 1 h. Find the speed ofsailor in still water and the speed ofCBSE 2010current.

Answer»

Let the speed of sailor in still water is x km/hr and the speed of stream is y km/hr.

Now, the speed of boat (upstream) = (x - y) km/hr

and the speed of boat (downstream) = (x + y) km/hr

Now, according to question,

8/(x + y) = 40/60 {Since time = distance/speed}

=> 8/(x + y) = 4/6

=> 4(x + y) = 8*6

=> 4(x + y) = 48

=> x + y = 48/4

=> x + y = 12 ................1

Again, 8/(x - y) = 1

x - y = 8 ...............2

Add equation 1 and 2, we get

2x = 20

=> x = 20/2

=> x = 10

From equation 1, we get

10 + y = 12

=> y = 12 - 10

=> y = 2

Hence, the speed of sailor in still water is 10 km/hr and the speed of stream is 2 km/hr

Thank u so much