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Circumference of a wheel is πD=22/7*98=308cm^2=3.08m^2Hence no of revolutions will be 1540/3.08=500revolutions.

I could be route5 because sin and cos value is equal to 1

Difference = circumference - diameter= 2πr-2r= 302r(π-1)= 30radius = 30/2(π-1)= 7.004cm

let the original cost be xsox + 8% of x = 1242108x/100 = 1242 x = (1242 × 100)/ 108 = 1150so original cost is ₹ 1150

Thank you mam

322m2 is the answer of the question

322 meter square is right answer Like my answer

322 m sq is the best answer.

322 meter is the answer

Let AB and CD be the two poles of equal height and their heights beH m. BC be the 80 m wide road. P be any point on the road. Let CPbe x m, therefore BP = (80 – x) .Also, ∠APB = 60° and ∠DPC = 30°

In right angled triangle DCP,Tan 30° = CD/CP⇒ h/x = 1/√3⇒ h = x/√3 ---------- (1)

In right angled triangle ABP,Tan 60° = AB/AP⇒ h/(80 – x) = √3⇒ h = √3(80 – x)⇒ x/√3 = √3(80 – x)⇒ x = 3(80 – x)⇒ x = 240 – 3x⇒ x + 3x = 240⇒ 4x = 240⇒ x = 60Height of the pole, h = x/√3 = 60/√3 = 20√3.Thus, position of the point P is 60 m from C and height of each pole is 20√3 m.please like the solution 👍 ✔️

6% is correct answer

6% is the correct answer

6℅ is the answer of the question

6 percentis correct answer

6% is the right answer

6%is the correct answer

On A,force = 1.5 Narea = 2 mm^21 mm = 1/1000 m = 0.001m1 mm^2 = 1 mm*1mm = 0.001 m * 0.001 m = 0.000001 m^2 = 10^-6 m^2

P = 1.5N/ (2*10^-6) m^2 = 7.5*10^5 Paon B,P = 1.5N/(6*10^-6) m^2 = 2.5*10^5 Pa

14 degree Celsius because 2*7=14

Brother height = 1.64mSister height =.98mDifference between their heights = 1.64-.98= 0.66To increase height, person should take balanced diet including a lot of green vegetables.

thank you broo

the answer could be option b

Suppose A to be the target and B to be the firing point and let the hearer be at a point P. If V1and V2be the velocity of the sound and bullet respectively, then the time taken by the bullet in reaching from B to the target A = BA/v2and the time taken by the sound in reaching from A to P = AP/v1.

Again the time taken by the sound in reaching from B to P = BP/v1.

As by hypothesis the sound reaches the hearer at P, simultaneously, the time taken by the sound to reach upto the position P from then target together with the time taken by the bullet to reach the target must be same as the time taken by the sound in reaching from the rifle upto P.

Hence BA/v2+ AP/v1= BP/v1

⇒BA/v2= BP/v1– AP/v1= 1/v1(BP – AP)

⇒BP – AP = v1/v2AB

As v1, v2and AB are constants, hence

BP –AP = Constant

Therefore the locus of the point P is the hyperbola having foci at A and B and transverse axis equal to v1/v2AB

I have proved the relationship below.

x/a + y/b + z/c=d; x=da;, y=db; z=dc;____________________(1); x^2/ a^2+y2/b^× + z^2/c^2=( da)^2/a^2 + (mb)^2/ b^2+( mc)^2/c^2= m^2a^3/a^2+ m^3b^3/ b^2+ m^3c^3/ b^2= m^3a+m^3b+ m^3c=m^3(a+b+c)_______(2); ( x+y+z)^3/(a+b+c)^2=( da+dm+dc)^3/(a+b+c)2 = d^3( a+b+c)^3/( a+b+c)^2==m^3(a+b+c)____(3)

Let Raju's age be x. 3x + 5 = 44 3x = 39 x = 13

let raju's age be x 3x + 5 = 44 3x=44-53x=39x=39/3x=13

X = 13 is correct answer

Radius of a garden roller (r) = 1.4 / 2 = 0.7 m

and length of the garden roller (h) = 2 m

∴Curved surface area of garden roller = 2πrh .

So, the area levelled of a garden roller in one revolution is 8.8 m2.

Now, area levelled of a garden in 50 revolutions = 8.8 x 5= 440m2