1.

of all lle UTIu9.The diameter of a garden roller is 1.4 m and itis 2 m long. Find the maximum area coveredby it in 50 revolutions?2A cvlindrical pillars.

Answer»

Radius of a garden roller (r) = 1.4 / 2 = 0.7 m

and length of the garden roller (h) = 2 m

∴Curved surface area of garden roller = 2πrh .

So, the area levelled of a garden roller in one revolution is 8.8 m2.

Now, area levelled of a garden in 50 revolutions = 8.8 x 5= 440m2



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