Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
032 What length of tarpaulin 3m wide will be required to make a conical tent of height 8m and base6m? Assume that the extra length of material that will be required for stitching margins and wastagecutting is approximately 20cm. (use T-3.14) |
| Answer» | |
| 2. |
ages ?(iv)The present age of Sahil's mother is three times thepresent age of Sahil. Afher 5 years ir g veis Fedhenpresent ageslums hased on geometry and mensuration: |
|
Answer» Let present age of sahil is 'x' his mother age is '3x'after five years sahil's age is 'x+5' his mother's age is '3x+5'according to problem, given sum of their ages after five years is 66 ⇒(x+5)+(3x+5)=66 4x+10=66 4x=66-10 4x=56 x=56/4 x=14sahil's age is x=14=14 years sahil's mother age is 3x=3(14)= 42=42years |
|
| 3. |
032 What length of tarpaulin 3m wide will be required to make a conical tent of height 8m and base radius6m? Assume that the extra length of material that will be required for stitching margins and wastage incutting is approximately 20cm. (use r-3.14) |
| Answer» | |
| 4. |
. A cone ot height 24 h ilas Cu0. A tent is in the form of cylinder upto height 3.5 m and conical above it. the base radius is 7m andfull height of tent is 13.5m find the cost of tanvas used for making it at rate rs. 10 per sqmm |
| Answer» | |
| 5. |
If third term of an A.P. is four times of first term and 6th term is 17, find the series. |
| Answer» | |
| 6. |
Q31 Using factor theorem factories: x +13x +322+20032 What length of tarpaulin 3m wide will be required to make a conical tent of height 8m and base radius6m? Assume that the extra length of material that will be required for stitching margins and wastage incutting is approximately 20cm. (use T-3.14) |
| Answer» | |
| 7. |
The square of first number is equal to the cube of second number. The numbers are:(a) 9,3(c) 6, 3(d) 4, 2 |
|
Answer» a² = b³ Substituting 8,4, we get 8² = 64 4³ = 64 So, the answer is option B |
|
| 8. |
A (1, 2, 3), B = (3, 4, 5), then A- B, B-A and An B are(A) Equal SetsC) Null Sets(B) Equivalent Sets(D) Disjoint Sets |
|
Answer» as A-B= 3B-A= 3 and A (intersection) B= 3so all three are equal sets as they have equal and exact same element tnx |
|
| 9. |
4 Show that sin a+B)sin(α+β)sin(α-β)4. Show that-3, given that tan α2 tan β |
|
Answer» sin(A+B)/sin(A-B) (sinA.cosB + cosA.sinB)/(sinA.cosB - cosA.sinB) now divide above and below by cosA.sinB, (tanA.cotB + 1)/(tanA.cotB - 1) now substitute for tanA = 2tanB, (2tanB.cotB + 1)/(2tanB.cotB - 1) (2 + 1)/(2 - 1) (using cotB = 1/tanB) =3 |
|
| 10. |
15. Give an example for disjoint sets? |
|
Answer» a=1,2,3,4b=5,6,7,8a intersection b is equal to zero as nothing is common so they are example of disjoint sets |
|
| 11. |
rcise 1.1Using appropriate properties find.\frac{2}{5} \times\left(-\frac{3}{7}\right)-\frac{1}{6} \times \frac{3}{2}+\frac{1}{14} \times \frac{4}{5} |
|
Answer» 2/3*3/5+5/2-3/5*1/62/5+5/2-3/304+25/10-3/3028/10-3/3028*3/10*3-3/3083/30-3/3081/3027/10 |
|
| 12. |
(4) Show that (e+4).Gr-3) and (r-7 are factors of -6-19x +44. Show thatand (x -/) are factors ox 84 |
| Answer» | |
| 13. |
4. Show that: |
|
Answer» 1/1+×^a/ x^b=1/ x^b+ x^a/ x^b= x^b/ x^b+ x^a_______(1), 1_/1+ x^b-a=1/x^a + x^b/ x^a=x^a_/ x^a+ x^b________(2) ; x^b/ x^b + x^a + x^a/ x^a+ x^b= x^a + x^b/ x^a+ x^b=1 |
|
| 14. |
Find the product and verify the result(1) x^{2} \times 7 x^{6} \times \frac{1}{2} x^{2} \times\left(-3 x^{4}\right), \text { for } x=1 |
|
Answer» put in X=1(1)^2*7(1)^6*1/2(1)^2*(-3(1)^4)1*7*1/2*-3-21/2 thanks |
|
| 15. |
Prakruthi's age is 6 times Sahil's age. After 15 years, Prakruthiwill be 3 times as old as Sahil. Find their age. |
| Answer» | |
| 16. |
. If 6 times the 6th term of an A.P is equal to 11 times its 11th term, then find its 17th term.QR |
| Answer» | |
| 17. |
8. If 6 times the 6th termof an A.P is equal to 11 times its 11th term, then find its 17th term.OR |
| Answer» | |
| 18. |
r =8. If 6 times the 6th term of an A.P is equal to 11 times its 11th term, then find its 17th term. |
|
Answer» First term=a, common difference=d6(a+5d)=11(a+10d)6a+30d=11a+110d5a+80d=0a+16d=0 Now, 17th term is a+16d=0 |
|
| 19. |
(69 - 9+ 1240 рди 290) + (b + 2┬в) |
|
Answer» Thank u |
|
| 20. |
Find the volume of a cone whose radius is 3.5 cm and height is 9 cm(π=22/7) |
|
Answer» volume of a cone = pie*r*r*h/3 = 22/7 * 3.5*3.5*9/3 = 22*0.5*3.5*3 = 115.5 cm*cm*cm |
|
| 21. |
what is the least multiple of 23which when divided by 18, 21 and 24 teaves remainders7, 10 and 13 respectively?(a) 1240(b) 3013(c) 2364d) 7628 |
|
Answer» Here (18 - 7) = 11, (21 - 10) = 11 and (24 - 13) = 11. L.C.M. of 18, 21 and 24 is 504. Let required number be 504k - 11. Least value of k for which (504k - 11) is divisible by 23 is k = 6. ∴Required number = 504 x 6 - 11 = 3024 - 11 = 3013.3013 is the least multiple of 23 |
|
| 22. |
04) Solve any 3 from 4 of the following.The ratio of two numbers is 5:7 If 40 is added in each number, then theratio becomes 25:31 find the numbers.Solution: Let first number = 5x and second number25From the given condition:7x+40 31(5x+40) - 25 (7x+40)155x+1240 +10001240- -175x-155x240 - 20%andThe cumbers areFirst number Second number2. If the mean of the following data is 20.2. then find value of p12320O3010 |
|
Answer» first number=60second number=84 |
|
| 23. |
3Duss find the sum of the reciprocal of (117) to thenegative of 190 ? |
|
Answer» Reciprocal of (-17/9) = - 9/17and negative of - 190/7 is-(-190/7) = 190/7 Now,Sum = - 9/17 + 190/7= (-9*7 + 190*17)/17*7= (-63 + 3230)/119= 3167/119= 26.6 |
|
| 24. |
6 द्वा००+ 4 OB+ “ 3I IF Pl b 1% |
| Answer» | |
| 25. |
find the 60th term of an ap 8,10,12 etc if it has total of 60term and hence find sum of its last ten terms |
|
Answer» a=8,d=10-8=2 60th term=a+(60-1)d=8+(59)2=8+118=126 AP:8,10,12.....120,122,124,126 To find sum of last ten terms, reverse the order of AP 126,124,122,120,.....,12,10,8 Now we have to find sum of first ten terms=(n/2)[2a+(n-1)d]=5[2*126+(10-1)(-2)]=5[252-18]=5(134)=670 |
|
| 26. |
e) Find the dividend when divisor 135, quotient 78 aremainder 29 |
|
Answer» find the dividend when divisor =135,quotient =78 and remainder=29 Find the dividend when the =241, quotient = 135 and the remainder =30. |
|
| 27. |
10-204 Ă 42V0.07x3.4 |
|
Answer» Right bhai |
|
| 28. |
(3) A--7, 5, 2) and B-125, 4, 49.Are the sets A and B equal? Justify your answer. |
| Answer» | |
| 29. |
If A and B are any two sets then A u (A(1) A(3) BB) is equal to(2) AC(4) BC |
|
Answer» AU (anb)=aua=A so common elements present in A itself yes it is A. option 1 A is the right answer |
|
| 30. |
10:35:x:42() |
| Answer» | |
| 31. |
Find the circumference of the circleswithradius:7 cmb 3.5 cmC 14cm |
| Answer» | |
| 32. |
Findthetotalsurface area of a hemisphere of radius 14cm |
|
Answer» thank you mam |
|
| 33. |
Find the surface area of a sphere of radius:(ii) 5.6㎝1.10.5 cm(im) 14cm |
| Answer» | |
| 34. |
Find the volume of a cone whose radius is 7cm and height is 14cm |
|
Answer» V. of cone=1/3pier^2×h=1/3×22/7×7×7+14=1/3×22/7×7×7×14= 22×7×14×1/3=22×98/3=2156/3=718.66 |
|
| 35. |
4, Find the radius of circles whose diameters are-3M꡸a. 9cmb. 14cmc. 15cm |
| Answer» | |
| 36. |
Find the surface area of a sphere of radius:i) 10.5 cmiii) 14cmii) 5.6 cm |
| Answer» | |
| 37. |
. Find the surface area of a sphere of radius:(n) 5.6cm(0 10.5 cmn) 14cm |
| Answer» | |
| 38. |
1. Find the circumference of the circles with the following radius: (Take π--)(a) 14cm(b) 28mm(c) 21em |
| Answer» | |
| 39. |
2 write the reciprocal ofsweitenegativeposlove istegasun is -4.3a.awhose |
|
Answer» 1. Reciprocal of 5/9 is 9/52. Answer is...... = -6 +(+2) = -4-4 is correct answer 😊😊 = -6+2 1.Write the reciprocal of 5/9 =9/52. answer = -12+8 = -4then, answer is -12+8is the correct answer.......... 1)9/52)–5+(1) =–4 ... |
|
| 40. |
2) Ifopposite angles of a Rhombus are 2x and (3x-40) then find the value ofs |
|
Answer» opposite angles of rhombus are equalso2x=3x-403x-2x=40x=40 |
|
| 41. |
दसं-याउ) का योग 21 ॐ परुली।परया का 1 1 )। Ob) 471-5 ठे। दुसरो न्य) का-TLCbJI SE |
|
Answer» 4 is the correct answer of the given question |
|
| 42. |
Example 8 In Fig 8.17. AOBA is the part of the ellipse 9r + y-36 in the firstquadrant such that OA 2 and OB 6. Find the area between the arc AB and thechord AB |
| Answer» | |
| 43. |
3. from the sets given below, selectequal sets and equivalent sets.LA = {0, ab, B={1,2,3,49 C:{4,8,123ID={3, 1,2,4} E ={10}, F={8,4,129G={1,5,7, 113, H={a,b} |
| Answer» | |
| 44. |
1 Are equal sets equivalent sets? What about converse |
| Answer» | |
| 45. |
Find six diferent solutions of the equation x +2y-6. |
|
Answer» When1)x=2 y=22+2*2=2+4=62)X=0 y=30+2*3=6=63)X=6 y=06=64)X=1 y=5/21+2*5/2=6=65)X=4 Y=14+2=6=6 |
|
| 46. |
12 + 22 +32 +42+.... 10) ?(A) 330(C) 365ge345(D) 385 |
| Answer» | |
| 47. |
3/2The value of 92 s |
| Answer» | |
| 48. |
3. How many chords can be drawn through 21 points on a circle?4. In how many ways can a team of h |
| Answer» | |
| 49. |
s. Find throc diferent itrational numbers between the rational nomberiand i |
|
Answer» 5/7=0.7142 9/11=0.818181first we have to change the the number into decimal or rationaldecimal form of 5/7 is 0.71428571 and the decimal form of 9/11 is 81818181hence the rational number are between 0.71428571 and 0.81818181 rational numbers between 5/7 and 9/11 1) 0.724285712)0.734285713)0.74428571 . . . .upto 0.80818181 |
|
| 50. |
The least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29 and 34respectively is |
|
Answer» LCM of 20, 25, 35, and 40 = 1400 Now, 20 - 6 = 14 25 - 6 = 19 35 - 6 = 29 40 - 6 = 34 The difference is of 6 Now , taking LCM (20,25,35,40) We get, 5* 5* 2*2*2*7 = 1400 So, the value will be 1400 – 6 = 1394 ans |
|