1.

find the 60th term of an ap 8,10,12 etc if it has total of 60term and hence find sum of its last ten terms

Answer»

a=8,d=10-8=2

60th term=a+(60-1)d=8+(59)2=8+118=126

AP:8,10,12.....120,122,124,126

To find sum of last ten terms, reverse the order of AP

126,124,122,120,.....,12,10,8

Now we have to find sum of first ten terms=(n/2)[2a+(n-1)d]=5[2*126+(10-1)(-2)]=5[252-18]=5(134)=670



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