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First multiply 16 with 18 to get 288 .Then xy × xy to get xy whole square.So the answer is 288 (xy)whole square

area of rhombus is 1/2×BD×AC

8^-1*5^3 ÷ 2^-4 = (2)^-3 * 125 * (2)^4= (2)^[-3+4]*125= 125*2= 250 ans

Degree of polynomial is higehst power of the polynomial .

Observe the terms x power 5 , x , and 1

When they multiplied we get the highest power.

So, degree of polynomial is 6

Please post complete question

(-8)×[5+(-5)]=-8×0(+5&-5will be cancelled)0(anything mutiplied with 0 =0

tq

Thanks

write three terms of the GP when the first term a and the common ratio r are given a=4;r=3

the sum of infinite terms is given by a/1-rhere, first term, a=-3common ratio, r=-6/-3=2so, sum=-3/1-2=3so it's true

A= -22 B= -207C = -357

answer no. (a) is -21(b) = -207(c) = -357(d) =26

(a) -22(b) -207(c)-357(d) 25

-22-207-35725....

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1/(root(3) + root(2)) - 2/(root(5) - root(3)) - 3/root(2) - root(5)

Rationalise all terms separately

= (root(3)+root(2))^2 /(3 - 2) - 2(root(5) - root(3))^2/(5-3) - 3(root(2) - root(5))/(2 - 5)

= [3 + 2 + 2root(6) - (5 + 3 - 2root(15)) + (2 + 5 - 2root(10))]

= 5 + 2root(6) - 8 + 2root(15) + 7 - 2root(10)

= 4 + 2root(6) - 2root(10) + 2root(15)

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(-37) I think so.......

-37 is the correct answer of the given

-37 is correct answer of this question.

1)√3/2+i*1/22)1/2+i*√3/23)5/2(cos(270+30)+isin30)5/2(√3/2+i*1/2)5√3/4+i*5/4

suppose parts are x and 51-xso x(51-x)=37851x-x^2=378x^2-51x+378=0(x-42)(x-9)=0so x=9 or 42so parts are 9 and 42

thanks for the answer

I think 56 is the correct answer

-30 is the correct answer of the following question

a. -30 = 30(-30) × 30 = (-1)b. 56 = (-56)56 × (-56) = (-1)

-30 is correct answer of 1st question

_ 30 age correct answer..........

i) f(x) = [x], for all x in R ==> By the definition of greatest integer function: If x lies between two successive integers, then f(x) = least integer of them.

ii) So, at x = 2, f(x) = [2] = 2 -------- (1)

Left side limit (x ---> 2-h): f(x) = [2 - h] = 1 ----- (2) {Since (2 - h) lies between 1 & 2; and the least being 1}

Right side limit (x --> 2+h): f(x) = [2 + h] = 2 -------- (3) {Since (2+h) lies between 2 & 3; and the least being 2}

iii) Thus from the above 3 equations, left side limit is not equal to right side limit. So limit of the function does not exist. Hence it is discontinuous at x = 2 So this is not derivable at x = 2 Hence Proved.

6x = 12 so x = 2 x/4 = 8 so x = 32

tan^2x+cot^2x = 2

∴tan^2x+1/tan^2x+2 = 2+2

∴(tanx+1/tanx)^2 = 4

∴(sinx/cosx+cosx/sinx)^2 = 4

∴(sin^2x+cos^2x/sinxcosx)^2 = 4

∴1/sin^2x. cos^2x = 4

∴x = nπ/2−π/4(n∈Z)

Therefore,Value of tan^3 x + cot^2 x= tan^3 π/4 + cot^2 π/4= 1 + 1 = 2

Let the first term be a ,The common difference be d .Then the sum of first three terms = a+a+d+a+2d = 3a+3d .

Given 3(a+d) = 33

=> a+d = 11 .

=> d =11-a

Therefore ,Second term of A.P = 11 .

The product of first and third terms = (a)(a+2d) = a(a+2(11-a)

= a(a+22-2a)

= a(22-a)

= 22a-a²

ATQ --->

Given 22a-a²-29= a+d

=> 22a-a²-29=11

=> 22a-a² -40 =0

=> a²-22a+40=0

=> a²-20a-2a+40=0

=> a(a-20)-2(a-20) =0

=> a= 2 or 20.

Finding common difference for a = 211-2=9

Finding Common difference for a =2011-20=-9 .

Now The possible A .P 's are 1) 2,11,20,29,38,47,56,65,74.....2) 20,11,2,-7,-16,-25,-34,-43,-52,-61,-70 .......

1.-5, 2.-7,3.-4, 4.-11

C (2) is the correct answer.

2 is the best answer

Let A=45, B=30

b is the best answer

2 is the correct answer

option b is the correct answer

sin(A+B)=sinAcosB+cosAsinAA=45, B= 30°sin(75)=(sin45+30)=sin45 cos30+ cos45 sin30=1/√2(√3/2)+1/√2×1/2= √3/2√2+1/2√2=(√3+1)/2√2option b is right

(c) is the correct answer

b. √3+1/2√2 the correct answer

c is the right answers

(d) 2√2 answer your question

c.(2) is the right answer

यदि आप एक घूर्णन समन्वय प्रणाली में स्विच करते हैं जिसमें घंटे का हाथ स्थिर रहता है, तो मिनट का हाथ केवल 11 चक्कर लगाता है, और इसलिए यह 22 घंटे के हाथ के साथ समकोण पर है। 24 घंटे के दिन में आपको 2 × 22 = 44 मिलते हैं। गणितीय रूप से, इसे निम्न प्रकार से किया जा सकता है: मिनट का हाथ 60 मिनट में 360 डिग्री चलता है

Option AasK is the next word

The answer is K option b

Let the common ratio be xPresent age of Maya= 6xPresent age of Shadow =5xAge of Maya after 15years=6x+15Age of Shadow after 15 years=5x+15Ratio of their ages after 15 years =9:4According to the problem,(6x+15)/(5x+15)=9/4Solve the equationAfter getting x multiply it by 6.That is maya age.

=B2, C3, D4, E5, F6, G7, H8, I9=B +1 =C=C +2 =E=E +2=G=G +2=I......(C)