This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In ΔABC, LA120° and 22.B = 310. Find LB and LC |
| Answer» | |
| 2. |
8.8suply and almost be sent in pelo sijunaexpress the result in positive exponents:а) 4x 4- |
|
Answer» (y^6/x^3)^1/3/= x^2; ( x6/y)^1/3=x^2/y^3; x^2 x x^2/y^3==2 x^2/y^3 |
|
| 3. |
5. The product of two numbers is 504347. If one of the numbers is 317, find the other.Lequotient is 130 and the remainder is 37 Find |
| Answer» | |
| 4. |
2, The sum l Iree coto3. Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.third nf its succeeding number. Find |
|
Answer» Let the number be x.So, the other number is (x + 15) because x-y=15.(x + 15) + x = 95 2x + 15 = 952x = 95 - 152x = 80x = 40So, the numbers are 40 and 55. |
|
| 5. |
bulat l SCL Il Cipucur15. The product of two numbers is 15, find the other. |
|
Answer» thanks |
|
| 6. |
\begin{array} { l } { \text { Two numbers differ by } 3 . \text { The sum of twice } } \\ { \text { the smaller number and thrice the greater } } \\ { \text { number is } 19 \text { . Find the numbers. } } \end{array} |
| Answer» | |
| 7. |
Prove that the product of 2nd and 3rd terms of an AP exceeds the product of 1st and 4th termsby twice the square of the difference between the 1st and 2nd terms. |
|
Answer» Let the A.P. be a, a + d, a + 2d, ..... Here, we have to prove: T2T3- T1T4= 2(T1- T2)^2 Proof: We know that, Tn= a + (n - 1)d LHS = T2T3- T1T4 = (a + d)(a + 2d) - a(a + 3d) = a^2+ ad + 2ad + 2d^2- a^2- 3ad = 2d^2 Now, RHS = 2(T1- T2)^2 = 2(a - (a + d))^2 = 2 (a - a - d)^2 = 2d^2 Hence, LHS = RHS |
|
| 8. |
If the coefficients of 2nd, 3rd and 4th terms inthe expansion of (1 + x)" are in A.P., then thevalue of n is |
| Answer» | |
| 9. |
In each of the following two configurations ofmatchsticks, move a single matchstick to formvalid equations. |
|
Answer» The first one is V+I=VI,The second is VII -I =VI |
|
| 10. |
EXERCISE 4.3Draw the graph of each of the following linear equations in two variables:(iii) y#3xll) y-(iv) 3 2r+yGive the equations of two lines passing through (2, 14). Howare there, and why? |
|
Answer» part 1 part 2 |
|
| 11. |
LULUsent 4.7 geometrically on the number line.Represent 4.7 .1: |
| Answer» | |
| 12. |
Karnataka cm |
|
Answer» The incumbent chief minister is the Janata Dal (Secular)'s H. D.Kumaraswamy, who was sworn in on 23 May 2018. |
|
| 13. |
x + 25-x) |
| Answer» | |
| 14. |
AB||ICD, ZADC &1 ¢A |
|
Answer» Angle BDC = 55°so Angle ADC will be60+55= 115° |
|
| 15. |
EXERCISE 7.2Find the cube root of each of the following numbers by prime facton(i) 64(V) 15625(ix) 1756161.(iii) 10648(vii) 110592ba(i) 512(vi) 13824(x) 91125(iv)(vi)ic |
| Answer» | |
| 16. |
EXERCISE 6.2In Fig. 6.28, find the values of x and y and thenshow that AB ICD500什一一一r.c130Fig. 6.28 |
|
Answer» x + 50° = 180°x = 130° y = 130° (vertically opposite angle) |
|
| 17. |
3Q7. AB| ICD Determine <A |
|
Answer» Angle A is equals to 93°. |
|
| 18. |
7. Find x and y if AB ICD EF |
| Answer» | |
| 19. |
[+०09509+00६ प[5o0€ SO0 +,09 uIso0E UL} -,09 UE) + |_ ०0६ ण४३-०09पण .-भीईि00 >> (= |
|
Answer» tan60=√3 tan30=1/√3hence√3-1/√3/1+√3*1/√3=3-1/√3/2=1/√3=tan30° |
|
| 20. |
5 209 + «09 09 + «0६ 0389 0 s g s Y |
| Answer» | |
| 21. |
(c) is equal to mond) Is is equal to mo |
|
Answer» yes,no is the best answer 4/5=16/201/15not equal to 4/30 yes, no is the correct answer of the given question. |
|
| 22. |
xsqure+x+2 then find derivative |
| Answer» | |
| 23. |
aly namfacton ofo) then pCa |
|
Answer» Yes, if (x - a) is factor of polynomial p(x)then p(a) is 0, this is application of remainder theorem. |
|
| 24. |
X+X+25=100 |
|
Answer» x+x+25=1002x+25=1002x=100-252x=75x=75/2x=37.5is the correct answer |
|
| 25. |
200 x 25 /100 |
| Answer» | |
| 26. |
25 x - 1 = 5 ^ { 2 x - 1 } - 100 |
| Answer» | |
| 27. |
Question number to 13 aly I mONDExpress 1.27 in the form p/q, where p & q are integers and q is not equal to 0. |
|
Answer» (1) x = 1.2727272727......... (2) 100x = 127.27272727......... From subtracting(1) and(2) We get : 99x = 126.0000000 x = 126/99 = 14/11. |
|
| 28. |
200 x 25 / 100 |
| Answer» | |
| 29. |
800 x 25% / 100 |
| Answer» | |
| 30. |
. Vani saves her money in a bank. Shesaved 12,500 for three years. The bankgives 12.5% interest. How much moneyshe will get in total after three years? |
|
Answer» Interest = 12500*12.5*3/100 = 4687.5 Total = 12500 + 4687.5 = 17187.5 |
|
| 31. |
raw data |
|
Answer» Raw data(sometimes called sourcedataor atomicdata) isdatathat has not been processed for use. |
|
| 32. |
What is the solution to the system of equations represented by these two lines?(3,1)(3.0)(1.3)(0.6) |
|
Answer» (1,3) Answer and (1,3) 1,3 is the answers of this question 1,3 is the right answer 1;3 is the correct answer |
|
| 33. |
1+sin2x-cos2x/1+sin2x+cos 2x=tan x |
|
Answer» Hello buddy.. sin2x / (1+cos2x) = tanx We will use trigonometric identities to solve. We will start from the left side and prove the right side. ==> we know that: sin2x - 2sinx*cosx cos2x = 2cos^2 x -1 I will substitute. ==> sin2x / (1+ cos2x) = 2sinx*cosx / (1+ 2cos^2 x -1) = 2sinx*cosx/ 2cos^2 x We will reduce similar. ==> sin2x / (1+ cos2x) = sinx/cosx But we know that tanx = sinx/cosx ==> sin2x / (1+ cos2x) = tanx........... Hope it helps you buddy hey thnx well I was knowing it but trying the app.... |
|
| 34. |
Sin2x |
|
Answer» 2sinxcosx is the right answer sin2x can be written as cos(90-2x)and it can also be written as 2 sinx cosx thank you 2 sinxcosx is the right answer.... sin2x = cos(90-2x) cos(90-2x)= 2sinx cosx2sinx cosx is the right answer |
|
| 35. |
4sin 8 —3cos®5. Iftan 0 = e then find the value of . जपना |
|
Answer» thx |
|
| 36. |
Iftan A= cot B, prove that A + B = 90。 |
|
Answer» tanA=cotB i.e., tanA=tan(90-B) i.e., A=90-B i.e.,A+B=90 |
|
| 37. |
sin2x - 2cosxsinx |
|
Answer» sin2x=2sinxcosxthen2sinxcox-2cosxsinx=0 |
|
| 38. |
Qu.Ans:R = 100%.T = 224 = 2.stearsIz 10250S.I - PRxtlooP=S. I x 1oooRxt-= 10250 x 1002.5x16= 10250 x 10025,P=241,000 |
|
Answer» 41000 is correct answer. 41000 is 100% guaranteed correct answer 41000 is the right answer 41000 is the right answer for this question |
|
| 39. |
v2-1, then find the value of 1 taanzgİftan θ1 + tan2 θ |
| Answer» | |
| 40. |
Iftan θ+sin θ= m and tan θ-sin θ= n , show thatm2-n3 = 4imn |
| Answer» | |
| 41. |
डक L J_(Mg,__flz__w i el P L 4 «किटe Lo é L j%n afive detm] T ot T हद |
| Answer» | |
| 42. |
ह ) Prorve ot Lo patnis C o0l ,064) andl=d,3) shtoमा श्र i mjfi Atcells DRnpen o g S |
| Answer» | |
| 43. |
Worksheetot. Say whether each of the following in an expression oran equationa)-7x:(2x-1=6:c) 7a+ab:d) 9a tl-lo= : |
|
Answer» (a)-expression(b)-equation(c)-expression(d)-equation a expression b equation c expression d equation a) expressionb) equationc) expressiond) equation |
|
| 44. |
lo b two equal chards ot a cixcle intersect within the circle, provethet the segments obsegments ob the other chorelohe chord are equal to correspondingCu |
|
Answer» In ΔAOM and ΔDOMOA = OD (radii)OM = OM (common side)So, ΔAOM ≈ Δ DOMHence, AM = DM provedIt is given that AB = CDSo, AB – AM = CD – DMOr, CM = BM proved |
|
| 45. |
\int _ { 0 } ^ 1 { \frac { \log ( 1 + x ) } { 1 + x ^ { 2 } } d x } = \frac { \pi } { 8 } \log 2 |
|
Answer» no clarety open it it's a clear picture thanks |
|
| 46. |
526What should be added toto get |
| Answer» | |
| 47. |
. Show that there are infinitely many positive prime numbers. |
|
Answer» Let there be finite number of positive prime numbera1,a2,a3.......,an. Such thata1<a2<a3< .......an+<an. Letm= 1 + a1,a2,a3.......,an. It is near thata1,a2,a3.......,anis divisible bya1,a2,a3.......,an. mis a prime number or it has factors other thana1,a2,a3.......,an. There exits a positive prime number other thana1,a2,a3.......,an. This contradicts the fact that there are finite number of positive primes. Hence, there infinite number of positive primes. |
|
| 48. |
What is the number of straight lines in the following figure?(a) 1114(c) 16(d) 17 |
|
Answer» 5 ( vertical) 3( horz)2 ( diagonal) 4 ( mid of sides to mid of sides) = 14. |
|
| 49. |
If the system of equations2x + 3y = 72ax + (a + b)y = 28has infinitely many solution |
|
Answer» L1=2X + 3Y=7, L2=2ax+ ( a+b)y=28; ratio of cofficent of x= ratio of cofficent of y; 2/2a=3/(a+b)=7/28; 1/a=3/( a+b)=1/4, a=4; 12= a + b; 12-a=b; 12-4=b=8; a=4; b=8 |
|
| 50. |
\operatorname { log } _ { 2 } ( 25 ^ { x + 3 } - 1 ) = 2 + \operatorname { log } _ { 2 } ( 5 ^ { x + 3 } + 1 ) |
| Answer» | |