\int _ { 0 } ^ 1 { \frac { \log ( 1 + x ) } { 1 + x ^ { 2 } } d x } = – InterviewSolution

1.

\int _ { 0 } ^ 1 { \frac { \log ( 1 + x ) } { 1 + x ^ { 2 } } d x } = \frac { \pi } { 8 } \log 2

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no clarety

open it it's a clear picture

thanks

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