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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the mean salary of, 18, 14,23, 22, 14, 18.of a0 workers of a factory from the following table:Salary (in)Number of workers161210600070008000900010000Total460 |
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| 2. |
Solve the following equations.1. x - 2 = 72. y + 3 = 103. 6=z+2 |
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Answer» 1. x-2=7=> x=7+2x=92. y+3=10=> y=10-3=> y= 73. 6=z+2=> z+2=6=> z= 6-2=>z= 4MARK AS THE BEST ANSWER PLEASE. 1. x-2=7x=2+7x=92. y+3=10y=10-3y=73. 6=z+2z=6-2z=4 answer 1.=x=92. 73. 4 1. x-2=7 x=7+2 x=92. y+3=10 y=10-3 y=73. 6=z+2 z=6-2 z=4 1)x-2=7 •X=7+2X=92)y+3=10•y=10-3y=7 1. x=92. y=73. z=4 1 x=9 2 y=7 3 z= 4 plz like my answer 1. x=7+2 x=9 2.y=10-3y=7 (a)=9(b)=7(c)=4please like my answers 1 x-2 =7 x=7+2 x=9 2 y+3=10 y=10-3 y=7 3 6=z+2 6-2=z 4=z =x=7+2=x=9 =y=10-3=y=7 =6=z+2=z go in place of 6 and 6 go in place of z =-z=-6+ 2=-+=- so 6-2=-4=-z=-4=- was cut -=z=4 x-2=7x=7+2x=9 y+3=10y=10-3y=7 x-2=7x=7+2x=9 y+3=10y=10-3y=7 6=z+26-2=z4=z 1.x=7+2 =92. y= 10-3 = 73. 6- 2 = z 4 = 1.) x= 92.) y=73.) z= 4 1) x=7+2=9 so x=9 (2)y=10-3=7so x=7 (3) z= 6-2=4 so z=4 answer1.=×=92.73.4 1.x-2=7=x-2-7=0=x-9=0=x=92.y+3=10=y+3-10=0=y-7=0=y=63.6=z+2=z+2=6=z+2-6=0=x-4=0=z=4 x - 2 = 7x. =7+2x. =9 y+3=10y. =10-3y. =7 6=z+26+2 = z8. =z x-2=7x = 7+2thus, x =9 y + 3= 10y = 10 - 3thus, y =7 6 = z + 26 - 2 = zthus, 4 = z 1) x-2=7x=7+2x=9 2) y+3=10y=10-3y=7 3) 6=z+26-2=z4=zz=4 X=7+2 so x = 9Y =10-3 so y= 7Z= 6-2 so z =4 1ka x=9, 2ka y=7, z=-4 1. x=7+2=92. x=10-3=73. z=6-2=4 1 x - 2=7x = 7 - 2x = 5 1. 52. 83. 4this is the answer of this question 1=x=7+2 : 2=y=7: 3=z=-4 X-2=7x=7+2x=9 y+3=10y=10-3y=7 6=z+26-2=zz=4... (i) x - 2 = 7 x = 7 + 2x =9Ans(ii)y + 3 =10y=10-3y=7Ans(iii) 6 = z + 2z = 6-2z=4Ans if answer is right👍 like the answe 1. x-2=7=>x=7+2=>x=92. y+3=10=>y=10-3=>y=73. 6=z+2=>z=-6+2=>z=-4 1. x-2=7x=7+2=9 1. x-2=7x=7+2x=9 2. y+3=10y=10-3y=7 3. 6 = z+2z+2=6z=6-2z= 4 1 x-2=7 x= 7+2 x= 9 2 y+3=10 y= 10-3 y= 7 3. 6=z+2 z+2= 6 z= 6-2 z= 4 x=9. y=7. z=4 ( 1) x=9 (2) y=7 (3) z=4 1) X - 2 =7 X =7+2 X=9✓ 2) y+3=10 y = 10-3 y =7✓ 3) 6=z+2 z= 6-2 z=4✓ q.no 1 x-2=7x=7+2x=9 ans q.no 2 y+3=10y=10-3y=7ans q.no 3 6=z+26-2=zz=4 ans 1. x-2=7x= 7+2x= 9 ans 2. y+3=10y= 10-3y= 7 ans 3. 6= z+2z= 2-6z= -4 ans x=9 a x =7 x=4 hope it helps 1 x= 92. y=73. z=4 x-2=7x=7+2x=9 9-2=7 answer of 1 is -5answer of 2 is 7answer of 3 is -4 1) 92) 73) 4these are the answers to your questions 🙂 ×-2=7=>×=7+2=9=>×=9 |
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| 3. |
(a) in an examination, 29,456 candidates passed while 57,281 candidatesfailed. How many candidates appeared for the examination? |
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Answer» 27825 is the answer for the question 29,456+57,281=85106 candidate appeared for the examination 86737 number of candidates appear in the exam 2 9, 4 5 6 + 5 7, 2 8 1 = 8 5106 The correct answer is 86'737 candidates 85106 candidate were applied. And please make it as best |
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| 4. |
. In an examination. 965. of the candidates passed. If 2272 candidates failed, howcandidates appeared for the examination and how many passed? |
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Answer» the right answer is 54528 student s passed |
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| 5. |
Solve the following equations.1. r-2= 7 |
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Answer» 9 x - 2 = 7x = 7 + 2 = 9 x-2=7x=7+2x=9अब मान बैठाने पर,9-2=77=7 ansx=9 x - 2 = 7 x = 7 + 2 x = 9 |
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| 6. |
63. If 4 4(1) 32(3) 5-24, then the value of 2x is(2) 512(4) of these |
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| 7. |
Find the principal and general solutions of thefollowing equations:1. tanxv3 |
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Answer» tan x =√3 We know thattanπ/3=√3 tan(π+π/3)=tanπ/3= √3 ⇒tan4π/3 ∴ tanπ3=tan4π/3= √3 ∴Principal solutions areπ/3,4π/3 Iftanx = tanπ/3 ∴General solution:x=nπ+π/3wheren∈z |
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| 8. |
gp+x a+gp )= X |
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Answer» hit like if you find it useful |
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| 9. |
2= X, 8 GP. & 'x |
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Answer» We know when a,b,c are in GP Then, b² = ac So, here x² = (-2)/7 × (-7)/2 x² = 1 So, x = 1 or -1 |
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| 10. |
GP=x+2,x+6 then value of xis |
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Answer» x , x + 2 , x + 6 are three consecutive terms in G. P Therefore , ( x + 2 )² = x ( x + 6 ) x² + 4x + 4 = x² + 6x 4 = 6x - 4x 4 = 2x 2 = x x = 2 |
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| 11. |
(C) 2For some data Z-Mdata is 20, then Z(D) 2.52.5. If the mean of the3.14.(B) 22.75 |
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Answer» If mean of data= 20Z-M=2.5Z-20=2.5Z=22.5 |
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| 12. |
187310. Some observations are arranged in the ascending order as9, a 3, a 7, 20, 23 and 26. If median of the data is18.5, find the value of.a. Also find the mean of the data |
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Answer» 9, a + 3, a + 7, 20, 23, 26are in ascending order and number of terms are 6 So median= 1/2( 3rd + 4th terms)= 1/2 *(a + 7 + 20)= (a + 27)/2 So,(a + 27)/2 = 18.5a + 27 = 37a = 37 - 27 = 10 Now values are9, 13, 17, 20, 23, 26 Mean = (9+13+17+23+26)/6 = 88/6 = 14.6 |
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| 13. |
IAns. Hence, 3 decimal places.]0.9. A survey was conducted by a group of students to collect the data regarding the number ofplarts in 10 houses of a locality which is as follows:10, 5, 2, 0, 4, 7, 1, 3, 12, 3Find the median of the data. |
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Answer» thanks |
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| 14. |
If, x, 5 are in GP then find the value of 'x'. |
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Answer» If they are in gpso x= √ 5*1/5= 1as for three numbers a, b, cb=√ac |
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| 15. |
ORIfa, b, c are in GP. andprove that x, y, z are in A |
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| 16. |
s. Solve the following equations(a) 2x +4 24 h2x+7 |
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| 17. |
Solve the following equations:1.7x-5=2x |
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Answer» 7x - 5 = 2x7x - 2x = 55x = 5x = 1 |
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| 18. |
ik iz (P) AT४ (को ही (®)८ है फुल >कृह >>8 DI & DA%) DIBE |3 1P 2y 1o %S e %CE BRI “%0T 2 %0EBED ‘%GT e %ST Wah ‘28 S I MoK kP ०2 29 6B अल |
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| 19. |
Solve the following equations1. 2x+1=5 |
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| 20. |
3 Solve the following equations.(i) 2x -1 = 4 |
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Answer» 2x-1=42x=4+12x=5X=5/2. Or x=2.5 x=2.5 is a correct answer 2x-1=42x=4+1=5x=5/2 or 2.5 2x - 1 = 4; 2x = 5:; x = 5/2 2x-1=42x=3X=3/2 answer 2x-1=142x=142x=15x=15/2x=7.5 2x-1=42x=4+12x=5x=2/5x=2.5 I) 2x-1=42x=4+12x=5x= 5/2 answer 2x-1= 42x= 4+12x=5x= 5/2x= 2.5 x=2.5 is the correct answer 2x-1=42x=4+12x=5x=5/2x=2.5 is the correct at |
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| 21. |
The cost of a pair of shoes is 450. The sales tax charged was 6%. Find the billamount. |
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| 22. |
the cost of a pair of shoes is Rs 450 the sales tax charged was 5percent. Find bill amount |
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| 23. |
The price of a TV is 13,000. The sales tax charged onit is at the rate of 12%. Find the amount that Vinod willhave to pay if he buys it. |
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| 24. |
The cost price of a pen is 19 and the selling price is ? 24. Is there a gainor loss? How much? |
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| 25. |
6 x 32 x 35 |
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Answer» (1/3)^3 * (3)^-2 * (3)^5 = (3)^-3 * (3)^-2 * (3)^5 = (3)^[-3 - 2 + 5] = (3)^[5 - 5] = (3)^0 = 1 |
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| 26. |
.The price of a TV ist 13,000. The sales tax charged onit is at the rate of 1 2%. Find the amount thatVinod willhave to pay if he buys it. |
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| 27. |
arithmetic mean of the observations from the data 3, 4, 6, 8, 14, x y is 5, then the value of sum isA) 35 (B) 32 (C) 36 (D) 33 |
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Answer» Arithmetic mean = sum of all the number/total number5 = sum of all number/7sum of all number = 5*7 = 35 |
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| 28. |
The price of a TV is Rs. 20,000. The sales tax charged on it is at therate of 12%. Find the amount that Vinod will have to pay ifhe buysit. |
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Answer» no price is 20000 price=20000tax is 12%so amount need to pay=(1.12)*20000=22400 |
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| 29. |
15th term of AP x-7, x-2, x+3, ....is: |
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| 30. |
Find the nth term of the GPX X-X2'4'8' |
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Answer» Tn= ar^n-1a= x/2r= x/4*2/x= 1/2x/2(1/2)^n-1 |
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| 31. |
The price of a TV is R 13,000. The sales tax charged onit is at the rate of 12%. Find the amount that Vinod willhave to pay if he buys it. |
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| 32. |
The price of a TV ist 13,000. The sales tax charged onit is at the rate of 12%. Find the amount thafVinod willhave to pay ifhe buys it.8.2086 Ifthe |
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| 33. |
The first 3 terms of Ap are 3y-1 3y+5 5y+1 respectively Find the value of y |
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Answer» In AP : Difference b/w successive terms=constant Therefore,3y+5-(3y-1)=5y+1-(3y+5) 3y+5-3y+1=5y+1-3y-5 6=2y-4 10=2y Therefore,y=5 |
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| 34. |
pÄrceHtageQ28.lf the cost price of 6 pen is equal to selling price of 5 pen. Find the gainpercentcimnla interest in |
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| 35. |
62. Show that the vectors 2i -3j+4k and -4i+ 6j-8k are collinea |
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| 36. |
Ifthe vectors 2i+j-k and i+4j+λ k are perpendicular, then λ(a) 4 (b)-5 (c) 2 (d) 1: |
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Answer» not complete |
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| 37. |
T II m, p is the transversal intersecting / and m. If 41 2x(b) 68(d) 3815° and 45x+ 40 thax equals(a) 25o1°5(c) 55°1°m.71 6 |
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| 38. |
What should be the value of a if the value of 2x^3 +x-a equals to 59. |
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Answer» when X=0then 2*0+0-a=5hence a=-5 |
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| 39. |
Jatin buys books for 1,350 and a pen for325. He makes a profit of 400 on selling thebooks and a loss of 100 on selling the pen.a. What is his total selling price?b. What is his profit or loss on the whole? |
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Answer» bxj xj jxj jxj jxj jxj jxj jcjcjjcj c 4999 is the correct answer |
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| 40. |
-3 x 2 35 6/35- 6 x 5.916 35.5 m2 (appr |
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Answer» 3 × 2√35 = 6√35 = 6×5.916 = 35.5 m*m (approx) |
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| 41. |
The cost price of 19 articles is equal to the selling price of 16 articles. Gain |
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| 42. |
(-2)x 356 x 3² |
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| 43. |
(-2)4 x 356 x 32 |
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| 44. |
(3/4)*(5/9 %2B (24/35)/((6/7))) |
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| 45. |
Solve for and if + C) => (35-6)Solve for x and y if x+ y |
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| 46. |
The x term of a pattern is given by3. Find the difference between thesixth and the ninth terms. |
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| 47. |
Question 2(a) A number pattern is given by the rule: T = 350 - 8n, where T is the term in thenumber pattern and n is the number of the term. Find:() the first 3 terms(ii) the 20th term(iii) the 45th term.[3+1+(b) Refer to the given figure. O is the centre of the circle. Fill in the blanks in thefollowing:(i) PQ is a of the circle.(ii) OC is a of the circle.(iii) QC is a of the circle.(iv) POC is a of the circle.(v) Line RQ is a of the circle.Question 2 |
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Answer» i) 342,334,326ii) 190iii)-10 (1) diameter(2) radius(3)chord(4) center angle(5) line segment with chord |
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| 48. |
Expressas a rational number with denominator 7. |
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Answer» hi how are you. hi to hell |
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| 49. |
ही + है =1+sec® cosec 01-cot® 1-tan 0संकेत: व्यंजक को अ० 6 और ००४९ के पदों में 1% |
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| 50. |
- ,:. hat1-cos9— (cosec 0 —cot 0)°1 + 00590 |
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Answer» (1-cos x)/(1+cos x)=(cosec x-cot x)^2 L.H.S. =(1-cos x)×(1-cos x)/(1+cos x)×(1-cos x) =(1-cos x)^2/(1-cos^2x) =(1-cos x)^2/(sin x)^2 =[(1-cos x)/sin x]^2 =[1/sin x - cos x/sin x]^2 =(cosec x- cot x)^2 Hence Proved. |
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