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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
है रिवकछावो८ e f\\nc denome ngtoy 0 जि 8) वि4 Vi = 42 आओ . डिनर )S VS -3 पड भा, |
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Answer» 1) 2/3√3multiply numerator and denominator by √3= 3√3/9 2)√40/√3 multiply numerator and denominator by √3=2√30/3 3)(3+√2)/4√2multiply numerator and denominator by √2=(3√2 + 2)/8 |
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| 2. |
(xi) Write the expression in the simplest form: sec 0 - -cosec 0-1 |
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Answer» cosec^2A-1=cot^2Ahencesec^2A-1/cot^2Asec^2Acot^2A-1/cot^2Acosec^2A-1/cot^2A=1as secA=1/cosAhencesecAcotA=1/sinA=cosecA cosec^2A_1=cot^2A hencesec^2A-1/cot^2Asec^2A_1/cot^2A_1/cot^2Acosec^2A_1/cot^2A=1as secA =1/cosAhencesecAcotA=1/sinA=cosecA |
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| 3. |
If mi,m2,m3,m4 are respectively themagnitude of the vectors 2i-j+k,3i-4j-4k,i +j-k,-i+3j+k then thecorrect order of m,m2,m3,m4 is |
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| 4. |
x-124, then (2x)' equals |
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| 5. |
1. Expressas a rational number with denominator 7 |
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Answer» -3/7 is the correct answer of the given question -3/5 is the answer for this |
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| 6. |
-42press-as a rational number with denominator 7.98 |
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| 7. |
-42Express —() 35as a rational number with denominator 7. |
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Answer» divide by 14-42/14. == -398/14. == 7 |
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| 8. |
.13. sec2 θ + cosec2 θ = sec2 θ cosec? θ.1+tan 2 θ14.m tan-θcoscc2 θ15., sec 0-1 sec θ+116, (1-cos2 θ) cosed 0-1.17, cos2 0.cosec θ + sin θ " cosec 0. |
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| 9. |
- 2 cot 0.. 1516.. (1-cos. θ) cosec. 0-1.17, cosa cosec θ + sin θ cosec θ.sec θ-1sec 0+1 |
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| 10. |
3. Divide the following.i. (x - 35)+7 |
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Answer» x - 5 is the correct answer ×_5 is the correct answer X = 6 is the corret answer 7(x-5)/7=(x-5)can be written as x-5 X - 5 is the correct answer x-5 x-5 is the answer.This is the correct answer 6 x-5 this is the correct answer x-5 is the answer of your question x-5 is the right answer 7x-5 is correct answer (7x-35)/77x/7 - 35/7(x-5) answer (7x-5)divide by 7answer is 1x-5 Answer is (7x-35)=x-5 x-5 write answer. hoga x-5 is the correct answer (1). (7x-35)/7solve.7(x-5) 7 x-5.Ans.. this question is answer of it (x-5) x-5 is the exact answer x-5 is the answer🙂🙂🙂 ×-5 is the correct answer x minus 5 is the correct answer x-5 is the right answer this question x-5 is right answer of your question x-5 is above answer for questions X-5 ISKA right answer Hoga x x-5 is the correct answer (1).(7x - 35)÷7solve=7(x-5) 7-35 = -28 divide divide 4 The correct answer is x-5 35_7=2828/7=4 answer is 428 |
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| 11. |
11. Prove that sec?0 - cosec?0 = 8600, 60560 0 |
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Answer» hit like if you find it useful |
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| 12. |
ORProve that sin 0 (1 + tan 0) + cos 0 (1 + cot 0) = sec 0 + cosec 0. |
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Answer» According to given sum, sin (1+tan)+cos (1+cot)=sec+cosec => LHS= sin (1+tan)+cos (1+1/tan) => sin (1+tan)+cos (1+tan)/tan => (1+tan)(sin+cos/tan) => (1+tan)(sin.tan+cos)/tan => (1+tan)(sin^2/cos+cos)/tan => (1+tan)(sin^2+cos^2)/tan.cos =>(1+tan)/tan.cos =>(1/tan.cos)+tan/tan.cos =>( cot/cos)+(1/cos) => cosec +sec LHS= RHS. Like my answer if you find it useful! |
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| 13. |
35 = 7 ( y - 9 ) |
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Answer» 35=7y-637y=35+637y=98y=98/7=14 35=7(y-9) Multiply 7 to the terms in brackets 35=7y-6335+63=7y98=7ytherefore 98/7=y 14=y therefore y=14 35=7(y-9) or 7(y-9)=35 |
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| 14. |
Q6. Divide the sum of 12/7 and -13/5 by the reciprocal of the product of -7/31 and -2 |
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| 15. |
blsin . tan1-cosÂŽ 1+ 0050 = sec 0 cosec 0 + cot 0 |
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Answer» Please like the solution 👍 ✔️ |
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| 16. |
(24/((-35)))*((-7)/27) |
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Answer» -168/-945 = 0.1777 is correct answer 8/45 =0.1777 is the correct answer to this question. |
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| 17. |
(cosec? 0 + 2tanf.cotd — cot?0) F1 7 2 : |
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Answer» cosec^2 theta + 2tan theta. cot theta - cot^2 theta = (cosec^2 theta - cot^2 theta) + 2tan theta.1/tan theta = 1 + 2 = 3 |
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| 18. |
3. Prove : cosec 0 1- cos2 0 = 1. |
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Answer» LHS =Costco√1-cos square theata = cosec theata √sec square theata=cosec theata . cos theata = 1 |
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| 19. |
(जन 6 जलन तय L sl -समान्तर म्रणी का e o 20+ 5 W A ward 20 पदों का थोग’ v ‘e e4nq |
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Answer» first term = 2*1+57second term = 2*2+59sum of 20 terms will ben/2(2a+(n-1))dn=20 a= 7 d= 2answer will be 520 |
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| 20. |
20e thei canncm2 e nalogi K inaaken byme topaeity toe n |
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Answer» 20 men can finish a job in 20 days 1 man - 20*20 days=400 days 25 men=400/25 days =16 days So 25 men require16 daysto complete that job. |
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| 21. |
ind the following.(i) 25% of what number is 8?i) 20% of what number equals 9?i) 10% of what number is 15?) 6 is 37 % of what number?2 |
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Answer» 1. take your first answer |
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| 22. |
A number x decreased by 4 equals to 16.When p is divided by 9, the result is 5. |
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Answer» Equation formx - 4 = 16p/9 = 5 |
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| 23. |
Can you write an expression that equals 24using the numbers and operations below?Numbers: 1, 9, 21, 32Operations: +,-, X, :, ()Each number must be used exactly once. |
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| 24. |
8s =4 eâ =xp 8%= & |
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Answer» y = sin(x³) dy d(sin(x³))---- = ---------------dx dx cos(x³) d(x³)/dx 3x²cos(x³) |
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| 25. |
If a=31 - 1 - 2k, = 27 +3;+k, then(2+ 25x (29 -6)=1) --257 +351 - 55k 2) 251 –35j +55k3) 251 +35; – 55k 4) -257-355 -55k |
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| 26. |
Simplify by rationalizing the denominator7-43+ 4 3 |
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Answer» the correct answer of this question is 97-28√3 |
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| 27. |
\frac { 1 } { 3 } + \frac { 7 } { 9 } \div \left( \frac { 7 } { 10 } \times 1 \frac { 1 } { 4 } \right) |
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| 28. |
If a and b are unit vectors inclined tox-axis at angle 30° and 120, then a+bequals |
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| 29. |
(4x + 7) (4x - 7) |
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Answer» Applying formula (a+b) (a-b) =a^2-b^2 (4x+7) (4x-7) =16x^2-49x^2 |
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| 30. |
1. A line makes some angle θ with each of the x-axis andz-axis. If angle β, which it makes with y-axis, is such thatsin2 β-3 sin2 θ, then cos2 θ equals |
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| 31. |
7.Divide 7+12x-5x2-4x by 4x+5 |
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| 32. |
3(3x -6, . 4x=3(35-%) 7- 4x+281x+3(2x-4)66+ y=76 |
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Answer» hit like if you find it useful |
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| 33. |
०४ एह « .0६ 500 + 6500 0g s () - |
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Answer» sin30*cos45+cos30*sin45=1/2*1/√2+√3/2*1/√2=1/2√2+√3/2√2=1+√3/2√2 |
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| 34. |
use the identity(2x+3y+4z)² |
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| 35. |
\left(2.4 \times 10^{3}\right) \div\left(8 \times 10^{-2}\right) equals |
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| 36. |
XSOt + ¢Xp ||< |
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Answer» Integration by Parts with: u = 1/(5 + 4sinx)du = -4 cos x / (5 + 4sin x) dx dv = dxv = x uv - Integral v du - Integral of v du = -(-4cosxdx)/(5 + 4sinx) = ln | 5 + 4sin x| |
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| 37. |
1) If 2x = 3y = 4z then find x:y:2 |
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| 38. |
94 - 26 \div 13 + 8 \times 4 |
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Answer» 94-26÷13+8 x 4=94-2+8x4=94-2+32=94+30=124 |
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| 39. |
XUISt +¢Xp |
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Answer» Integration by Parts with: u = 1/(5 + 4sinx)du = -4 cos x / (5 + 4sin x) dx dv = dxv = x uv - Integral v du - Integral of v du = -(-4cosxdx)/(5 + 4sinx) = ln | 5 + 4sin x| |
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| 40. |
find the number when increased by 12 equal 160 times its reciprocal ?find the number |
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| 41. |
4xp |
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Answer» transposing x to RHS we get 4= px |
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| 42. |
2рек03 +1 |xp |
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| 43. |
एिपट6/.xp Pt :अछापृष्ठ/ |
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| 44. |
реж2o eXp |
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| 45. |
\tan ^{-1} \sqrt{3}-\cot ^{-1}(-\sqrt{3}) equals |
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| 46. |
find the value of p for which the equation 4x^2 + px + 3 equals to zero has equal roots |
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Answer» Given : 4x² + px + 3 = 0 When roots are equal discrimanat is 0 D = b² - 4ac = 0 p² - 4 × 4 × 3 = 0 p² = 48 p = √(48) p = 4√3 |
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| 47. |
3.25 per metre.A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of therectangle. By how much does the perimeter of the rectangle exceed the perimeter of thesquare?llgtam are 24 cm and 18 cm. If the distance between |
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| 48. |
Find the locus of the point whose distance from x-axis equals2/3 times its distance from the origin. |
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| 49. |
(ii) Find the locus of the point whose distance from x-axis equals2/3 times its distance from the origin. |
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| 50. |
)1 nd log,(0g,l0g, x)- 0 then p' equalslog, (loga (log,1 and loga (log, (logp x)) 0 then 'p' equals |
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Answer» The value of p is p = r^(q/r) |
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