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ORProve that sin 0 (1 + tan 0) + cos 0 (1 + cot 0) = sec 0 + cosec 0. |
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Answer» According to given sum, sin (1+tan)+cos (1+cot)=sec+cosec => LHS= sin (1+tan)+cos (1+1/tan) => sin (1+tan)+cos (1+tan)/tan => (1+tan)(sin+cos/tan) => (1+tan)(sin.tan+cos)/tan => (1+tan)(sin^2/cos+cos)/tan => (1+tan)(sin^2+cos^2)/tan.cos =>(1+tan)/tan.cos =>(1/tan.cos)+tan/tan.cos =>( cot/cos)+(1/cos) => cosec +sec LHS= RHS. Like my answer if you find it useful! |
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