This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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). Find the (a) value of (u) lFind the 4 AOC, 4 COD andDOB from the given figure.Cy4x+20x+182x+95x-10*3x+41Fig Q.l1Flg. 0.12Fig. Q.13 |
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| 2. |
11. If xx0 and0 and x +-= 2; then show that :x22 |
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| 3. |
. Solve : (1+x22+2xy=x'dydxs |
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| 4. |
IfX22+find the values of each of the following:4.xl-x|X- |
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| 5. |
In the given figure, express x in terms of p. q and r.7070° |
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| 6. |
ILLU6.13:5, then find the angles.In the given figure, if ZAOC = 50°, then find(ZAOD + ZCOB).fo12 |
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Answer» angle AOC=50°therefore,angle DOB=50°. (By vertically opposite angle)also angle COB= angle AODthere fore let x the required anglenow x+x+50+50=360. (complete angle is 360°)x=130°therefore angle COB and AOD=x then the sum of angles is 260° (answer) |
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| 7. |
9x4 is same as(i) 122() 36 ()36(iv)18 |
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Answer» Given 9 × 4² We will do factorization, 3² × 4² ( 12)² i) option is correct |
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| 8. |
5. In the given figure, express x in terms of p, q and r.70°70° |
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| 9. |
4. A.quadratic equation ax2 + bx + c = 0 has two roots α = ー2a and β =こb2ao. thenfind α + β, αβ and α-β. |
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| 10. |
all the grouplig ylnSimplify: (a8ab 5)+ (3ab - 4a2+ 8)the second parenthe |
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Answer» The equation simplifies as a^2-8ab-5 +3ab-4a^2+8 =(1-4)a^2+(-8+3)ab+(-5+8)=-3a^2-5ab+3 |
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| 11. |
33. Give possible expression for the length abreadth of the rectangle whose area is given by4a2+4a- 3 |
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| 12. |
Subtract the sum of -Ta? - 3ab 4b aa2- 7ab from the sum of 4a2-b and-1a+7tongle W |
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| 13. |
लासे के शिराप्त है ८ जा भिजा डालने ।पर सैमी पी ग १ ज २ का2018 या ८T |
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Answer» सिक्के का आयतन पानी में हुई वृद्धि के बराबर होगा haa vahid hoga .2 sami panic hi aayan hoga kunki jitna USA bhaar hoga tuna pani pani chakaa ga na |
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| 14. |
If one root of the equation ax2 + bx + c O thesquare of the other, then a(c-b)-cx, where xis(a) a)-b?(c) (a-b(b) a+b(d) of these |
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Answer» Don't copy paste idiot....the solution is wrong anyway |
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| 15. |
Can two angles be supplementary if both of them are:(i) acute?7.(ii) obtuse?(ii) right? |
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| 16. |
2. Write the degree of the following polynomials(i) 4m-V5(ii) m9-m4+m+m-7(ii) 7p q4- 11pt +2p'(iv) abed-3abed3 +2ac41 2 |
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Answer» The degree of a polynomial is the highest degree of its monomials with non-zero coefficients. The degree of a term is the sum of the exponents of the variables that appear in it, and thus is a non-negative integer.(i) 4m - sqrt(5) Degree = 1 (ii) m^9 - m^4 + m^12 + m - 7 Degree = 12 (iii) 7p^2q^3t - 11p^4t + 2p^2q^6Degree = 8 (iv) ab^2cd - 3a^2bcd^3 + 2ac^4Degree = 7 solve second no questions |
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| 17. |
factorise:12x-30 |
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Answer» we can first find the HCF of 12x and 3012x = 2*2*3*x30 = 2*3*5HCF = 612x - 30 = 6 ( 2x - 30 ) ANS.. |
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| 18. |
56. If 5a-4-3a-a 10, What is the value of a? |
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Answer» 2a-4=a-10 a=-6 The value of a is -6. |
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| 19. |
1) 4prFind the value of a, if x + 2 is a factor of 4x4 +238x +5a.3) 44) |
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| 20. |
3 -15. If A=1, show that A' - 5A is a scalar-4 21matrix. |
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| 21. |
Solve the following (1 to 7) quadratic equations:1 () x22 02 (6) x-x -12 0(ii) 4x2 +50(ii) 25x2 +30x +7-0(i) 15x2 + 15-34 |
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Answer» thank you |
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| 22. |
3.Ifa"-Äą = bc, by-. I = Ca, cz-i = ab, then 1+1+1== ca, c= ab, then-+-+-- |
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Answer» How to develop maths skills? Keep on practicing questions. Solve as many questions as you can. If you're stuck in a question, clear your doubt as soon as possible. We're always here to help you. Also, if possible ,solve the topics you find difficult first and then the easy ones. |
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| 23. |
19. In ÎABC, AC > AB, D is the mid-point of BC andAEBC. Prove that :4(1) AB? - AD? -BCDE+BC(iii)AB" + ACa_ 2AD2 BC2. |
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Answer» i) ABC is a triangle, in which AC > AB; this is only for the inference that the altitude from A on to BC lies towards B, that is point 'E' lies between B and D; this is the most important inference for proving the given ii) D is the midpoint of BC iii) AE perpendicular BC Required to prove: AB^2=AD^2-BC*DE+1/4BC^2 PROOF: [for easy convenience, let me denote all squares by * and multiplication by 'x'] 1) Since AE is perpendicular to BC, ABE is a right triangle with angle E = 90 deg. 2) Hence applying Pythagoras theorem we have, AB* = AE* + BE* 3) In similar way from the right triangle, ADE, AD* = AE* + DE*, => AE* = AD* - DE* 4) Substituting for AE* from step 3 in step 2, we have, AB* = AD* - DE* + BE* 5) From the figure (Kindly make according to the description given in data), BE = BD - DE 6) Substituting this in (4), AB* = AD* - DE* + (BD-DE)* 7) Expanding, AB* = AD* - DE* + BD* + DE* - 2 x BD x DE 8) Cancelling -DE* and +DE* and substituting BD = (1/2)BC {Since, D is mid point of BC} we get, AB* = AD* + (1/4)BC* - BC x DE Thus it is proved that "AB^2=AD^2-BC*DE+(1/4)BC^2" Now, BD = BC/2(since, D is midpoint) Therefore, AB2= AD2+ BD2-2BD*ED =AD2+ (BC/2)2– 2(BC/2)*ED = AD2+ (BC/2)2–2(BC/2)*ED = AD2– BC*DE + ¼ BC2 |
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| 24. |
i)5x2 +13x + 8ii) 4r - 16x + 7ii) 3z - 4z-43. If (2x - 3) is a factor of 2x3-9x2 + x + k, then find the value of |
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| 25. |
1. IfCD 1 AB, and CD bisects AB, prove that AABC is an isosceles triangle. |
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Answer» In triangle ADB &ADCBD=CD(given) AD=AD(common) angle ADB=angle ADC(90°each) - By SAS criteria triangle ADC congruent to triangle ADB.By CPCT AB=AC Therefore, Triangle ABC is isosceles triangle. |
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| 26. |
Which term of the AP 3,10,17,.......... will be the 84 term more than it's 13th term |
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| 27. |
if 4 x square - 16 X + 16 is equal to zero then find the value of x |
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Answer» 4x²-16x+16 = 0=> x²-4x+4 = 0=> x²-2x-2x+4=0=> x(x-2) -2(x-2) = 0=> (x-2)(x-2) = 0=> x = 2,2 |
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| 28. |
8. Which term of the A.P 3, 10, 17,will be 84 morethan its 13th term? |
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| 29. |
B रा नहा पदक नर 8.22 2 25) 5a - [a® - {2a(l - a + 4a*) - 3a(a® - 5a - 3}l - 80e O e D A |
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Answer» 5a-{a^2-{2a(1-a+4a^2)-3a(a^2-5a-3)))-8a5a-(a^2-2a+2a^2-8a^3)-3a^3+15a^2+9a)))-8a5a-3a^2+2a+8a^3-3a^3-15a^2-9a-8a5a^3-18a^2-10a |
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| 30. |
. For the equation ax2 bx c O which of h fol(A) If (b2 4ac) O the roots are imaginary(B) If (b2-latement incorrect ?4ac) = 0 the roots are real and(C) If (b2 4ac) > 0 and (b2- 4ac) is a perf uarthe roots e rational aunequal(D) (b2-ac) < 0 the rnols are irrational. |
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| 31. |
GALOOL5a, 3a', 7a का गुणनफल ज्ञात कीजिए।Find the product of 5a, 3a?, 7a4. |
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Answer» 5a × 3a^2 × 7a^4 = 105 a^7 Multiply the numbers and the powers are added. |
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| 32. |
8 Find the sum of:a 3a+ b; 5a +2b; 3a-bс 5x2 + 7x + 3; 12x2-3x + 8: 6x2-4x + 9e 4x + 5y + 7; -5x-y-3; 3x-3y + 2d2а + 5b + 7; 8а-3b + 3.-5a-70-6 |
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| 33. |
IfAL= [ 3-5-4 2-7ther141-5A =then A2-5A =b) 141Q5:c)0c) 0d) of these |
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| 34. |
5A 4 |123,10 |
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| 35. |
25/6-9y=11 |
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| 36. |
-) = 7y (= 9y=19 |
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Answer» (x-7)(x-9) = 195x^2 - 9x - 7x + 63 = 195x^2 - 16x - 132 = 0x^2 - 22x + 6x - 132 = 0x(x - 22) + 6(x - 22)=0(x+6)(x-22)=0x = - 6, 22 ans |
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| 37. |
0.Which polynomial will you get after subtracting (4+9y + 2x) from the sof (8x - 6y +4) and (6y -3x +7)?(1) 3x -9y 7(3) 7x +9y + 15(2) 3x -3y +7(4) 7x-9y-15 |
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Answer» Sum = (8x-6y+4)+(6y-3x+7)= 5x+11Difference = (5x+11)-(4+9y+2x)= 3x - 9y + 7 |
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| 38. |
9x-3y-6y+9y= |
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| 39. |
(v)Find the sum of first 15 multiples of 8. |
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| 40. |
(feterheindt,if the 10th term of an AP is 52 nd 17th term is 20 more thanhits 13thterm, find the AP.ICBSE 2009C]ICRSE 20151 |
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| 41. |
> dy= (r‘ से रन जैक8. यदि ) न अंश), |
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Answer» y = sin(x³) dy d(sin(x³))---- = ---------------dx dx cos(x³) d(x³)/dx 3x²cos(x³) |
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| 42. |
Find the sum of the first 15 multiples of 8. |
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| 43. |
17. Find the sum of the first 15 multiples of 8 |
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| 44. |
(i) 9a -3b to 6a -10b |
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Answer» Add : (9a - 3b) + (6a - 10b)= (9+6)a + (-3 - 10)b= (15a - 13b) ans |
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| 45. |
d. Find the sum of the first 15 multiples of s. |
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| 46. |
prove that tan 13A-tan 9A-tan 4A=tan13Atan9Atan4A |
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Answer» a ki aa yaar samaj nahi aa rahi ki aaa |
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| 47. |
sinAsin2A +sin3Asin6A+sin4Asin13A/sinAcos2A+sin3Acos6A+sin4Acos13A = tan 9A |
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| 48. |
: J(3x + 12)9(2r 32)° |
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Answer» (3x+12)+(2x-32)=1805x-20=1805x=200x=40D=BD=2x-32=80-32=48 |
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| 49. |
wards1.Can you ever imagine a world without trees?2Dunha ticket today |
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Answer» No Humans. Haveyou everwondered what aworld without trees wouldlook like? Close your eyes, and try toimaginea desolateEarth. ... Even if our species survived the devastation of deforestation, life asweknow itwouldbe very different from now in 2011, where only half of theworld'sforests No. No trees....No humans. ..Life could not exist on Earth without treesbecause they produce most of the oxygen that humans and wildlife breathe. Trees absorb carbon dioxide from the atmosphere and release oxygen using the process of photosynthesis. ... Forests act as giant air filters for the world. No we cannot imagine without trees. because Life could not exist on Earth without treesbecause they produce most of the oxygen that humans and wildlife breathe. Trees absorb carbon dioxide from the atmosphere and release oxygen using the process of photosynthesis. ... Forests act as giant air filters for the world. |
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| 50. |
③Findthesum of first8 multiples of. |
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Answer» =sum of first 8 multiples of =3=3+6+9+12+15+18+21+24=3(1+2+3+4+5+6+7+8)=summation of natural no's==n(n+1)/2=8(8+1)/2=8(9)/2=36sum of first 8multiples of 3=3(36)=108 3+6+9+12+15+18+21+24=108 It will make a series having first term, a=3 and common difference, d=3Then we will apply formula of A.PSum of first 8 multiples of A.P={2a+(n-1) d}×n/2={2×3+7×3}×8/2=27×4=108 The first-8 multiples of 3 are 3,6,9,12,15,18,21 and 24these numbers are now in Arithmetic progressionsofirst term, a=3common difference,d=6-3=3number of terms,n=8Therefore Sum of AP=n/2[2a+(n-1)d]=8/2[2(3)+(8-1)3]=4[6+(7)3]=4(6+21)=4x27=108 a=3, d= 3sum = n/2{2a+(n-1)d} =8/2{2×3+(8-1)×3} = 4(6+21) = 27×4 = 108 108 is the best answer |
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