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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Angles, Lines and TrianglesIn the given figure, AB|| PQ. Find the values of x and75*25* |
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Answer» 25 + y = 75 [corresponding angles] y = 5025 + x = 75 + 20 [exterior angle] x = 70 |
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| 2. |
B Q. 5. Lines PQ and RS intersect each other at O (seefigure). If POR: RORS : 7, find all theangles a, b, c and d. Board Term I, 2012, Set-41 |
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Answer» sum of all angles around a point = 360°a+b+c+d= 360°Let angle POR be 5x and angle ROQ be 7xSo, 7x+ 5x + 7x +5x = 360°this gives x=15°So, a= c = 7x = 105°and, b=d= 5x = 75° |
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| 3. |
4. The marked price of the fan is 3000 rupees. Shopkeeper gave 12% discounton it. Find the total discount and selling price of the fan. |
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| 4. |
-a %2B b %2B 3*(a*b) - a*b - a %2B b - a*b %2B 3*a - 2*b |
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| 5. |
Find the mean proportional of (z, 40 2Ans. (i) 9, (ii) 6 xyz] |
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Answer» Thanks 🙂 |
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| 6. |
In quadrilateral ACBD,AC AD and AB bisects Z A(see Fig. 7.16). Show that A ABCA ABD.What can you say about BC and BD?1. |
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| 7. |
29/2400 |
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Answer» 0.0120833333non-terminating recurring decimal.if helpful like it. it is not form of 2^m×5^nq=2^5×3×5^2this is non terminating and repeting decimal 0.0069047619 is the answer 29/2400=29/2×2×2×2×2×3×5×5 so it is cleared from above that denominator is not in the form of 2m ×5nSo it is non - terminating decimal 0.0120 is answer of this question |
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| 8. |
8000000 - 240000 + 2400 - 8 |
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Answer» 8000000 - 240000 + 2400 - 8= 8000000 + 2400 - 240000 - 8= 8002400 - 240008= 7,762,392 |
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| 9. |
46. यदि >> हो, तो 0 >?(1) x (1 + logx) (2) (1 + logx)का (3) ¢ logx (4) इनमें से कोई नहीं |
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Answer» 1मततथथथदभडयत णणणत चततत णणत |
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| 10. |
नि थे value थ Eh% .+ >u_‘2_44\~ V. - |
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Answer» 5(4)+5(-2)-2=20-10-2=10-2=8 |
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| 11. |
11 no1100 2400 |
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Answer» Is question ka answer 0.00002 hoga 0.00002 is the right answer 0.00002 right answer hoga 1/5000 is the right answer |
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| 12. |
Findayy=(logx)x + (x)logxifdx |
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Answer» Please hit the like button if this helped you |
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| 13. |
€ logx/x |
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| 14. |
eh-1 (0-1) what is the Hat ofand Zx 52? |
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Answer» The HCF of 35 and 5 is 5 |
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| 15. |
rea of the base of a cuboid is 45 cm,eh is 6cm. Find the volume. |
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Answer» Area of the base means the product of length and breadth. we have to just multiply the height. So, Volume = 45×6 cm³ = 270 cm³ |
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| 16. |
In figure lines PQ and RS intersect each other at point 0. If LPOR: LROO-Find all the angles. |
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| 17. |
DATE20PAGE NoEndte |
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Answer» hence, -2 is the remainder. |
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| 18. |
ln figure lines PQ and RS intersect each other at point O. If anglePOR:angleROQ=5:7.Find all the angles.[21 |
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| 19. |
Page No.:Date:20 |
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| 20. |
figureAnS.In the given, ABä¸BC, DCL BC,L AC, ZD = 30° and DC = 60,f m.BDFind the length of AB.6013 m |
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Answer» The Answer is 20 * sqrt(3) |
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| 21. |
In the given figure, if AB AC and DB DC, then find ABDZ DCA Ans,1 |
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| 22. |
KR6. Two lines PQ and RS intersect at O. If ZROT = 45°, findthe measures of all other angles.4y2x |
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Answer» 2x = 4y(vertically opposite angles)x = 2y............... (1) 2x + y + 45 = 180(Linear Pair) Put value of x from eq(1)2*2y + y = 180 - 455y = 135y = 135/5 = 27°.......... (2) x = 2y = 2*27 = 54° z = 45 + y(vertically opposite angles) Put value of y from eq(2)z = 45 + 27 = 72° |
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| 23. |
Xy =log| ——| logx ) |
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| 24. |
. A sum of 3000 is to be given in the form of 63 prizes. If the prize money is eitherR.I0or .25. Find the number of prizes of each type. |
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Answer» Let no. of Rs 100 prizes be n and 25 prizes be (63-n) 100n + (63-n)25 = 300075n = 3000-157575n = 1425n = 19 No. Of Rs 100 prizes are 19 and Rs 25 prizes are (63-19) = 44 |
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| 25. |
*show that any positive een integers isof the foom (82) 20 (62+2) or (68+4). forsome integer 2show that reciprocal ob an irrationalIملحبمصر اسمعیو |
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Answer» 62+2=64/2=32/2=16/2=8/2=4; 72/2=36/2=18/2=9/3=3 |
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| 26. |
'क. यदि y = B, A सिद्ध कीजिए कि-- डी =x"(1+logx). |
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| 27. |
(o) Show that the points (-2, o), (-4, -2 V3) and (6,0) are the vertices of an equilateral triangle.Show that the points (-2, 0(6)Hence find its area. |
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Answer» s |
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| 28. |
Find the youwhich w09) differentatiate the e*(x + logx) w.rtxo |
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| 29. |
10. Discuss the continuity of f(x) = sin | xl. |
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| 30. |
l+ XL(AiX) |
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| 31. |
2The two of a quadrilateral are of measure65° each cand the other two englesare agual What is the meareof these two angles ? |
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| 32. |
0=6-99+XL ०0न्8+पिए 3. |
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Answer» 6x-4y+8=0... Multiply with 67x+6y-9=0... multiply with 4 36x-24y+48=028x+24y-36=0 Add 64x+12=0x=-12/64=-3/16y=5x+8/4y=5(-3/16)+8/4y=(-15/16+8)/4y=-15+128/32y=113/32 |
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| 33. |
EXERCISE 91.State the property used in each of the following to make the statement truei. If/11m, then <3-27.ii. IfL5-L5, then Illm.iti. If 23 6 180°, then I|Im.In Figure 2, find the values ofL6 and <7, given that mlin and 1-115°.In Figure 3, AB |CD. EF intersects them at P and Q, respectively.If 412.Fig. 13.130o, find all the other angles.Fig. 3Fig. 2 |
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| 34. |
3a 2. Name any 4 pairs of adjacent angles in the givenfigureAns.(1) LAOB and LkCOk |
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Answer» TwoanglesareAdjacentwhen they have a common side and a common vertex (corner point), and don't overlap.(1)angle(AOB) and angle(BOC)(2)angle(AOB) and angle(AOE)(3)angle(AOD) and angle(DOC)(4)angle(COB) and angle(DOC) |
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| 35. |
8. In the figure two lines PQ and RS intersect each other at O. Namepairs of vertically opposite angles |
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Answer» POR and SOQ POS and ROQ |
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| 36. |
0=6-49+xL0=8+4p—x5 (9 |
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Answer» Like if you find it useful |
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| 37. |
दिन सदा + (0 - सदन x)8 — XL+ कक... |€T <- |
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| 38. |
GI 0 |
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| 39. |
Exercise 3.15Solve the following quadratic equations by completing the square(i) x2 + 6x-7=0(Gi) x +3x +1=0 |
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| 40. |
A Sum eh 3000 is be giver |
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| 41. |
& w w2 सिद्ध कीजिए कि | ८० w* 1|7 (जहां ८० घन मूल ईकाई है।o WGk |
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Answer» Thanks bhai ji |
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| 42. |
2showthat 0 2355 in the giver |
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Answer» I don't know how to explain |
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| 43. |
find the surface area and volume of giver)cylinder. |
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| 44. |
3 рди |; |7: 53 Wg x:y=7:3 %, eA |
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| 45. |
उप A>o "B_-__—_______J - ;- A- 3 SJanW d__________,___gm-’/“‘”—: ————— ; _______—————c—‘_—7 : (/)Y/ w ही. २/८/7८९'. /८ःet |
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| 46. |
a+bx b+cx c+ dx牙引 |
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| 47. |
_ In the giver figure, find the measure of engleslapse45X320 |
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Answer» angles=45+a+75+20=180; 140+ a=180; a=180-140=40 sum of angle of straight line is 18045+a+75+20=180140+a=180a=180-140a=40°the angle is 40°. A= 40 degrees. It is the right answer to your question I hope that my answer helped u in doing ur work Have a great Day 45°+x°+75°+20°=180140°+x=180x=40is correct answer |
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| 48. |
जन ज्ञात कीजिए:(3°+4-1)x22 |
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Answer» (1+1/4)×45 is the correct answer of the given question (1+1/4)×4(5/4)× 45 |
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| 49. |
AAAA+ A = ?+ B 3+ B ++ B +CXb |
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Answer» A + B + C × 4 = 24 This is the correct answer A=1B=2C=3So, A+B+C x 4= 1+2+3x4 = 3+3x4 =6x4 .: the answer is 24 |
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| 50. |
the given | Name 2 pairs of adjacent angles in the giverfigure:Ans. |
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