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let 0.47 bar be x

So,

x = 0.477777..... (1)

Multiply by 10 on both sides

10x = 4.777777...... ....(2)

Mutliply by 100 (1)

100x = 47.777777..... ....(3)

(3) - (2)

90x = 43

x = 43/90

Width of track = (outer circumference - inner circumference)/2π= (528-61)/2π= 74.33 m

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As alpha+ beeta= -b/aand alpha* beeta= c/a

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In this fig we have 2 altitude , one has base DC and other have base BC and BC=AD and AB=DCtherefore area of llgram will be BM x DC which is equal to DL x BCby solving both we get 8 x 10= 6 x Bc80/6= AD. ( since BC =AD)AD=40/3 =13.33 cm

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a + B + c=0, a^3 + b^3 + c^3=3abc;, a^2/bc + b^2/ac + c^2/ab=a^3+b^3+c^3/abc=3abc=abc=3

the right answer is 3

3 is right answer of this question

a+b+C=0so a^3+b^3+c^3-3abc=0a^3+b^3+c^3= 3abca^2/bc+b^2/ca+c^2/aba^3+b^3+c^3/abc= 3abc/abc= 3

Given a + b + c = 0 ⇒ a3 + b3 + c3 = 3abc → (1) Consider, (a2/bc) + (b2/ca) + (c2/ab) = (a3 + b3 + c3)/abc = 3abc/abc = 3 [From (1)]..

3 is the correct ans ok

3 is correct answer this question

3 is the following question answer.

3 is the correct answer

the answer of this question is 3

-2 is the correct answer

a+b+c=0

there fore (a+b+c) square=2abc

3 is the correct answer

3 is the best answer

3 is the right answer

For a+b+c=0a^3+b^3+c^3=.3abcNow , a^2/bc+b^2/ca+c^2/ab= a^3+b^3+c^3/abc= 3abc/abc= 3

3 is the correct answer

3 is the best answer of the following question

the correct answer is 3

3 is the right answer for the equation

b+c=-ac+a=-ba+b=-cso, LHS a^2/bc + b^2/ca + c^2/ab LCMof the denominators bc, ca and ab is abc. =(a^3 + b^3 + c^3) / abc Given that a + b + c = 0 Thus, a^3 + b^3 + c^3 = 3abc Replacing numerator with 3abc, 3abc / abc = 3

effective profit =110-95 =15%

letter appear to be rust resistant when view glass slab disappear due to you give me the answer

Thanks

Let CP = 100.Then, MP = 100 + 20% of 100 = 120.Now, SP = 120 - 10% of 120 = 108.Gain = 108 - 100 = 8%Gain = (8 *100)/100 = 8%.

Short-cut100(CP)==20%(up)==>120(MP)==10%(disc.)==>108.% gain = 8%.

thank you.

A line segment can only have one midpoint. A) only one

Consider a parallelogram ABCD.

AB = CD [ Opposite sides of parallelogram are equal]

So, AM = CN and AM ll CN [ Since AB ll CD ]

So, AMCN is now a parallelogram.

Now, P and Q are midpoints

MC ll AN , so MQ ll NP

and as opposite sides of parallelogram are equal so, MQ = PN

therefore PMQN is a parallelogram.

:A = P(1+ R/100)NInitial population of the city (P) = 20,000Rate of increase (R) = 5% paN (number of years) =3Population of the city after 3 years = AA = 20000(1+5/100)³ = 20000(105/100)³ = (20000*105*105*105)/(100*100*100)A = 23152.5So, population of city after 3 years = 23152.5

thank u

5 are of 1230 so in 7872 number of cars are 7872×5/1230 = 32

Rong

now check

Ya saval

Kro

Total quantity = 48 litres

Ratio of hydrochloric acid to water = 5: 3

Quantity of acid = 5/(3+5) * 48 = 5/8 * 48 = 30.

Quantity of water = 3/(3+5) * 48 = 3/8 * 48 = 18.

If the ratio of acid to water is 3: 2

Quantity of acid = 3/(2+3) * 48 = 3/5 * 48 = 29.

Quantity of water = 2/(2+3) * 48 = 3/5 * 48 = 19.

Sorry this is not answer

Selling price of an article = Rs 250Profit = 5%Cost price = (100 x SP) / ( 100 + gain)Cost price = (100 x 250) / 105Cost price = (100 x 250) / 105 = Rs. 238

tanx = 3/4tan^2x = 9/16sec^2x - 1 = 9/16sec^2x = 25/16secx= 5/4cosx=1/secx=4/5sinx=√1-cos^2x=3/5cos^2x-sin^2x=16/25-9/25=7/25

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Population in 1997 P = 20000Population in 2000 A =?Rate of Increase R = 5%Number of years n = 3

Then,A = P(1 + R/100)^3 = 20000(1 + 5/100)^3 = 20000(21/20)^3 = 20000(1.157) = 23140

Therefore population at the end of year 2000 is 23140

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option b is correct since cos 3x will lie between -1 and 1

I think(E) 15is a write answer

Please mention the complete details of the question!