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1487×327 + (-487)×327 = 327 × (1487-487) = 327 × 1000 = 327000

a²b² - 2abc + c²a²b² - abc - abc + c²ab(ab - c) - c ( ab - c)(ab-c) (ab -c)(ab-c)²

So, division is a²b² - 2abc + c²------------------------ (ab -c)

(ab-c)²----------- (ab -c)

(ab-c)

3 is the right answer

3 is the right answer

3 is the right answer

3 is the right answer

3 is the correct answer of the given question

3 is the right answer

5 is the right answer

3 is the right answer

3 is the right answer

3 is the right answer

3 is the right answer

3 is the right answer

If,10x=30,Then,x=3.

3 is the right answer

3 is the right answer

If this is the given condition the result are consistent that is it has a unique solution.

S=150/100T=1.5Tso S+T=T+1.5T=2.5Tso T=10/25*100(S+T)=40%(S+T)

1 2 P+6 P Q-------------- P 0 9

Possible Value of P = 8, Q = 1

Then, value of P^2 + Q^2= (8)^2 + (1)^2 = 64 + 1 = 65

(4) is correct option

ice-cream cone im an example or a

let the roots be a and b

now a+b = -p/1 = -p...... iand ab = q/1 = q.......... ii

now ATQ , (a+b) = 3(a-b) => 2a = 4b => a = 2b

now putting the value of a and b in eq 1 and 2 we get, 3b = -p or b = -p/3, and from eq...2 , 2b² = qso, 2(-p/3)² = q => 2p²/9 = q or 2p² = 9q.

option B.

If A's income is 10 % more than B ....

So B's income less than A is....

= 10 / ( 10 + 100 ) × 100 %= 10/110 × 100 %= 1000/110 %= 9.09 % .....

the answer is -100

percent student cam swim are = 350/500 * 100 = 70% so percent student can not swim are 100-70=30%

For a function to follow |f(x) +g(x)| = |f(x)| +|g(x)| , both the functions must be positive for all the domains inside it.

so, here f(x) ≥ 0 , 4-x² ≥ 0 and 2 > 0 ✓

so, 4-x² ≥ 0=> x²≤4 => x belongs to [-2,2]

if X+1 is a factorby putting X=-1a(-1)^3+(-1)^2-2(-1)+4a-9=0-a+1+2+4a-9=03a-6=0a=6/3=2hence a =2

p(-1)=-1-1-1+1=-2p(1)=1-1+1+1=2(1/2)[p(-1)+p(1)](1/2)(0)=0

Answer the question

Answer the question

Answer the question

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The highest number which exactly divides 27 and 45 is the HCF(27, 45).HCF(27, 45) = 9

Therefore, the required number is 9.

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Increased number =120 Σ( ° △ °)

sorry wrong answer

increased number =120% of x= 120 ÷100 ×x= 6x÷ 5deceased number =80% of 6x÷5=24x÷25net decrease =X-24x÷25=x÷25net decrease percent =(x÷25×1÷x×100)%=4%

Percentage of children who can swim= 350/500*100= 70 Percentage

consider triangle PAC and QBCAC = BCangle PCA = angle QCBangle PAC = angle QBCso ∆PAC is congurent to ∆QBC by ASA ruleso again consider traingle DBC and EAC which congurent by ASA rule by CPCT DC = ECadding ∆PAC = ∆QBC and ∆ EAC = ∆ DBC so , we get ∆ ACE = ∆ DBC proved

Ans :- 4x/3 + 9 = 17 4x/3 = 17 - 9 4x/3 = 8 4x = 8×3 4x = 24 x = 24/4 x = 6

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x + y = 7........(1)x = -1.............(substitute in equation 1)-1 + y = 7y = 7 + 1 = 8

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mean={(x+2)+(x+4)+(x+6)+(x+5)+(x+8)}/520=(5x+25)/520=x+5x=16

so the observation are 18,20,22,21,26

2/15 + 7/18={2(6)+7(5)}/90=(12+35)/90=47/90

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In given fig. z = 50° (vertical opposite angles)

x + 45 + z = 180 (linear pair)x + 45 + 50 = 180x = 180 - 95 = 85

y + z = 180 (linear pair) y + 50 = 180y = 180 - 50 = 130

(a-b)(a²+ab+b²)=a³+a²b+ab²-a²b-ab²-b³=a³-b³

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Insurance is an arrangement in which you pay money to a company, and they pay money to you if something unpleasant happens to you, for example if your property is stolen or damaged, or if you get a serious illness.

Natureor Characteristics of Insurance

Contract.

Consideration.

Co-operative Device.

Protection of financial risks.

Risk sharing and risk transfer.

Based upon certain principles.

Let a be any positive integer and b =8 ,then , ecluid algorithm ,

a = 8q +r for some integer q >or = 0 and r = 0,1,2,3,4,5,6,7 0 <,= r <= 7

then , 8q +1 = 2 x 4q +1 2m +1, where m is any positive integer = 4q

8q+3 = 8q +2+1 2 (4q +1) +1 => 2 m +1 , where m is any positive integer = 4q +1

8q +5 = 8q + 4+1 2 (4q +2) +1 =2 m +1 , where m is any positive integer = 4q+2

8q +7 = 8q + 6+1 2( 4q +3) +1 =2m +1 , where m is any positive integer = 4q +3

this means that 8q +1, 8q+3 , 8q+5 and 8q+7 cannot be exactly divisible by 2 .

Hence any odd no. can be expressed in the form of 8q+1 , 8q+3 , 8q+5 and 8q+7