Saved Bookmarks
| 1. |
Q.5 In the given tigure, AC BC. DCAthat △ DBC-△ LAC and DC-LC.FCB and LPRCLFAC. Prove13 |
|
Answer» consider triangle PAC and QBCAC = BCangle PCA = angle QCBangle PAC = angle QBCso ∆PAC is congurent to ∆QBC by ASA ruleso again consider traingle DBC and EAC which congurent by ASA rule by CPCT DC = ECadding ∆PAC = ∆QBC and ∆ EAC = ∆ DBC so , we get ∆ ACE = ∆ DBC proved |
|