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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
how to answer in in these app |
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Answer» by answering the answer click on the question and if u know the answer then start typing your answer |
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| 2. |
APP ROPATATE PRoPERTI FIND52 |
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Answer» thanks for giving me answer |
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| 3. |
After 6 g of carbon is completely burnt in anatmosphere of 40 g of oxygen, the percentageoxygen left is:1. 802. 603. 404. 20 |
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Answer» Answer:2) 60%Explanation:Gram molecular wight of carbon = 12gms 12 gms of carbon =1 mole carbon Therefore, 6 gms of carbon = 0.5 moles of carbon Gram molecular weight of oxygen = 32 gms 1 mole of oxygen = 32 gms The chemical reaction between carbon and oxygen is as follows: C + O₂ = CO₂ i.e 1 mole of carbon will react with 1 mole of oxygen => 0.5 mole of carbon will react with 0.5 mole of oxygen hence oxygen consumed in the reaction = 0.5 mole = 16 gms so oxygen left = 40 - 16 = 24 gms % of oxygen left = 24 x 100/40 = 60% Hence 60% of oxygen will be left. answers is 40 that's the right answers I muss say |
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| 4. |
If z +4 33 then find the greatest and least values of +1 |
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Answer» |z+4| = |z+1+3| , that will always be ≤ |z+1| +|3| so, maximum value of |z+1| +3 = 3 => |z+1| ≤ 3-3 = 0therefore minimum value is 0 and minimum value of of |z+1| -3 ≤3=> |z+1| ≤3+3 =6 maximum value is 6 |
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| 5. |
Findgain or loss percent when:(a) C.P. = 350 and S. P. 400(b) C. P.250 and S. P.235(c) C. P.300 and Gain75 |
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Answer» a)gain percentage=(400-350)/350*100=100/7=14.28%b)loss percentage=(250-235)/250*100=15/25*10=6%c)gain percentage=75/300*100=25% |
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| 6. |
) Explain why 7×6×5×4×3×2× 1+5 is composite)Without gtual |
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Answer» 7× 6 × 5 × 4 × 3 × 2 × 1+ 5 = 5040 +5=5045 = 5045 = 5×1009 We know that a number is called a composite number if it has at least one factor other than 1 and the number itself. Here, 5045 is the product of 2 prime factors 5 and 1009 . Hence,7× 6 × 5 × 4 × 3 × 2 × 1+ 5 is a composite number. HOPE THIS WILL HELP YOU… please like the solution 👍 ✔️ |
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| 7. |
UAJILIET+ .lll .111116What will replace Question Mark?IFONE=314TWO=325THREE=538FOUR=448THENwww.Fun With Puzzles.com1 youIved it!10.3soyeznam!!!Fun WithPuzzles.comSIX=? |
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Answer» gff Then that means six will equal 459 the correct answer will be 459 because you adding 11 more |
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| 8. |
tiesA fair dice is rolled. Find the following probabilities:(a) P (prime number)(b) P (perfect square)(c) P (at least 4)-(d) P (at most 4)5. |
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Answer» can you please do the other sums |
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| 9. |
14. Simplify (2x+p-c)? - (2x - p + c) |
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| 10. |
of the curve y=x° +5x+6xमूल्यांकन कीजिए-[/sinade.Evaluate-[/4 sinade. |
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Answer» After putting limits1/4[ 3π/8-1] |
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| 11. |
Evaluate the following integrals\begin{array}{l}{\int \frac{(x+1)^{0}}{x^{2}} d x} \\ {\sqrt{y} \int\left(x^{2}+\frac{1}{x^{2}}\right)^{3} d x}\end{array} |
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| 12. |
\begin{array} { l } { \text { Evaluate the following integrals } } \\ { \text { 1. (i) } \int _ { 0 } ^ { 3 } \int _ { 0 } ^ { 1 } \left( x ^ { 2 } + 3 y ^ { 2 } \right) d y d x } \end{array} |
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Answer» thank you sir |
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| 13. |
many-oneOn tofun^n example |
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| 14. |
रासायनिक समीकरणों को संतुलित कीजिए: ...HNO, + Ca(OH), - Ca(NO,), + H,0 |
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Answer» यह संतुलित समीकरण हे |
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| 15. |
Integrate the rational fun1.+ 1)(x+2) |
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| 16. |
6. Fyplain why1313 and641 - s are composite number.Explain whyExplain whyx1 1 x 1 3 + 13 and 7654321 + 5 are composite numbers.s |
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| 17. |
। यदि A = [३३] और B = [३३] AB निकालें।If A = [३] and B = [३३ ३]. find AB |
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| 18. |
AB 1PQ 3AB 1Given Δ ABC-aPOR , if PQ#3,then find,then find r3POR |
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| 19. |
( 1 ) x ^ { 2 } - 8 x + 12 = 0 |
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| 20. |
3. Find the product of abab? |
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| 21. |
\left. \begin{array} { l } { \frac { 1 } { 5 x } + \frac { 1 } { 6 y } = 12 } \\ { \frac { 1 } { 3 x } - \frac { 3 } { 7 y } = 8 , x \neq 0 , y \neq 0 } \end{array} \right. |
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Answer» your answer is wrong pls post correctly |
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| 22. |
* 12. If tane(a).70cosec -sec20then cosec 0 + seco(b).8. (1 + sin )(1-sino)NI(d). 3 |
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Answer» if tan q =1/5them ( a) 2/3 1/3 is the correct answer. option a is the correct answer of the given question 1 and 5 is the right answer 1 and 5 is the right answer |
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| 23. |
qUris a ki. Find ,z0012.050 |
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Answer» Adjacent side angle sum is 180°so angle p+ angle r = 180angle p(y) =130°angle q+angle s=180°120+x=180x=60° |
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| 24. |
tan(2*x)=(2*tan(x))/(-tan(x)^2 %2B 1) |
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| 25. |
The average age of an adult class is 40 years .12 new students with an average age of 32 yearsJoin the class, thereby decreasing the average of the class by 4 years the original strength of theclass was: |
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Answer» Average age of x students=40Total age=40x Average age of 12 students=32Total age=32*12=384Average age of x+12=40-4Total age =x+12=36=x=24 Let, initially x student presentInitially total age of adult class=40xafter 12 new students join, total students is x+12 & total age is 40x + 12×32a/c to que, 36×(x+12) =40x +12×324x=12×4x=12 |
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| 26. |
a +b Ka holhoskar |
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Answer» (a + b)² = a² + 2ab + b² |
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| 27. |
Prove that \frac{\sin x+\cos x}{\cos ^{3} x}=\tan ^{3} x+\tan ^{2} x+\tan x+1 |
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| 28. |
a+b ka holl qur |
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Answer» a²+b²+2ab is the correct answer of the given question a^2+b^2+2ab is correct answer of following question a2+b2+2ab will be the right answer a2+b2+2ab will be the right answer a²+b²+2ab is right... a²+b²+2ab is right answer |
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| 29. |
4ABC9,柯ACTI 껴-fa-S.xt1zjR XY||Abt, di red qm01く4In AA BC, X is middle point of AC. IFXYAB then prove that Y is middle point of AB. |
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Answer» In∆CAB,wehaveXY∥AB,thenCXXA=CYYB[BPT]........(1)now,XisthemidpointofCA,thenCX=XA.nowfrom(1),wehave,CXCX=CYYB⇒1=CYYB⇒CY=YB⇒YisthemidpointofBC |
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| 30. |
Draw different pairs of circles. How many points does each pair have inWhat is the maximum number of common points?les.Howmany poiniv i oCJe |
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| 31. |
25. A maximum of how many pieces of 12.6 cmcan be cut from a 857 cm long rod ? |
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Answer» A maximum of how many pieces of 12.6cm can be cut from a 857 cm long rod So suppose x pieces can be cutnowx * 12.6= 857x= 857/12.668 approximately |
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| 32. |
(ii) Consider Δ ACB, right angled at C, in which AB-29 units, BC-21 units andABC-θ. Determine the values of2(a) cos-g + sinθ(b) cos 2 θ-sin 2 θ |
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Answer» use Pythagoras theorem |
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| 33. |
dbyFromthetopequilateralUlahand foot of a tower 40m high, the angle of elevation of ttriangle of side 2 cm.found to be 30° and 60° respectively. Find the height of the lighthouse.the top of the lighthouse from the foot of the tower.A solid is composodthe top of a lighthouse isAlso find the distance of5) |
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| 34. |
values of sil l, EUSThe shadow of a tower standing on a level ground is found to be 40m longer whenthe sun's altitude is 30 than when it is 60°. Find the height of the tower |
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| 35. |
The angle of elevation of the top Q ofa vertical tower PQ from point X on the ground is 60 degree.At apointY 40m vertically aboveXthe angle of elevation is 45degree.Find the height Of thetower PQand distance XQ. |
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| 36. |
4.Thesthadowofatowerstandingofalevelgroundisfoundtobe40m. longer when the sun's altitude is 30° than when it is 60.Find the height of the tower.4 |
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Answer» tnx |
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| 37. |
the strillgthe two kiles meet.ThePO from a point on the angle of elevation of the top Q of a vertical towere ground is 60° At a point Y 40mabove X the angle of elevation is 45 find the2.height of the tower PO and the distance xOthe elevation of its summit is |
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Answer» Answer: Step-by-step explanation: In triangle YRQ, tan 45 = QR/ YR This gives YR = x or XP = x [ As YR = XP ] ...... (1) Now, in triangle XPQ, tan 60 = PQ / PX V3 = x+40/x [Using(1)] This gives: x = 40 / V3 - 1 x = 20 (V3 + 1) = 54.64 m (By rationalisation) So, height of the tower, PQ = x + 40 = 54.64 + 40 = 94.64 m
In triangle XPQ, sin 60 = PQ / XQ V3/2 = 94.64/ XQ This gives XQ = 109.3 m |
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| 38. |
ole4,A pole 5 m high is fixed on the top of a tower. The angle of elevation oftneof the A' from4, A pole 5 m high is fixed on the top of a tower. The angle of elevationobserved from a point 'A' on the ground is 60° and the angle of depressionthe top of the tower is 45°. Find the height of the towerle of t |
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| 39. |
what is business ethics |
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Answer» Business ethics, connotes the form of applied ethics, which studies ethical principles, morals and problems that take place in the business environment. It is nothing but the integration of day to day morals and ethical norms to business and applies to all types of business |
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| 40. |
As observed from the top of a 100 m high light house from the sea-level, the angles ofdepression of two ships are 30° and 45°. If one ship is exactly behind the other on thesame side of the light house, find the distance between the two ships. [Use v3 1.732] |
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| 41. |
28.Two ships are sailing on opposite sides of a light house 150 m high and in the same line withthe foot of the light house. Find the distance between the ships when the angles of depres-sion of the ships are observed from the top of light house are 60°and 45° |
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Answer» AB= Height of lighthouse= 150mAt C and D there are two ships.Angle ADB = 45°therefore, tan45°=AB/BDAB=BDtherfore, BD=150mAngle ACB = 60°therefore, tan60°=AB/BC√3=150/BCBC = 150/√3BC = 50×√3= 86.6mTherfore distance between the ship isBC+BD=150+86.6=236.6m |
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| 42. |
The side of a triangle are of lengths 20, 21 and 29units. The sum of the lengths of altitude will be16091)units(2) 49 units160921units(4) 40 units |
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| 43. |
From a window 15 metres high above the ground in a street, the angles of elevation anddepression of the top and the foot of another house on the opposite side of the street are30° and 45o respectively, show that the height of the opposite house is 23.66 metres.(Take V3 = 1.732) |
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| 44. |
11. From the top and foot of a tower 40m high the angle of elevation of the top of a light house is found tobe 30 and 60 respectively. Find the height of the light house and also find the distance of the top ofthe light house from the foot of the tower |
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| 45. |
As observed from the top of 300 m high light house, the angle of depressionoftwo ships anchored in the opposite direction in the sea are found to havemeasures 45 and 60. Find the distance between two ships. |
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| 46. |
From a window 15 metres high above the ground in a street, the angles of elevation anddepression of the top and the foot of another house on the opposite side of the street arerespectively, show that the height of the opposite house is 23.66 metres.(Take ./3-: 1.732) |
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| 47. |
Percentage Concept |
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Answer» Basic Definition: Percent implies “for every hundred” and the sign % isreadas percentage and x % isreadas x per cent. In other words, a fraction with denominator 100 is called a per cent. For example, 20 %means20/100 (i.e. 20 parts from 100). |
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| 48. |
The floor of a building consist of 3000 tiles which are rhombus shaped and each of itsdiagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if thper sq m is 4 |
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Answer» Thank you |
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| 49. |
The floor of a building is made up of 3000 tiles. Each tile is in theshape of rhombus having diagonals 45 m and 20 m in length. If the cost ofpolishing the floor is 135 per sq. m. then find the cost of polishing the floor |
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| 50. |
.c ܩ ܐ ܘk_ܩPܗ ܗ |
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Answer» 30 is the correct answer 6 is correct answer of following question 12 is the correct ans 30 is correct answer. correct answer is= 12 12 is the correct answer 12 is the right answer of the following the correct answer is 12 |
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