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4ABC9,柯ACTI 껴-fa-S.xt1zjR XY||Abt, di red qm01く4In AA BC, X is middle point of AC. IFXYAB then prove that Y is middle point of AB. |
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Answer» In∆CAB,wehaveXY∥AB,thenCXXA=CYYB[BPT]........(1)now,XisthemidpointofCA,thenCX=XA.nowfrom(1),wehave,CXCX=CYYB⇒1=CYYB⇒CY=YB⇒YisthemidpointofBC |
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