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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
5. A sum of money triples itself in 8 years. Find the rate of interest. |
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| 2. |
424dxx2 +2x+1 |
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| 3. |
A person on tour has 4200 for his expenses. If he extends his tour for 3 days, hehas to cut down his daily expenses by 70. Find the original duration of the tour. |
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Answer» Let the original duration of stay be n.Let the daily expense be x.Then, xn = 4200=> x = (4200 / n)Also, ( x - 70 ) ( n + 3) = 4200=> nx - 70n + 3x -210 = 4200=> 4200 - 70n + 3x - 210 = 4200=> 70n - 3x + 210 = 0=> 70n - 3*(4200/n) + 210 = 0=> 70n^2 - 12600 + 210 n = 0=> n^2 - 180 + 3n = 0.=> n^2 + 3n - 180 = 0=> n^2 + 12n - 9n - 180 = 0=> n(n+12) - 9(n+12) = 0=> (n+12)(n-9) = 0=> n = 9.ORIGINAL DURATION OF STAY = 9 DAYS. PLEASE HIT THE LIKE BUTTON |
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| 4. |
A person on tour has Rs4200 for his espenses. If he extends his tour for 3 days he has to cut down his daily expenses by Rs70. Find the original duration of the tour. |
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Answer» Yee 10,800 kaha se aaya |
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| 5. |
a person on tour has 4200 Rs for his expenses. if extends it tour for 3 days he has to cut down his daily expenses by Rs. 70 .find the duration of the tour. |
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Answer» 20 days |
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| 6. |
A person on tour has Rs. 360 for his expenses. If he extends his tour for 4 days, he has to cutdown his daily expenses by Rs. 3. Find the Original duraiton of the tour. |
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| 7. |
21. A person on tour has Rs 4200 for his expenses. If he extends his tour for 3days, he has to cut down his expenses by Rs. 70. Find the original duration ofthe tour. |
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| 8. |
27. A person on tour has360 for his expenses. If he extends his tour for4 days, he has to cut down his daily expenses by R 3. Find the originalduration of the tour. |
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| 9. |
y doubles itself in 10 years. Find the rate of interest.4.7' |
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Answer» Let the principal be xTime = 10 yearsAmount after 10 years gets doubled So amount = 2x simple interest = amount - principalsimple interest = 2x - x = xRate per annum = SI × 100 / P × T= x × 100 / x × 10100x/ 10x = 10So rate per annum = 10%. Please hit a like if you find it useful |
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| 10. |
PAGE:DATE:IAG |
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| 11. |
23. A sum of money lent at simple interest amounts to4745 in 3 years and to54755 years. Find the sum and the rate per cent per annum. |
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Answer» thanks |
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| 12. |
su. A sum of money lent at simple interest amounts to 4745 in 3 years and to? 54755 years. Find the sum and the rate per cent per anuum |
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| 13. |
A sum of money doubles itself in 8 yearsFind the rate of interest. |
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| 14. |
How many terms of an AP 9, 17, 235 .. be taken so that their sum is 676? |
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| 15. |
Prove that the curves x =y2 and xy = k cut at right angles if 8k2-1 |
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| 16. |
1. Two circles of radii 5 cmand 3 cm intersect at two points and the distance betweencs is 4 cm、Find the length of the common chord.heir centre |
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| 17. |
ill and its height is 15 cm. Find the volumecylinder having the same base, find the ratio of their heights if heir volumes ateof the tonC.equal. |
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Answer» Volume of cone = Volume of cylinder => (1/3)π*r*r*h = π*r*r*H=> h/H = 3/1 |
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| 18. |
This part has questons 6. The ratio of incomes of two persons is 9:7 and the ratio of their expenditures is 4:3. Ifeich of them manages to save t200 per month, find heir monuh inc |
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| 19. |
x3-4x2-x+1=(x+2) |
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| 20. |
(x3 + 4x2 +x-6) รท (x + 3) |
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Answer» hit like if you find it useful |
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| 21. |
\lim _ { x \rightarrow \infty } \frac { 2 x ^ { 3 } - 5 x ^ { 2 } + x - 4 } { 3 x ^ { 3 } + 2 x ^ { 2 } - 5 x - 8 } |
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| 22. |
4 Four times a number x is 15 less than thrice the number y. Write it mathematically |
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| 23. |
O70 per anmiunsumof money doubles itself in 10 years. Find the rate of interest. |
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Answer» Let the principal be xTime = 10 yearsAmount after 10 years gets doubled So amount = 2x simple interest = amount - principalsimple interest = 2x - x = xRate per annum = SI × 100 / P × T= x × 100 / x × 10100x/ 10x = 10So rate per annum = 10%. Please hit a like if you find it useful |
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| 24. |
Solve the equation \frac{x^{2}+x-2}{2-x}=\frac{x^{2}-2 x+3}{2 x-3} |
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Answer» very thanks |
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| 25. |
percent.2.A sum of money doubles itself in 10 years at simple interest. What is therate of interest? |
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Answer» Let the principal be xTime = 10 yearsAmount after 10 years gets doubled So amount = 2x simple interest = amount - principalsimple interest = 2x - x = xRate per annum = SI × 100 / P × T= x × 100 / x × 10100x/ 10x = 10So rate per annum = 10%. |
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| 26. |
8. A sum of money doubles itself in 10 years. What is the rate of interest? |
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| 27. |
percent.12.A sum of money doubles itself in 10 years at simple interest. What is therate of interest? |
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Answer» Let the principal be xTime = 10 yearsAmount after 10 years gets doubled So amount = 2x simple interest = amount - principalsimple interest = 2x - x = xRate per annum = SI × 100 / P × T= x × 100 / x × 10100x/ 10x = 10So rate per annum = 10%. |
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| 28. |
what was the first invention of India |
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Answer» Prefabricated home and movable structure was the first invention at akbar rule. I don't agree.because our mathematician invented many things.like zero,distance of Sun from Earth. |
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| 29. |
cost of 1kg of fish is Rs.200. Find the cost of 750g fish |
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Answer» I want to know the answer 1kg=200 so 750g is 25percent of 1kg so 200- 25percent of 200 so and is 150 1kg=200 so 750g is 25percent of 1kg so 200- 25percent of 200 so and is 150 |
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| 30. |
. ~40k)x ~9 % UH Uदि |
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Answer» मूल को a तथा -a होने दोयोग = - (8k ^ 2-40k) / 4एक-एक = 0 = - (8k ^ 2-40k) / 48k ^ 2 = 40kk = 0,5 |
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| 31. |
If [(x+2) + (x+3)]2-[(x+2)-(x+3)]2 = 4x2 + 64, |
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| 32. |
x+2)4x2+3x+7( |
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| 33. |
sum of money doubles itself in 6 years. What is therate of interest? |
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Answer» Let sum of money be P,T = 6 years, R =? We know,SI = P*R*T/100 As per given conditionP = P*R*6/100R = 100/6 = 16.6 Therefore, Rate of Interest = 16.6 % |
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| 34. |
hential equations.im) (12)* = 28tions an interclass poster maki |
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| 35. |
a + b + c = 6 , a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = 14 \text { and } a ^ { 3 } + b ^ { 3 } + c ^ { 3 } = 36 |
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| 36. |
If a+b+c=14 \text { and } a^{2}+b^{2}+c^{2}=96then (ab + bc ca)? |
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Answer» (a+b+c)^2==a^2+b^2+c^2+2(ab+BC+ca)(ab+bc+ca)=0 |
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| 37. |
\begin{array} { c } { \text { Factyorise the following: } } \\ { 49 x ^ { 2 } + 14 x + 1 } \\ { \frac { a ^ { 2 } } { 4 b ^ { 2 } } + 1 + \frac { b ^ { 2 } } { a ^ { 2 } } } \\ { \text { ii) } x ^ { 2 } + 2 \sqrt { 5 x } + 5 } \end{array} |
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| 38. |
4000 2mind the values of m and n where m and n are non-negative integers.Hence wrexpansion without actual division241S.,find the values of m and n where m and n are non-negative= |
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| 39. |
Ifone zero ofp(x) = 4x2-(8ks_ 40k) x-9 is negative of the other, find valuesk. |
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Answer» Let the roots be a and -asum=-(8k^2-40k)/4a-a=0=-(8k^2-40k)/48k^2=40kk=0,5 |
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| 40. |
ofIf one zero ofp(x) 4r2-(8k-40k)x-9 is negative of the other, find valuesk. |
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| 41. |
Q 2: If one zero of p(x)-4x2-(8k2-40k)x-9 is negative of the other, find the values of k |
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Answer» Let a and b are zeroes of equation 4x^2 - (8k^2 - 40k)x - 9 Then,a = - b Sum of zeroes = (8k^2 - 40k)/4a + b = (8k^2 - 40k)/4-b + b = 2k^2 - 10k2k(k - 5) = 0k 0, 5 Therefore value of k = 0 and k = 5 |
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| 42. |
= oR e 4 न mat i |
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Answer» sinθ=√(3)/2-->θ=π/3 |
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| 43. |
Find a point on the parabola J (x-4) where the tangent is parallel tothe chord joining (4. 0) and (5, 1). |
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| 44. |
t a2 +b2 +c2-ab -be - ca is always non-negative for all values of a, b214. Prove thatand c. |
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| 45. |
Q 2: If one zero of p(x) = 4x2ăź(8k2-40k)x-9 is negative of the other, find the values on( |
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| 46. |
em 10.1 : The tangent at any point of a circle is perpendicular tothrough the point of contact.yy to the circleat |
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Answer» Tx |
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| 47. |
What is shifting cultivation |
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Answer» Shifting cultivation is a form of agriculture, used especially in tropical Africa, in which an area of ground is cleared of vegetation and cultivated for a few years and then abandoned for a new area until its fertility has been naturally restored. |
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| 48. |
2.Prove that the line joining the mid-points of two parallel chord of a circlepasses through the centre. |
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| 49. |
A circle passes through( 2,4) point and its radius is 2 units. Find the equation of the circle |
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Answer» (X-2)^2+(y-4)^2=4 formula is (x-a)^2+(y-b)^2=r^2 a -crixle passes through (2,4)poinr (x-2)^2 + (y-4)^2 = 2^2 The equation of circle X2+y2-4x8y+16=0 the eqn must be: x²+y²-4x-8y+16=0 |
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| 50. |
5. Prove that the perpendicular at the point ofcontact to the tangent to a circle passes throughthe centre |
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