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Q 2: If one zero of p(x)-4x2-(8k2-40k)x-9 is negative of the other, find the values of k |
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Answer» Let a and b are zeroes of equation 4x^2 - (8k^2 - 40k)x - 9 Then,a = - b Sum of zeroes = (8k^2 - 40k)/4a + b = (8k^2 - 40k)/4-b + b = 2k^2 - 10k2k(k - 5) = 0k 0, 5 Therefore value of k = 0 and k = 5 |
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