This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The angles of a quadrilateral are in A.P. whose common difference is 10°. Find bangles. |
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| 2. |
. The angles of a quadrilateral are in A.P. whose common difference is 10. Find the angles.ANSWERS |
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| 3. |
9. Find0) the lateral or curved surface area of a closed cylindrical petrol soragetank thatis4.2 m in diameter and 4.5 m high.(i) how much steel was açtually used, if 17- of the steel ctully used was wasted inmaking the tank. |
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| 4. |
find the circumference of the circle whos dimater 44 |
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Answer» Diameter is 44hencecircumference is πd=22/7*44=138.16units |
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| 5. |
The incentre of the triangle, whos l(-36, 7). (20, 7) and (0. 8) is |
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Answer» Given,vertices of the triangle are A (-36,7), B (20,7) and C (0,-8) a = BC = root (0-20)^2 + (-8-7)^2= root(-20)^2 + (-15)^2= root 400 + 625= root 525= 25. b = CA = root (36-0)^2 + (7-(-8))^2= root 1296 + 225= root 1521= 39. c = AB = root 20-(-36)^2 + (7-7)^2= root (20 + 36)^2 + 0= root 56^2= 56. a = 25, b=39,c=56. We now that incentre of the triangle is (ax1 + bx2 + cx3)/(a+b+c),(ay1 + by2 + cy3)/(a+b+c) ------------ (2) Subsitute values in (2), we get (25(-36)+39(20)+56(0)/(25+39+56),25(7)+39(7)+56(-8)/(25+39+56))= ((-120)/120,(448-448)/120)= (-1,0). Therefore the incentre is (-1,0). HIT THE LIKE BUTTON IF THIS HELPED YOU! |
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| 6. |
rawer contains 50 bolts and 150 nuts. Half of the bolts and half of the nuts arsrusted. If one item is chosen at random, what is the probability that it is a rusted oris a bolt. |
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| 7. |
weight of the Shien.4. A hemispherical bowl is made of steel 0.5 cm thick. The inside radius ofthe bowl is 4 cm. Find the volume of steel used in making the bowl |
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| 8. |
B. I. A rectangular field is 250 metres long and 75 metres wide. Find its arpermeter |
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| 9. |
A village has a population of 4000 It requires 150 t ofwater per head per-day. It has atank measuring 20 m by 15 m by 6 m. For how many days will the water of this tank last9. A cuboidal water tank is 6 m longmde andmd |
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| 10. |
a cuboidal water tank contains 216 litre of water its depth is one by third of its length and breadth is one by two of its one by third or difference between Length and depth find the length of tank |
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| 11. |
g sictenients are True or Faise) Book-keeping and accounting are one and the same thing |
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Answer» While bookkeeping and accounting are both essential business functions, there is an important distinction. Bookkeeping is responsible for the recording of financial transactions. Accounting is responsible for interpreting, classifying, analyzing, reporting and summarizing financial data. The biggest difference between accounting and bookkeeping is that accounting involves interpreting and analyzing data and bookkeeping does not The accounting process involves recording, interpreting, classifying, analyzing, reporting and summarizing financial data. Bookkeeping is the process of recording financial transactions. Recording financial transactions is the first part of and the foundation of the accounting process. Bookkeepers handle the recording part of the accounting process. Accountants handle all parts of the accounting process. Understanding Bookkeeping Bookkeepers record financial transactions in chronological order on a daily basis. Because accounting software automates many of the processes, some bookkeepers in small organizations also classify and summarize financial data in financial reports. These bookkeepers are often referred to as full-charge bookkeepers. They make higher salaries than bookkeepers but lower salaries than accountants. Understanding Accounting Accountants analyze financial transactions in financial statements and business reports following accounting principles, standards and requirements. Accountants analyze and interpret financial data to report the financial condition and performance of the business to company leaders to help them make informed business decisions. The Similarities Bookkeeping and accounting can appear to be the same profession to the untrained eye. Both bookkeepers and accountants work with financial data. To enter either profession, you must have basic accounting knowledge. Bookkeepers in smaller companies often handle more of the accounting process than simply recording transactions. They also classify and generate reports using the financial transactions. They may not have the education required to handle these tasks, but this is possible because most accounting software automates reports and memorizes transactions making transaction classification easier. Sometimes, an accountant records the financial transactions for a company, handling the bookkeeping portion of the accounting process. |
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| 12. |
3) A hemisphere bowl is made of steel 0.5cm thick. The inside radius of the bowlis 4cm. Find the volume of steel used in making the bowl. |
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| 13. |
3) A hemisphere bowl is made of steel 0.5cm thick. The inside radius of the bowlis 4cm. Find the volume of steel used in making the bowl |
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| 14. |
A field is 10 metres long and 8 metres wide.Find its area and perimeter |
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Answer» thankyou for answer send |
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| 15. |
What is the perimeter of a flower garden whose length is 5a metres, andwidth is 3b metres when a -4 and ba? |
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Answer» Given,Length of flower garden l = 5a mWidth of flower garden b = 3b m Then,Perimeter of flower garden= 2(l + b)= 2(5a + 3b) = 10a + 6b For a = 4, b = 1/2 aPerimeter = 10a + 6*a/2= 10a + 3a= 13a= 13*4= 52 m |
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| 16. |
3. The perimeter of a rectangular field is 120 metres. If its breadth is 27 metres. find its length. |
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Answer» Let the length and breadth of the rectangular field be l m and b m, respectively.According to the question, we have:2(l+b)=120 ...(i) ⇒l+b=60Given that b=27m ...(ii)Using (ii) in (i), we have:l+27=60⇒l=60-27⇒l=33m∴ length of rectangle is 33 m |
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| 17. |
Who invited computer |
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Answer» Charles Babbage invented computer. |
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| 18. |
7. In fig., the shape of the top of a table in restaurant is thatof a sector of a circle with centre O and ZBOD 90°, ifBO- OD 60 cm find:(0 the area of the top of the table(ii) the perimeter of the table top. [Take Ď = 3.141Foreign 2009) |
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| 19. |
10. ) The length of a rectangle shaped park exceeds its breadth by 17 metres if theperimeter of the park is 178 metres, find the dimensions of the park. |
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| 20. |
1. With a sharp tip of the pencil, mark four points on a paper and name themby the letters A.C.P.H. Try to name these points in different ways. One suchway could be this |
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Answer» acph ,apch ,aphc , ahcp ,ahcp, achp, hcap, hapc, ahpc, caph , apha, chap, cpah , |
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| 21. |
की HCF > 15 तथा L.CM = 178| बरेढ़ी 21, 28, 31, ....लि समीकरण 4. न पहन 3 न |
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Answer» No ,2 numbers cannot have HCF as 15 and LCM as 175 .Because LCM>HCF and HCF of 2 numbers should divide the LCM completely.Here , the 1st criteria is fulfilled but the 2nd criteria is not.Since 175/15=35/3= 11 2/3∉ N.175 is not completely divisible by 15.Hence 2 numbers cannot have HCF as 15 and LCM as 175 |
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| 22. |
separate 178 into 2 parts so that the first part is 8 less than twice the second part |
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Answer» Let the second part be 'x'Then the first part is 2x-8By the problem,x+2x-8=1783x-8=1783x=178+8=186x=186/3 = 62So the first part is 2x-8 = 2(62)-8 = 124-8=116Second part is x = 62 |
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| 23. |
कि जप:VE=18- ¥ (450 mous) ) pim) 1o |r " |
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| 24. |
EXERCISE 5.41. Find the LCM of the following by Prime Factorization method:(a)216, 314 and 520(b) 175, 178 and 350(c)128,54 and 100 |
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| 25. |
6: The length of a rectangle shaped park exceeds its breadth by 17 meters. If theperimeter of the park is 178 meters find the dimensions of the park? |
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Answer» Let the breadth be xtherefore length of the rectangular park will be x+17given2(x+x+17)=1782(2x+17)=1782x+17=892x=72x=36mthe length =53m |
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| 26. |
how many chord can be formed by 12 points |
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Answer» 12c2 = 12!/2!*(12-2)! = 12*11*10!/2*10! = 66 chords Are you Sure About it |
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| 27. |
A table cover of dimensions 3 m 25 cm x 2 m 30 cm is spread on a table. If 30 cm of the table cover ishanging all around the table, find the area of the table cover which is hanging outside the top ottable. Also, find the cost of polishing the table top at 16 per square metre.13.thelr oath is 44 m, |
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Answer» Area of hanging tablecloth = {3.25*2.30} - {(3.25-0.60)*(2.30-0.60)}= 7.4750 - 4.5050= 1.97sqr metrecost of polishing table top = 4.5050*16=RS72.8 |
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| 28. |
separate 178 into two parts so that the first part is less than twice the second part |
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Answer» suppose second part is 2xthen first part will be2x-2then2x+2x-2= 1784x= 180x= 180/4x= 45then those part will be2*45 =90 and 88 |
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| 29. |
SalalySeparate 178 into two parts so that the firstpart is 8 less than twice the second part. |
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Answer» Let one part be x.Then the other part is (178 - x). (178 - x) = 2x - 8 178 + 8 = 2x + x 3x = 186 x = 62 178 - x = 178 - 62 = 116Therefore, the two parts are 62 and 116. |
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| 30. |
ics2. Solve:(a) 10+1o18 18 |
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Answer» 1/18 + 1/18 = 2/18 = 1/9 |
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| 31. |
\operatorname{Li} \frac{x-a}{x \rightarrow a^{\frac{3}{2}}-a^{\frac{3}{2}}} |
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Answer» by putting x=a we will get 0/0 form so using L'hospital rulelim x->a 1/(3/2)x^(1/2)=2/3root(a) |
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| 32. |
E 12 Points A(-1,y and B(5,7) lie on a circle with centre O(2, -3y).Find the values of y. Hence, find the radius of the circle. [CBSE 2014] |
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| 33. |
lou 2010 (D.D.12. Find that non-zero value of k, for which the quadratic equation kot + 1-2 (k-1+ x = 0 has equal roots. Hence, find the roots of the equation.ICBSE 2015 (D.B |
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Answer» Question incomplete plz resend |
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| 34. |
Mathematics Xi.e.,-4=0which is a false statementTherefore, the equations do not have a common solutieach otherEXERCISE 32_I. Solve the following pair of linear equations by the(i)'r + y #14 |
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Answer» Adding the two equations ,2x=18x=9 Substitute x =9 in equation 1,9+y=14 y=5 |
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| 35. |
SR ABID is a poderellaogram. Find theо «Она с.0 и 43Proho |
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Answer» here 180°-50°= 130°so y=130° and 130 the answer is correct y+50=180 then Y=130 x=y=130 & z=50 |
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| 36. |
0|ho=htetS= b-0 |
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Answer» x= y+5now putting the value in 2 nd equation2y+10+4y= 246y= 14y= 14/6x= 5+(14/6)= 44/6thanks |
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| 37. |
no a quadratic polynomial whose sensand product or se perces are 2 and8rospectualy -4-47%zxtiles21 II |
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Answer» Let a and b are zeroes of polynomial Then,a + b = 21/8a*b = 5/16 Therefore, Quadratic polynomial :x^2 - (a + b)x + ab = 0x^2 - 21/8x + 5/16 = 016x^2 - 42x + 5 = 0 X2-47/16x+105/128 |
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| 38. |
zerosisv2andFind the quadratic polynomial, the sum of whosetheir product is -12 Hence find the zeros of the polynomial |
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| 39. |
Mathematics X24-2)+4y -1208-12=0i.e.i.ewhich is a false statementTherefore, the equations do not have a common solution. Soeach otherEXERCISE 3I. VSolve the following pair of linear equations by the sul(i)x+y= 14n) |
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Answer» Adding the two equations ,2x=18x=9 Substitute x =9 in equation 1,9+y=14 y=5 |
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| 40. |
( 5 p ^ { 2 } - 25 p + 20 ) \div ( p - 1 ) |
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| 41. |
In the figure, AD and BC are equal perpendicularsto line segment AB. Prove CD bisects AB.(2 marks)roof: |
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Answer» in ∆AOD and ∆BOCA = B (90°)DOA = BOC ( vertically opposite angle)AD = BC (given)by AAS rule, ∆AOD and ∆BOC are congurent soby CPCT AO = OB |
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| 42. |
som andareIrind the quadretic polynomial whoseproduct of its reros respectively3 and 8 |
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| 43. |
Of the roots of the equation (e -ab) 12 -20of the equation (a)22(abe)x+ (b -ac)ho))0 are real and equal, show thatare real and equal, show that |
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| 44. |
H THE COLUIVIIColumn AThe thickness of one book is 3.85 cm and that of other bis 2.63 cm . The thickness of the two books when placedone on top of the other is .................cm.15 ond 12.36 from sum of 25.2 |
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Answer» Thickness = 3.85 + 2.63 = 6.48 cm |
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| 45. |
b)2 cards are being drawn one by one from ack of 52 playing cards. Find out the prob-ability of one card being drawn is ace and sec-ond an honour card. First card is not put backin stack before withdrawing second card. |
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Answer» Note:-The Ace, King, Queen and Jack of each suit are called HONOR CARDS. |
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| 46. |
ax + by = c and mx + ny = d and an is not equal to bm then these simultaneous equations have 1. Only one common solution 2. No solution 3. Infinite number of solution 4. Only two solutions |
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Answer» If you like the solution, Please give it a 👍 |
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| 47. |
\begin{array} { c } { \text { If } 7 \csc \phi - 3 \cot \phi = 7 , \text { prove that } } \\ { 7 \cot \phi - 3 \csc \phi = 3 } \end{array} |
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| 48. |
Find the positive root of V3x2 + 6 = 9. |
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| 49. |
12 Write the positive root of a quadretic equation ac+bx+c=0 |
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Answer» To say that the roots ofax2+bx+c=0are imaginary is to say that the graph of: f(x)=ax2+bx+c does not intersect thexaxis for any real value ofx. Since this is described as a quadratic, we must havea≠0. So the whole of the parabo, one side of thexaxis or the other. When we multiply bya≠0, gettinga2x2+abx+acwhose graph is simply a scaled version of the original, the coefficient ofx2isa2>0. Hence we know that for large values ofxthe quadratic function will be positive. Hence it is positive for all values ofx. |
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| 50. |
\int \frac{(3 \sin \phi-2) \cos \phi}{5-\cos ^{2} \phi-4 \sin \phi} d \phi |
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Answer» 1 2 |
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